Printing floats with setw and setprecision - output doesn't line up - c++

Question

I'm trying to print matrix in C++ using std::cout, but I have no idea how to do this correct.
I tried such variants as setw() and setprecision(), but still not achived desired appearance(You can see it on the bottom of this question).
Matrix.cpp
template<class T>
class Matrix
{
public:
...
void print(int precision=5);
...
private:
size_t rows;
size_t cols;
std::vector<T> data;
};
template<class T>
void Matrix<T>::print(int precision)
{
for (int i = 0; i < (int)this->rows; i++) {
for (int j = 0; j < (int)this->cols; j++) {
//cout << ... << " ";
}
cout << endl;
}
cout << endl;
}
Main.cpp
...
int main()
{
...
matrix.print(4);
...
}
Some attempts:
cout << data.at(i*cols + j) << " ";
Output:
-21.4269 -11.9088 -14.8804 -11.1715 3.77597
16.1763 10.68 7.99879 -0.849034 -11.9758
15.7518 -19.1033 6.27838 -3.86534 21.4716
cout << fixed << data.at(i*cols + j) << " ";
Output:
-21.426937 -11.908819 -14.880438 -11.171500 3.775967
16.176332 10.679954 7.998794 -0.849034 -11.975848
15.751815 -19.103265 6.278383 -3.865339 21.471623
Here I'm trying to use setprecision()
cout << setprecision(precision) << data.at(i*cols + j) << " ";
Output:
-21.43 -11.91 -14.88 -11.17 3.776
16.18 10.68 7.999 -0.849 -11.98
15.75 -19.1 6.278 -3.865 21.47
cout << setprecision(precision) << fixed << data.at(i*cols + j) << " ";
Output:
-21.4269 -11.9088 -14.8804 -11.1715 3.7760
16.1763 10.6800 7.9988 -0.8490 -11.9758
15.7518 -19.1033 6.2784 -3.8653 21.4716
And here I'm using setw()
cout << setw(precision) << data.at(i*cols + j) << " ";
Output:
-21.4269 -11.9088 -14.8804 -11.1715 3.77597
16.1763 10.68 7.99879 -0.849034 -11.9758
15.7518 -19.1033 6.27838 -3.86534 21.4716
cout << setw(precision) << fixed << data.at(i*cols + j) << " ";
Output:
-21.426937 -11.908819 -14.880438 -11.171500 3.775967
16.176332 10.679954 7.998794 -0.849034 -11.975848
15.751815 -19.103265 6.278383 -3.865339 21.471623
And what I really need:
-21.42 -11.91 -14.88 -11.17 3.7760
16.176 10.680 7.9988 -0.849 -11.98
15.752 -19.10 6.2784 -3.865 21.472

Answer 1

It turns that I just need to call function with bigger argument:
cout << setw(10) << fixed << data.at(i*cols + j) << " ";
Output:
-21.426937 -11.908819 -14.880438 -11.171500 3.775967
16.176332 10.679954 7.998794 -0.849034 -11.975848
15.751815 -19.103265 6.278383 -3.865339 21.471623
And yes, answer under link that provided #Andy is even better because it more customizable.