c++ empty copy assignment operator copies data - c++

Question

I am sort of new to c++ and wanted to write a small matrix library which has a base class Matrix from which some new matrix types like SparseMatrix, DenseMatrix, HashMatrix etc.
My base class looks like this:
class Matrix {
protected:
int m,n;
public:
Matrix(int m_p, int n_p) : m(m_p), n(n_p){
std::cout << "gen constr" << std::endl;
}
Matrix(Matrix& other) = delete;
Matrix() = delete;
virtual ~Matrix() {}
int getM() const {
return m;
}
int getN() const {
return n;
}
virtual double& get(int m, int n) = 0;
virtual double get(int m, int n) const = 0;
inline double& operator() (int m, int n){
return get(m,n);
}
inline double operator() (int m, int n) const{
return get(m,n);
}
friend std::ostream &operator<<(std::ostream &os, Matrix &matrix) {
using std::scientific;
using std::fixed;
os << std::fixed << std::setprecision(2) << scientific << std::setfill(' ');
for(int i = 1; i <= matrix.getM(); i++){
for(int j = 1; j <= matrix.getN(); j++){
os << std::setw(10) << matrix.get(i,j) << " ";
}
os << "\n";
}
return os;
}
Matrix& operator=(const Matrix& other) {
// std::cout << "equality assign" << std::endl;
return *this;
}
};
As you can see, I have overwritten the equality assign operator which simply returns the object and does not actually copy values.
My first implementation of DenseMatrix is very straight forward:
class DenseMatrix : public Matrix{
private:
double* data;
public:
DenseMatrix(int mP, int nP) : Matrix(mP, nP){
std::cout << "gen constr base" << std::endl;
this->data = new double[mP * nP]{0};
}
DenseMatrix() = delete;
~DenseMatrix() {
delete this->data ;
}
double &get(int m, int n) {
int index = m*getN()+n-(getN()+1);
assert(index < (getN() * getM()) && index >= 0);
return this->data [index];
}
double get(int m, int n)const {
int index = m*getN()+n-(getN()+1);
assert(index < (getN() * getM()) && index >= 0);
return this->data [index];
}
};
Furthermore the main() function looks like this:
DenseMatrix mat(3,3);
for(int i = 1; i<= 3; i++){
mat(i,i) = i;
}
DenseMatrix mat2(3,3);
mat2 = mat;
std::cout << mat << std::endl;
std::cout << mat2 << std::endl;
>>> 1.00e+00 0.00e+00 0.00e+00
>>> 0.00e+00 2.00e+00 0.00e+00
>>> 0.00e+00 0.00e+00 3.00e+00
>>> 1.00e+00 0.00e+00 0.00e+00
>>> 0.00e+00 2.00e+00 0.00e+00
>>> 0.00e+00 0.00e+00 3.00e+00
As you can see, I create two matrices first. I adjust the values for the first matrix and leave the values of the second matrix default to 0. Yet after calling the equality assign operator, the content of the second matrix changes even tho the function I implemented has basically no code which affects the matrix.
I do not understand this behavior and would be very happy if someone could briefly explain what is going on here.
Thank you very much for your patience and help :)

Answer 1

You have not deleted or defined the operator= copy-assignment operator for DenseMatrix, so the compiler will synthesize one for you. This function is going to do a member wise copy of the data members, in this case double *data. Since the pointer is going to point to the same contents in both mat and mat2, you see the same contents when you print them out.
Note that this is probably not what you want. One issue is that your DenseMatrix destructor is going to delete data twice, leading to possibly a segfault.

Answer 2

You didn't define assignment operator for DenseMatrix.
The implicitly generated assignment operator assigns the sub objects. The base sub object will be assigned using the overloaded assignment operator of Matrix and therefore the dimensions stored within the base are not modified - but you had specified the dimensions to be the same, so they would have been assigned with the same values anyway.