I'm new to django and using crispy-forms to render the form.How do i add placeholder text to a field e.g "please enter your address"
In my views.py
class PostCreateView(LoginRequiredMixin, CreateView):
model = Post
fields = ['name', 'address']
In models.py
class Post(models.Model):
name = models.CharField(max_length=100, blank="true")
address = models.CharField(max_length=100, blank="true")
Every input field is Given an id by django; get the ids from inspect -- In the Html file and add a script tag some where and
Then use this JS code
document.getElementbyId('id of the field').setAtribute('placeholder','Your PH')
Btw use google for spelling errors and soory for them
Related
I want to not to display the null value fields in template.So How can i achieve this in django?Is there any functions available to do this.
In you used Django ModeForm then do this
class ProductForm(forms.ModelForm):
class Meta:
model = ProductModel
exclude = ('selling_price','discounted_price') # this is exclude fields not render in html template
NOTE:- pass null=True, blank=True in Model
If what you are saying is that you do not want a field that has been set to null = True in your models.py to be rendered in your html template, you can use django inbulit form class to render the form and exclude whatever field is null
Here is an example of what i am saying.
class Userdetail(forms.ModelForm):
class Meta:
model = User_detail
exclude = ("name_of_null_field",) #This field won't be rendered in your html template because it is excluded.
You can read more on Django forms here Working with forms
I hope the title of this question is as it should be based on this explanation below.
I have a model as below:
class Setting(models.Model):
TYPE_CHOICES = (
('CONFIG', 'Config'),
('PREFS', 'Prefs'),
)
attribute = models.CharField(max_length=100, unique=True)
value = models.CharField(max_length=200)
description = models.CharField(max_length=300)
type = models.CharField(max_length=30, choices=TYPE_CHOICES)
is_active = models.BooleanField(_('Active'), default=True)
I use this to save settings. I have don't know all settings in advance and they can change in future. So I decided to save attributes and their values in this model instead of creating columns for each setting(attribute in the model).
Now the problem I am facing is how do I present form with all attributes as fields so that a user can fill in appropriate values.
Right now, as you can see, form shows columns 'Attribute' and "Value" as labels. I would like it to show value of column 'Attribute' as label and column 'Value' as field input.
For example, in Setting model I have this:
Attribute ------------ Value
'Accept Cash' ---------- 'No'
I would like to appear this on form as
<Label>: <Input>
'Accept Cash': 'No'
I think I will have to build form fields from the database(Setting model). I am new to this and have no idea how to begin with it any example or link to tutorial that would help me get started will be much appreciated.
Thank you
you can define a model form based on your Settings model. Check the django documentation on Django Model Forms. The basic definition of the model form should be something like this
Define a forms.py file in your current django app and put the following code in it.
from django import forms
from .models import Settings
class SettingsForm(forms.ModelForm):
class Meta:
model = Settings
fields = ['the fields you want to add'] # or use '__all__' without the parentheses for all fields
Then in your views.py file navigate to the function which renders the page containing the form and add this to it
from .forms import SettingsForm
def your_function(request):
....
context = {
....
'form':SettingsForm()
}
return render(request, 'template_name.html', context)
Now in your template add the form using
........
{{ form }}
.......
I have a model Teacher which has following data:
class Teacher(models.Model):
name = models.CharField(max_length=100)
thumbnail = models.ForeignKey(Thumbnail)
class Thumbnail(models.Model):
thumbnail = models.FileField(upload_to=upload_to)
class TeacherAdmin(admin.ModelAdmin):
list_display = ('name',)
Here I want to relate all the thumbnail in my project to Thumbnail field. In my admin it shows me a dropdown of thumbnail while I want to add the thumbnail from admin.
Is it possible that I can upload from admin too?
Also what can I do in the case like :
class Teacher(models.Model):
name = models.CharField(max_length=100)
thumbnail = models.ManyToManyField(Thumbnail)
If I want to add multiple Images.
The only issue I am having is on admin side. Client side can be handles from regular forms.
Need suggestions and Ideas
The following shows up instead of a field in my template.
<django.contrib.localflavor.us.forms.USStateSelect object at 0x92b136c>
my template has
{{ form.state }}
what could the issue be?
class RegistrationForm(forms.Form):
first_name = forms.CharField(max_length=20)
last_name = forms.CharField(max_length=20)
phone = USPhoneNumberField()
address1 = forms.CharField(max_length=45)
address2 = forms.CharField(max_length=45)
city = forms.CharField(max_length=50)
state = USStateSelect()
zip = USZipCodeField()
also is there anyway i can make the state and zip optional?
To limit the choices to a drop down list, use us.us_states.STATE_CHOICES in your model, and use us.forms.USStateField() instead of us.forms.USStateSelect() in your forms.
To make a field optional in a form, add blank = True to that field in the model.
from django.contrib.localflavor.us.us_states import STATE_CHOICES
from django.contrib.localflavor.us.models import USStateField
class ExampleLocation(models.Model):
address1 = models.CharField(max_length=45) #this is not optional in a form
address2 = models.CharField(max_length=45, blank = True) #this is made optional
state = USStateField(choices = STATE_CHOICES)
Instead of STATE_CHOICES, there are several options you can find in the localflavor documentation. STATE_CHOICES is the most inclusive, but that may not be what you desire. If you just want 50 states, plus DC, use US_STATES.
This answer assumes you're using ModelForms. If you aren't, you should be. Once you've made your model, you should follow DRY and create basic forms like so:
from django.forms import ModelForm
class ExampleForm(ModelForm):
class Meta:
model = ExampleLocation
And it inherits your fields from your model. You can customize what fields are available, if you don't want the whole model, with other class Meta options like fields or exclude. Model forms are just as customizable as any other form, they just start with the assumption of your model's fields.
In my django admin I have a database column with different urls in each row. These urls are displayed as simple texts and not as link. How can I make them links so that they redirect the user to the url when they click on it.
Set allow_tags on the method on the model to true:
class Person(models.Model):
first_name = models.CharField(max_length=50)
last_name = models.CharField(max_length=50)
color_code = models.CharField(max_length=6)
def colored_name(self):
return '<span style="color: #%s;">%s %s</span>' % (self.color_code, self.first_name, self.last_name)
colored_name.allow_tags = True
from the django documentation.
If you have access to your templates:
If the contents of the field are something like:
http://www.google.com
You could output this in your template to make them clickable:
{{ field }}
If not:
I think this Stacko question is similar: How to add clickable links to a field in Django admin?