Class variable not declared in this scope error c++ - c++

Question

I'm having problem with the function DisplayValues() in this program. First, I'm asked to write the prototype only for the function inside the class. Second requirement is to place the entire function DisplayValues() outside the class. DisplayValues() is a const inline member function.
All the above needs to be in a header file. I've written below and got errors "'accountType' not declared in this scope" for the DisplayValues() function. I did search for solutions but none worked without modifying the requirements above. Would anyone please advise?
My codes:
File SavingsAccount.h
ifndef SAVINGSACCOUNT_H
#define SAVINGSACCOUNT_H
class SavingsAccount
{
private:
int accountType;
public:
inline void DisplayValues() const;
};
inline void DisplayValues()
{
cout << "Account type: " << accountType << '\n'
}
#endif //SAVINGSACCOUNT_H
File SavingsAccount.cpp
#include <iostream>
#include "SavingsAccount.h"
using namespace std;
void SavingsAccount::GetInitialValues()
{
cout << "Enter account type:\n";
cin >> accountType;
}
File main.cpp
#include <iostream>
#include "SavingsAccount.h"
using namespace std;
int main()
{
SavingsAccount ac;
ac.GetInitialValues();
ac.DisplayValues();
return 0;
}

Answer 1

Your code has 3 obvious problems that I can see:
This is a free function, not a class member function.
inline void DisplayValues()
{
cout << "Account type: " << accountType << '\n'
}
Fix:
inline void SavingsAccount::DisplayValues()
{
cout << "Account type: " << accountType << '\n'
}
Your declaration is inline void DisplayValues() const; but definition is missing the const keyword.
inline void SavingsAccount::DisplayValues()
^^^^^ const missing here
You are missing a semicolon is this line:
cout << "Account type: " << accountType << '\n'
^^ semicolon missing here