Trying to convert postgres time stamp string to c++ time stamp - c++

Question

I have PostgreSQL timestamp string:
2020-07-06 09:30:00.646533
I'm trying to convert it to timeval struct, I tried using this answer, but I'm getting this output:
Thu Jan 1 00:33:40 1970
This is my code:
#include <iostream>
int main()
{
std::string ss("2020-07-06 09:30:00.646533");
auto t = atoll(ss.c_str());
time_t time = atoi(ss.c_str());
std::cout << asctime(gmtime(&time));
return 0;
}
When running with debugger, I see that this line
auto t = atoll(ss.c_str());
isn't working/set time with values.
How can i fix it?

Answer 1

atoll and atoi simply parse integers of various sizes from a string. They aren't great functions to use in general as they have no way of indicating that they have failed to parse the string. std::stoi and friends are the better functions to use. However in this case we don't have a number we have a date string so std::stoi won't work either (but it can at least tell you it didn't work).
c++20 comes with much better date support, until then Howard Hinnant's date library provides the same functionality:
#include "date.h"
#include <iostream>
#include <sstream>
#include <chrono>
int main()
{
std::stringstream ss("2020-07-06 09:30:00.646533");
// convert string to date time
std::chrono::system_clock::time_point time;
ss >> date::parse("%F %T", time);
if (!ss) {
std::cout << "invalid date\n";
return 1;
}
// get the amount of time since the epoch, assumes std::chrono::system_clock uses the same epoch as timeval
auto sinceEpoch = time.time_since_epoch();
// get the whole number of seconds
auto seconds = date::floor<std::chrono::seconds>(sinceEpoch);
// get the remaining microseconds
auto microseconds = std::chrono::duration_cast<std::chrono::microseconds>(sinceEpoch - seconds);
std::cout << seconds.count() << ", " << microseconds.count() << "\n";
return 0;
}
If you must re-invent the wheel you can do it using the pre c++20 standard library:
#include <iostream>
#include <sstream>
#include <chrono>
#include <iomanip>
int main()
{
std::stringstream ss("2020-07-06 09:30:00.646533");
std::tm tm;
// convert string to date time
std::chrono::system_clock::time_point time;
double fraction;
ss >> std::get_time(&tm, "%Y-%m-%d %H:%M:%S") >> fraction;
if (!ss) {
std::cout << "invalid date\n";
return 1;
}
time_t seconds = mktime(&tm);
int64_t microseconds = fraction * 1'000'000;
std::cout << seconds << ", " << microseconds << "\n";
return 0;
}
Note that the microseconds should really be parsed as an integer not a double but you have to be careful to handle strings with different numbers of digits after the decimal point and with leading zeros.

Answer 2

you can use like this:
#include<ctime>
#include<iotream>
int main()
{
std::string ss = "2020-07-06 09:30:00.646533";
auto i = ss.find_first_of('.');
std::string line(ss.begin()+(i+1),ss.end());
std::tm tm = {};
tm.tm_isdst = -1; // <- to set not to use day lghite saveing.
strptime(ss.c_str(), "%F %H:%M:%S", &tm); //<-enter the data to tm
start.tv_sec = mktime(&tm); //<-convert tm to time_t
start.tv_usec = stoi(line); // <- set the usec from the stirng
//IF you want the other why around
strftime(tmbuf, sizeof tmbuf, " %F %H:%M:%S", localtime(&start.tv_sec));
snprintf(buf, sizeof buf, "%s.%06ld", tmbuf, start.tv_usec);
std::cout << tmbuf;
return 0;
}
output:
2020-07-06 09:30:00.646533