Please note that I am new to XSLT and will probably never have to use it again.
I have a simplified XML document that looks like the following:
<row>
<tax_allocation_details>
<tax_allocation_detail>
<allocation_percent>0.0269</allocation_percent>
</tax_allocation_detail>
<tax_allocation_detail>
<allocation_percent>0.0583</allocation_percent>
</tax_allocation_detail>
<tax_allocation_detail>
<allocation_percent>0.1704</allocation_percent>
</tax_allocation_detail>
<tax_allocation_detail>
<allocation_percent>0.7444</allocation_percent>
</tax_allocation_detail>
</tax_allocation_details>
<ParticipantID>364787525</ParticipantID>
<TransactionAmount>407252.34</TransactionAmount>
</row>
What I'm trying to do is output the sum of all the products of allocation_percent * TransactionAmount and don't have the slightest idea of how to do that. I'm using XSLT 2.0 and have done some research and found that
sum(for $x in node-set return f($x))
could be used but I have absolutely no idea how to implement it and don't have the time needed to understand it.
Use this XPath 2.0 expression:
sum(/*/*/tax_allocation_detail/allocation_percent/(../../../TransactionAmount * .))
XSLT 2.0 - based verification:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<xsl:sequence select=
"sum(/*/*/tax_allocation_detail/allocation_percent/(../../../TransactionAmount * .))"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on the provided XML document:
<row>
<tax_allocation_details>
<tax_allocation_detail>
<allocation_percent>0.0269</allocation_percent>
</tax_allocation_detail>
<tax_allocation_detail>
<allocation_percent>0.0583</allocation_percent>
</tax_allocation_detail>
<tax_allocation_detail>
<allocation_percent>0.1704</allocation_percent>
</tax_allocation_detail>
<tax_allocation_detail>
<allocation_percent>0.7444</allocation_percent>
</tax_allocation_detail>
</tax_allocation_details>
<ParticipantID>364787525</ParticipantID>
<TransactionAmount>407252.34</TransactionAmount>
</row>
the above XPath expression is evaluated and the result of this evaluation is output:
407252.34
You set up a template that will match tax_allocation_details then sum across the nodes:
<xsl:template match="tax_allocation_details">
<p><xsl:value-of select="sum($tranAmount * tax_allocation_detail/allocation_percent)" /></p>
</xsl:template>
Related
I have problem with XSLT and/or XPATH. Let's say I have XML Input:
<context>
<pdpid-set>
<list>
<item>1</item>
<item>2</item>
<item>4</item>
<item>6</item>
<item>7</item>
<item>8</item>
</list>
</pdpid-set>
</context>
Task is: find FIRST missing element in array pdpid-set/list. In example above answer is 3.
I tried to use <xsl:for-each to find missing element but there is no possibility to break such loop so my XSL produce more than one element in output:
<xsl:variable name="list" select="context/pdpid-set/list"/>
<xsl:variable name="length" select="count(context/pdpid-set/list/item)"/>
<xsl:for-each select="1 to ($length)">
<xsl:variable name="position" select="position()"/>
<xsl:if test="$list/item[$position] > $position">
<missing-value>
<xsl:value-of select="$position"/>
</missing-value>
</xsl:if>
</xsl:for-each>
in code above output will be:
<missing-value>3</missing-value><missing-value>4</missing-value><missing-value>5</missing-value>...
I don't want to have more than one missing-value. Any suggestion?
Even in XPath 1.0
/context
/pdpid-set
/list
/item[not(position()=.)][1]
Do note: this select the first item not aligned with the ascending order. I still think that position() is better than following-sibling axis performance wise and for code clarity. Also, it lets you easily change starting number and step like in:
/context
/pdpid-set
/list
/item[not((position() - 1) * $step + $start = .)][1]
Task is: find FIRST missing element in array pdpid-set/list. In
example above answer is 3
Here is a correct XPath 1.0 expression that when evaluates to the wanted result (3):
/*/*/*/item[not(. +1 = following-sibling::*[1])][1] + 1
The XPath expression in the currently selected answer, on the other side, selects this element:
<item>4</item>
And the complete correct XSLT 1.0 transformation is:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/">
<missing-value>
<xsl:copy-of select="/*/*/*/item[not(. +1 = following-sibling::*[1])][1] + 1"/>
</missing-value>
</xsl:template>
</xsl:stylesheet>
When applied on the provided XML document, the wanted, correct result is produced:
<missing-value>3</missing-value>
Finally, if the task is to find all missing elements:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match=
"item[following-sibling::* and not(number(.) +1 = following-sibling::*[1]/number())]">
<xsl:for-each select="xs:integer(.) + 1 to following-sibling::*[1]/xs:integer(.) -1">
<missing-value><xsl:copy-of select="."/></missing-value>
</xsl:for-each>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
when this XSLT 2.0 transformation is applied on the following XML document (missing 3, 5, and 6):
<context>
<pdpid-set>
<list>
<item>1</item>
<item>2</item>
<item>4</item>
<item>7</item>
<item>8</item>
</list>
</pdpid-set>
</context>
the wanted, correct result is produced:
<missing-value>3</missing-value>
<missing-value>5</missing-value>
<missing-value>6</missing-value>
I am trying to learn the basics of XSLT, but am stuck on a particular use case. What I want to achieve is to transform one xml file into another xml (I am using XSLT 2.0), but a condition is that the grouping of elements in the output xml is decided by the value of one particular element in the input xml.
I will try to exemplify my question through a made-up example.
Lets say this is an input xml:
<products>
<shoes>
<shoe>
<name>Ecco City</name>
<category>Urban</category>
</shoe>
<shoe>
<name>Timberland Forest</name>
<category>Wildlife</category>
</shoe>
<shoe>
<name>Asics Gel-Kayano</name>
<category>Running</category>
</shoe>
</shoes>
<clothes>
<shorts>
<name>North Face</name>
<category>Wildlife</category>
</shorts>
<shorts>
<name>Adidas Running Shorts</name>
<category>Running</category>
</shorts>
</clothes>
Based on the value of the category element I want to, for each product, list similar products, that is, other products having the same category in the input xml, like this:
<output>
<forSale>
<item>Asics Gel-Kayano</item>
<similarItem>Adidas Running Shorts</similarItem>
</forSale>
</output>
This doesn't seem to be a grouping problem as such. If I understand correctly, you want to do something like:
XSLT 2.0
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:key name="product-by-category" match="*" use="category" />
<xsl:template match="/products">
<output>
<xsl:for-each select="*/*">
<forSale>
<item>
<xsl:value-of select="name" />
</item>
<xsl:for-each select="key('product-by-category', category) except .">
<similarItem>
<xsl:value-of select="name" />
</similarItem>
</xsl:for-each>
</forSale>
</xsl:for-each>
</output>
</xsl:template>
</xsl:stylesheet>
Applied to your input example, the result will be:
<?xml version="1.0" encoding="UTF-8"?>
<output>
<forSale>
<item>Ecco City</item>
</forSale>
<forSale>
<item>Timberland Forest</item>
<similarItem>North Face</similarItem>
</forSale>
<forSale>
<item>Asics Gel-Kayano</item>
<similarItem>Adidas Running Shorts</similarItem>
</forSale>
<forSale>
<item>North Face</item>
<similarItem>Timberland Forest</similarItem>
</forSale>
<forSale>
<item>Adidas Running Shorts</item>
<similarItem>Asics Gel-Kayano</similarItem>
</forSale>
</output>
Say this is my xml :
<History>
<University>TSU</University>
<Payload>
<Attrib Order="0">OVERSEA</Attrib>
<Attrib Order="1">GRADE2</Attrib>
<Attrib Order="2"><Person><ID>TQR344</ID></Person></Attrib>
<Attrib Order="3">3566644</Attrib>
</Payload>
</History>
And I want to query the inner XML inside Order=2 tag and read ID of the person.
I have created this so far :
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
>
<xsl:output method="xml" encoding="UTF-8" indent="yes" omit-xml-declaration="no" />
<xsl:template match="/History">
<xsl:apply-templates select="/History" />
</xsl:template>
<xsl:template name="Person" match="//History">
<Event>
<Uni><xsl:value-of select="University" /></Uni>
<ID><xsl:value-of select="Payload/Attrib[#Order='2']/Person/ID" disable-output-escaping="yes" /></ID>
</Event>
</xsl:template>
</xsl:stylesheet>
But as you can see it is not working.
Also I assigned the inner XML into a variable and tried to query that variable and It didn't work too.
Is it possible to do that via xsl ?
Limitations : I cannot change xml format. But maybe I was able to move from xsl ver 1 to new versions.
I want to query the inner XML inside Order=2 tag
The tag in question does not contain any XML; its content is a string and needs to be manipulated using string functions. Try:
XSLT 1.0
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>
<xsl:template match="/History">
<Event>
<Uni>
<xsl:value-of select="University" />
</Uni>
<ID>
<xsl:value-of select="substring-before(substring-after(Payload/Attrib[#Order='2'], '<ID>'),'</ID><')"/>
</ID>
</Event>
</xsl:template>
</xsl:stylesheet>
Note:
1. This:
<xsl:template match="/History">
<xsl:apply-templates select="/History" />
</xsl:template>
creates an infinite loop and will crash your processor.
2. Alternatively, you could serialize the string back into XML and process the result as XML; in XSLT 1.0, this can be done only by outputting the string with the escaping disabled, saving the result as a new document, then processing the new document with another XSLT stylesheet. Using XSLT 3.0 (or a processor that supports serializing as an extension) this can be all done during the same transformation.
I have the following XML:
<?xml version="1.0" encoding="utf-8"?>
<string>
<Table>
<Rows>
<Row Id="0">
<Column Name="INS_NAME" XPath="Ins.Name">Jane</Column>
<Column Name="INS_LASTNAME" XPath="Ins.LastName">Smith</Column>
</Row>
<Row Id="1">
<Column Name="INS_NAME" XPath="Ins.Name">Joe</Column>
<Column Name="INS_LASTNAME" XPath="Ins.LastName">Miller</Column>
</Row>
<Row Id="2">
<Column Name="INS_NAME" XPath="Ins.Name">George</Column>
<Column Name="INS_LASTNAME" XPath="Ins.LastName">Ramsey</Column>
</Row>
</Rows>
</Table>
</string>
and I would like to transform it to this XML using a single XSLT:
<?xml version="1.0" encoding="utf-8"?>
<Customers>
<Customer><Name>Jane</Name><LastName>Smith</LastName></Customer>
<Customer><Name>Joe</Name><LastName>Miller</LastName></Customer>
<Customer><Name>George</Name><LastName>Ramsey</LastName></Customer>
</Customers>
I can do it with two different XSLT's:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:value-of select="/" disable-output-escaping="yes" />
</xsl:template>
</xsl:stylesheet>
and then:
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<Customers>
<xsl:for-each select="Table/Rows/Row">
<Customer>
<Name><xsl:value-of select="Column[#Name='INS_NAME']" /></Name>
<LastName><xsl:value-of select="Column[#Name='INS_LASTNAME']" /></LastName>
</Customer>
</xsl:for-each>
</Customers>
</xsl:template>
</xsl:stylesheet>
I have been reading about multi phase transformations but I can't seem to get it. I have tried saving the first XSLT in a variable but it seems disable-output-escaping="yes" does not work when saving to a variable.
Can anybody help?
Thank you.
New information (Edit)
I am now translating the string this way:
<xsl:output method="text"/>
<xsl:template match="/">
<xsl:variable name="stringXml">
<?xml version="1.0" encoding="utf-8"?>
<xsl:value-of select="translate(translate(/,'>','>'),'<','<')" />
</xsl:variable>
...
How can I do a transformation on the resulting XML stored in stringXML?
Final Solution (Edit)
<msxml:script implements-prefix="myLib" language="C#">
<msxml:assembly name="System.Web"/>
<msxml:using namespace="System.Web"/>
<![CDATA[
public System.Xml.XPath.XPathNodeIterator convertText(string text)
{
XmlDocument doc = new XmlDocument();
doc.PreserveWhitespace = true;
doc.LoadXml(text);
return doc.CreateNavigator().Select("/");
}
]]>
</msxml:script>
it seems disable-output-escaping="yes" does not work when saving to a
variable.
Your observation is correct.
DOE only affects the serialization of the (final) result of the transformation and isn't applied on intermediary trees.
Here is what the W3C XSLT 1.0 specification explicitly says:
"An XSLT processor will only be able to disable output escaping if it
controls how the result tree is output. This may not always be the
case. For example, the result tree may be used as the source tree for
another XSLT transformation instead of being output."
The same negative answer holds for trying to use a variable, whose value is a string, containing a textual representation of an XML document.
I had a similar situation where I needed to parse an escaped XML inside my actual XML. I will post up my solution to also help someone else. Please also note that I am also using Saxon-PE parser.
In my situation I have the original XML that contains an escaped XML in a child node. I needed to get the inner XML inside the RootNode of the escaped XML.
Source XML:
<?xml version="1.0" encoding="utf-8"?>
<MyTestXml>
<SomeXmlStuff>
<Text1>Hello</Text1>
<Text2>World</Text2>
</SomeXmlStuff>
<SomeEscapedXml><RootNode><FirstNode>Hello</FirstNode><SecondNode>World</SecondNode><ThirdNode>Again</ThirdNode></RootNode></SomeEscapedXml>
</MyTestXml>
When you unescaped the XML, it looks like this:
<RootNode>
<FirstNode>Hello</FirstNode>
<SecondNode>World</SecondNode>
<ThirdNode>Again</ThirdNode>
</RootNode>
With the following XSLT transformation is applied on the source XML:
<?xml version='1.0' encoding='utf-8' ?>
<xsl:stylesheet version="3.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:saxon="http://saxon.sf.net/"
exclude-result-prefixes="xsl saxon">
<xsl:template match="/">
<MyOutput>
<xsl:call-template name="GetRootNodeInnerXml">
<xsl:with-param name="escapedXml" select="MyTestXml/SomeEscapedXml" />
</xsl:call-template>
</MyOutput>
</xsl:template>
<xsl:template name="GetRootNodeInnerXml">
<xsl:param name="escapedXml" required="yes" />
<xsl:copy-of select="saxon:parse($escapedXml)/RootNode/node()"/>
<!-- You can also use this line below if you're not using saxon parser. Just make sure your parser supports XSL 3.0 -->
<!--
<xsl:copy-of select="fn:parse-xml($escapedXml)/RootNode/node()" xmlns:fn="http://www.w3.org/2005/xpath-functions"/>
-->
</xsl:template>
</xsl:stylesheet>
This gives you the following output:
<?xml version='1.0' ?>
<MyOutput>
<FirstNode>Hello</FirstNode>
<SecondNode>World</SecondNode>
<ThirdNode>Again</ThirdNode>
</MyOutput>
I have the following code (eg):
<response>
<parameter>
<cottage>
<cot>
<res>
<hab desc="Lakeside">
<reg cod="OB" prr="600.84>
<lwz>TR#2#AB#200.26#0#QB#OK#20120829#20120830#EU#3-0#</lwz>
<lwz>TR#2#AB#200.26#0#QB#OK#20120830#20120831#EU#3-0#</lwz>
<lwz>TR#2#AB#200.26#0#QB#OK#20120831#20120901#EU#3-0#</lwz>
I need to create a concatenated string that includes the whole of the first 'lwz' line and then the price (200.26, but it can be different in each line) for each corresponding line.
So the output, separating each line with | would be:
TR#2#AB#200.26#0#QB#OK#20120829#20120830#EU#3-0#|200.26|200.26
Thanks
This XSLT 1.0 transformation:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:strip-space elements="*"/>
<xsl:template match="lwz[1]">
<xsl:value-of select="."/>
</xsl:template>
<xsl:template match="lwz[position() >1]">
<xsl:value-of select=
"concat('
',
substring-before(substring-after(substring-after(substring-after(.,'#'),'#'),'#'),'#')
)
"/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
when applied on the provided text (converted to a well-formed XML document !!!):
<response>
<parameter>
<cottage>
<cot>
<res>
<hab desc="Lakeside">
<reg cod="OB" prr="600.84">
<lwz>TR#2#AB#200.26#0#QB#OK#20120829#20120830#EU#3-0#</lwz>
<lwz>TR#2#AB#200.26#0#QB#OK#20120830#20120831#EU#3-0#</lwz>
<lwz>TR#2#AB#200.26#0#QB#OK#20120831#20120901#EU#3-0#</lwz>
</reg>
</hab>
</res>
</cot>
</cottage>
</parameter>
</response>
produces the wanted, correct result:
TR#2#AB#200.26#0#QB#OK#20120829#20120830#EU#3-0#
200.26
200.26
II XSLT 2.0 solution:
This transformation:
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="text"/>
<xsl:strip-space elements="*"/>
<xsl:template match="lwz[1]">
<xsl:value-of select="."/>
</xsl:template>
<xsl:template match="lwz[position() >1]">
<xsl:value-of select=
"concat('
', tokenize(.,'#')[4])"/>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
when applied on the above XML document, again produces the wanted, correct result. Note the use of the standard XPath 2.0 function tokenize():
TR#2#AB#200.26#0#QB#OK#20120829#20120830#EU#3-0#
200.26
200.26
You can use the XPath substring function to select substrings from your lwz node data. You don't really give much more detail about your problem, if you want a more detailed answer, perhaps provide the full XML document and your best-guess XSLT