SwiftUI Multiple alerts for same button [duplicate] - swiftui

Question

This question already has answers here:
how to show different alerts based on a condition after clicking a button in swiftui
(3 answers)
Closed 2 years ago.
The code below only shows the false alert. Is there a way to make the alert match the IF condition?
#State var showTrueAlert = false
#State var showFalseAlert = false
var body: some View {
Button(action: {
let isTrue = Bool.random()
if isTrue {
self.showTrueAlert = true
print("True Alert")
} else {
self.showFalseAlert = true
print("False Alert")
}
}) {
Text("Random Alert")
.font(.largeTitle)
}
.alert(isPresented: $showTrueAlert) {
Alert(title: Text("True"))
}
.alert(isPresented: $showFalseAlert) {
Alert(title: Text("False"))
}
}

Answer 1

You can apply .alert only once to a View. Create a State which only handles the current State of the Alert and then two variables which decide if false or true was pressed. (might store that in one variable only aswell)
struct ContentView6: View {
#State var showAlert : Bool = false
#State var showTrueAlert = false
#State var showFalseAlert = false
var body: some View {
Button(action: {
let isTrue = Bool.random()
if isTrue
{
self.showTrueAlert = true
self.showAlert = true
print("True Alert")
} else {
self.showFalseAlert = true
self.showAlert = true
print("False Alert")
}
}) {
Text("Random Alert")
.font(.largeTitle)
}
.alert(isPresented: Binding<Bool>(
get: {
self.showAlert
},
set: {
self.showAlert = $0
self.showTrueAlert = false
self.showFalseAlert = false
})) {
if (showTrueAlert)
{
return Alert(title: Text("True"))
}
else
{
return Alert(title: Text("False"))
}
}
}
}