I want to use regex validation formula on Text Field. Here is pure regex:
^(?!(?:\D*\d){7})\d+(\.\d{1,2})?$
When I test this expression in regex online tools (eg: https://regex101.com/) everything works fine.
But when I try to use this as validator in Orbeon like this:
matches(string(.), '^(?!(?:\D*\d){7})\d+(\.\d{1,2})?$') or xxf:is-blank(string(.))
I get error 'Incorrect XPath expression'.
When I removed from regex lookahead part, I was able to use it.
matches(string(.), '^\d+(\.\d{1,2})?$') or xxf:is-blank(string(.))
Is Orbeon Forms supports regex lookahead?
Regex lookahead:
https://www.regular-expressions.info/lookaround.html
Re-write the expression without lookahead. It matches strings with no more than 6 digits.
Use
^(\d{1,4}(\.\d{1,2})?|\d{5}(\.\d)?|\d{6})$
See proof
EXPLANATION
NODE EXPLANATION
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
( group and capture to \1:
--------------------------------------------------------------------------------
\d{1,4} digits (0-9) (between 1 and 4 times
(matching the most amount possible))
--------------------------------------------------------------------------------
( group and capture to \2 (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\. '.'
--------------------------------------------------------------------------------
\d{1,2} digits (0-9) (between 1 and 2 times
(matching the most amount possible))
--------------------------------------------------------------------------------
)? end of \2 (NOTE: because you are using a
quantifier on this capture, only the
LAST repetition of the captured pattern
will be stored in \2)
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
\d{5} digits (0-9) (5 times)
--------------------------------------------------------------------------------
( group and capture to \3 (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\. '.'
--------------------------------------------------------------------------------
\d digits (0-9)
--------------------------------------------------------------------------------
)? end of \3 (NOTE: because you are using a
quantifier on this capture, only the
LAST repetition of the captured pattern
will be stored in \3)
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
\d{6} digits (0-9) (6 times)
--------------------------------------------------------------------------------
) end of \1
--------------------------------------------------------------------------------
$ before an optional \n, and the end of the
string
Related
I have a URL that contains multiple sequences of numbers I want to capture them all in groups suppose I have the following
https://www.example.com//first/part/54323?key=value
or
https://www.example.com/first/12345/second/part/part2/5432?key=value
I tried to use something like that but it only matches one sequence of numbers
(.*\/)([0-9]{4,})(\/.*|$|)
I want to have multiple groups represent different sections if numbers sequence is included
1st group will be "example.com/first"
2nd group "12345"
3rd group "second/part"
4th group "5432"
5th group "?key=value"
The initial .* is Greedy, meaning it tries to match as much as possible. It matched everything up to the last slash "https://www.example.com/first/12345/second/part". You can modify this behavior by replacing the initial .* with .*?, but that will stop after the first slash, which is also not what you want "https:/" because there are no digits after those slashes.
But really we need to back up and ask some questions about your pattern. Apparently, you have a preamble you are not interested in, an indefinite number of sequences of 'character string, followed by slash, followed by number string' and then there is the "everything after there are no more slash digit patterns".
The key question is whether the number of char/char/digits combos are indefinite or limited to a definite number like the two pairs in your example. To get the regex parser to return an unbounded number of string-number pairs, you are going to want to turn on the /g (Global) switch so regex will return all matches. That is a problem with the part of your URL at the beginning and end which does not fit your pattern.
I recommend first using a regular expression to divide your URL into three parts, preamble, path, remaining data. Then you can pass the path string to a second regular expression to parse the pairs - it will be much simpler.
If you do it that way your first expression could be:
^[a-z+.-]+?:\/\/(:www\.)?([^?#]+?)(.*)$
The first part skips over everything through the optional www. and does not capture it because you are not interested in that part. The second part captures everything up to any query or fragment (delimited by ? and #, respectively) and places it in the first capture group. The last part captures the rest of the URL into the the second capture group. In your example that is ?key=value.
Now take your first capture group, which contains the host and the path, and pass it to a second regex with the global flag set (so it processes all pairs repeatedly). This second regex will be:
(.*?)\/([0-9]{4,})\/?
For each match of this string, the parsed values and numbers will be in capture groups 1 & 2.
It sounds very straight-forward:
https?:\/\/(?:www\.)?(.*?)\/(\d+)\/(.*?)\/(\d+)(?:\?(.*))?
See regex proof.
EXPLANATION
--------------------------------------------------------------------------------
http 'http'
--------------------------------------------------------------------------------
s? 's' (optional (matching the most amount
possible))
--------------------------------------------------------------------------------
: ':'
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
www 'www'
--------------------------------------------------------------------------------
\. '.'
--------------------------------------------------------------------------------
)? end of grouping
--------------------------------------------------------------------------------
( group and capture to \1:
--------------------------------------------------------------------------------
.*? any character except \n (0 or more times
(matching the least amount possible))
--------------------------------------------------------------------------------
) end of \1
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
( group and capture to \2:
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
) end of \2
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
( group and capture to \3:
--------------------------------------------------------------------------------
.*? any character except \n (0 or more times
(matching the least amount possible))
--------------------------------------------------------------------------------
) end of \3
--------------------------------------------------------------------------------
\/ '/'
--------------------------------------------------------------------------------
( group and capture to \4:
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
) end of \4
--------------------------------------------------------------------------------
(?: group, but do not capture (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\? '?'
--------------------------------------------------------------------------------
( group and capture to \5:
--------------------------------------------------------------------------------
.* any character except \n (0 or more
times (matching the most amount
possible))
--------------------------------------------------------------------------------
) end of \5
--------------------------------------------------------------------------------
)? end of grouping
I would like to match a specific pattern with regex but I am running into catastrophic backtracking. I wonder if there's a way it would be possible to match what I would like and not get an error.
I start with a simple assumption; I want my string to contain only one specific number e.g. 7 and only that specific number:
^\D*7\D*$
Only if I find this pattern do I want to look for another word in the same text such as "Coffee"; I put my condition into a group (^\D*7\D*$) and reference the group in my conditional and the then part will contain "Coffee":
(?(1)Coffee|)
Is there another phrasing that would avoid the the catastrophic backtracking?
You can use a negative lookahead to assert that the word Coffee is at the right.
^(?=.*\bCoffee\b)\D*7\D*$
The pattern matches:
^ Start of string
(?= Positive lookahead, assert that on the right is
.*\bCoffee\b Match Coffee between word boundaries \b to prevent a partial match
) Close lookahead
\D*7\D* Match number 7 between optional non digit characters.
$ End of string
Regex demo
Note that \D also matches a newline. If you don't want to cross newline boundaries, you can use [^\r\n\d] instead.
Left to right checking is more traditional:
^(?=.*Coffee)[^\d7]*7\D*$
See regex proof.
EXPLANATION
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
(?= look ahead to see if there is:
--------------------------------------------------------------------------------
.* any character except \n (0 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
Coffee 'Coffee'
--------------------------------------------------------------------------------
) end of look-ahead
--------------------------------------------------------------------------------
[^\d7]* any character except: digits (0-9), '7' (0
or more times (matching the most amount possible))
--------------------------------------------------------------------------------
7 '7'
--------------------------------------------------------------------------------
\D* non-digits (all but 0-9) (0 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
$ before an optional \n, and the end of the string
Right to left checking is only possible with engines like latest JavaScript, .NET or PyPi regex in Python:
^[^\d7]*7\D*$(?<=Coffee.*)
See proof.
EXPLANATION
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
[^\d7]* any character except: digits (0-9), '7' (0
or more times (matching the most amount
possible))
--------------------------------------------------------------------------------
7 '7'
--------------------------------------------------------------------------------
\D* non-digits (all but 0-9) (0 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
$ before an optional \n, and the end of the
string
--------------------------------------------------------------------------------
(?<= look behind to see if there is:
--------------------------------------------------------------------------------
Coffee 'Coffee'
--------------------------------------------------------------------------------
.* any character except \n (0 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
) end of look-behind
I have some strings in Oracle where there is a minus sign (not at the beginning but inside the string), followed by a number (int or decimal with dot or comma).
I would like to find these in PLSQL. I have this already, and it's almost perfect:
REGEXP_LIKE(string, '-\d+(,|\.)*\d*')
I was hoping that it's finding strictly strings like somestring-11,1 but the problem is, it finds also strings like somestring-11a1,1 so where there is eventually a non numeric (or word) character between the minus and the numbers. I was trying to use negative lookahead, but unfortunately it's not working:
REGEXP_LIKE(string, '-\d+!(\w)(,|\.)*\d*')
because somestring-1s won't be found either anymore. Could you please point me to the right direction? Thank you.
Could you please try following, written and tested based on your shown samples. Simple explanation would be: using lazy match to match till - then match digits(1 or more occurrences) followed by , and followed by 1 or more occurrences of digits.
.*?-\d+,\d+
Online regex demo for above regex
Use
(^|\D)-(\d+([,.]*\d+)?)($|\W)
See proof.
EXPLANATION
--------------------------------------------------------------------------------
( group and capture to \1:
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
\D non-digits (all but 0-9)
--------------------------------------------------------------------------------
) end of \1
--------------------------------------------------------------------------------
- '-'
--------------------------------------------------------------------------------
( group and capture to \2:
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
( group and capture to \3 (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
[,.]* any character of: ',', '.' (0 or more
times (matching the most amount
possible))
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times
(matching the most amount possible))
--------------------------------------------------------------------------------
)? end of \3 (NOTE: because you are using a
quantifier on this capture, only the
LAST repetition of the captured pattern
will be stored in \3)
--------------------------------------------------------------------------------
) end of \2
--------------------------------------------------------------------------------
( group and capture to \4:
--------------------------------------------------------------------------------
$ before an optional \n, and the end of
the string
--------------------------------------------------------------------------------
| OR
--------------------------------------------------------------------------------
\W non-word characters (all but a-z, A-Z, 0-
9, _)
--------------------------------------------------------------------------------
) end of \4
My current regex:
(\d.{17})[^#]*(\D+)(\d+)gr(\d+)
In group 2, they are still having the hashtag, I want to remove it from there. What should I change from my current regex?
201223E0MWJPJD2230#AdeSaputra290gr99000
2101023CNV6TT1109J#Fefe430gr142000
2101183EDTFPSA0128#Jessica500gr112000
201221E2QKWRY11413#EssyYosita880gr233500
2101123G9XQ7R41705#Meily1120gr329000
201228ECEWTJT50859#WidyaNatali1720gr457230
201227EEBX1K9K1020#Excelio112gr58900
2101112N4YNFB12016#DebyNath520gr156220
2101072R8A0QB22347#AlycieHandoTan700gr85000
Output:
group 1: 201223E0MWJPJD2230
group 2: #AdeSaputra
group 3: 290
group 4: 99000
remove [^] from your regex
(\d.{17})#*(\D+)(\d+)gr(\d+)
see this
\D matches any non-digits and it matches # in your input.
Add # to the pattern instead of the opposite [^#] so as to match it.
Use
^(\d.{17})#(\D+)(\d+)gr(\d+)$
See proof it works. Adding anchors to match entire strings.
Explanation
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
( group and capture to \1:
--------------------------------------------------------------------------------
\d digits (0-9)
--------------------------------------------------------------------------------
.{17} any character except \n (17 times)
--------------------------------------------------------------------------------
) end of \1
--------------------------------------------------------------------------------
# '#'
--------------------------------------------------------------------------------
( group and capture to \2:
--------------------------------------------------------------------------------
\D+ non-digits (all but 0-9) (1 or more
times (matching the most amount
possible))
--------------------------------------------------------------------------------
) end of \2
--------------------------------------------------------------------------------
( group and capture to \3:
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
) end of \3
--------------------------------------------------------------------------------
gr 'gr'
--------------------------------------------------------------------------------
( group and capture to \4:
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
) end of \4
--------------------------------------------------------------------------------
$ before an optional \n, and the end of the
string
I'd like to match positively strings like "10a3b4c", "10a", "5b4c", "3a6c", but not match "2c1b" (because the letters aren't in alphabetical order) or the empty string.
Attempt: (\d+a)?(\d+b)?(\d+c)?
Problem: Matches the empty string. It falsely matches "".
Attempt: (\d+[abc]){1,3}
Problem: Doesn't enforce the a, b, c order. It falsely matches "2c1b"
How can this restriction be expressed as a regex?
Use
^(?!$)(\d+a)?(\d+b)?(\d+c)?$
See proof
Explanation
EXPLANATION
--------------------------------------------------------------------------------
^ the beginning of the string
--------------------------------------------------------------------------------
(?! look ahead to see if there is not:
--------------------------------------------------------------------------------
$ before an optional \n, and the end of
the string
--------------------------------------------------------------------------------
) end of look-ahead
--------------------------------------------------------------------------------
( group and capture to \1 (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
a 'a'
--------------------------------------------------------------------------------
)? end of \1 (NOTE: because you are using a
quantifier on this capture, only the LAST
repetition of the captured pattern will be
stored in \1)
--------------------------------------------------------------------------------
( group and capture to \2 (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
b 'b'
--------------------------------------------------------------------------------
)? end of \2 (NOTE: because you are using a
quantifier on this capture, only the LAST
repetition of the captured pattern will be
stored in \2)
--------------------------------------------------------------------------------
( group and capture to \3 (optional
(matching the most amount possible)):
--------------------------------------------------------------------------------
\d+ digits (0-9) (1 or more times (matching
the most amount possible))
--------------------------------------------------------------------------------
c 'c'
--------------------------------------------------------------------------------
)? end of \3 (NOTE: because you are using a
quantifier on this capture, only the LAST
repetition of the captured pattern will be
stored in \3)
--------------------------------------------------------------------------------
$ before an optional \n, and the end of the
string
This seems to work (see it on regex101)
\b(?=[\dabc]+\b)(\d+a)?(\d+b)?(\d+c)?\b