How to use a string literal as a macro argument? - c++

Question

My question is the inverse of this question.
I want to write a macro that will accept an integer and a string literal as it's arguments, like so:
#define STRING_MAP_ENTRY(value, name) \
{value, std::to_string(val) + " - " + name}
STRING_MAP_ENTRY(0, "ENTRY_1")
The macro should turn the above call into {0, "0 - ENTRY_1"}
Is there a way to do this? My current attempt is this:
#define STRING_MAP_ENTRY(val, name) \
{ val, std::to_string(val) + "(" + name + ")" }

Answer 1

Something like this could work:
#define STRING_MAP_ENTRY(value, name) \
{value, #value " - " #name}
STRING_MAP_ENTRY(0, ENTRY_1)
the # before a token will stringify it. As for combining them, adjacent string literals will be combined into a single string.

Answer 2

Why do you want to use macro?
It's not good.
Use this:
auto STRING_MAP_ENTRY(int value_,string name_){
struct{int value;string name;} pair_{value_,to_string(value_)+string(" - ")+name_};
return pair_;
}
And use this to check if it works:
auto aa= STRING_MAP_ENTRY(0,string("ENTRY_1"));
cout<<aa.value<<','<<aa.name<<endl; // 0,0 - ENTRY_1
Remember:
Always use FUNCTION not MACRO!!