I require an IF statement in Tableau to find certain people (players) who only played Sports & not Casino. The formulas I have tried are:
IF [Bet € for Calculation €]>0 THEN
IF [Product Vertical]="sport" THEN
IF [Bet € for Calculation €]=0 THEN
IF [Product Vertical]="casino" THEN
THEN [Bet € for Calculation €] END
ELSE NULL
END
I have also tried an AND version, but both come out with errors.
Any help would be greatly appreciated.
Have you tried to include brackets?
IF (([Bet € for Calculation €]>0)
AND ([Product Vertical]="sport")
AND ([Bet € for Calculation €]=0)
AND ([Product Vertical]="casino"))
THEN [Bet € for Calculation €]
ELSE NULL
END
Related
Im trying to get the number between '-' and '-' in google sheets but after trying many things I still havent been able to find the solution.
Data record 1
England Premier League
West Ham vs Crystal Palace
2.090 - 3.47 - 3.770
Expected value = 3.47
Data record 2
England League Two
Carlisle vs Scunthorpe
2.830 - 3.15 - 2.820
Expected value = 3.15
Hopefully someone can help me out
Try either of the following
option 1.
=INDEX(IFERROR(REGEXEXTRACT(AE1:AE4," \d+\.\d+ ")*1))
option 2.
=INDEX(IFERROR(REGEXEXTRACT(AE1:AE4,".* - (\d+\.\d+) ")))
(Do adjust the formula according to your ranges and locale)
use:
=INDEX(IFNA(REGEXEXTRACT(A1:A, "- (\d+(?:.\d+)?) -")*1))
A UK number looks like this 233.25 .
For a Dutch Number, it looks like this in the Power APP 233,25.
This works for the Power App in the UK but not in Holland, due to the comma for the decimal separator. How can I change this to get it to work? I have tried an OR statement but it does not work . ( ( TextInput.Text,"\d+(.\d{0,2})?") ) - REGEX
If(IsMatch( TextInput.Text,"\d+(.\d{0,2})?"), //justify whether meet the format
Submit(Form1), //submit the form if the result is true
Nodify("wrong format",NotificationType.Warning)) //display Notification if the result is false
You could try to format it yourself. Regardless of what the user inputs.
Left(Value(TextInput.Text),Len(Value(TextInput.Text))-2) & "," & Right(Value(TextInput.Text),2) & "."
I am working with a educational dataset called IPEDS from the National Center for Educational Statistics. They track students in college based upon major, degree completion, etc. The problem in Stata is that I am trying to determine the total count for degrees obtained by a specific major.
They have a variable cipcode which contains values that serve as "majors". cipcode might be 14.2501 "petroleum engineering, 16.0102 "Linguistics" and so forth.
When I write a particular code like
tab cipcode if cipcode==14.2501
it reports no observations. What code will give me the totals?
/*Convert Float Variable to String Variable and use Force Replace*/
tostring cipcode, gen(cipcode_str) format(%6.4f) force
replace cipcode_str = reverse(substr(reverse(cipcode_str), indexnot(reverse(cipcode_str), "0"), .))
replace cipcode_str = reverse(substr(reverse(cipcode_str), indexnot(reverse(cipcode_str), "."), .))
/* Created a total variable called total_t1 for total count of all stem majors listed in table 1*/
gen total_t1 = cipcode_str== "14.2501" + "14.3901" + "15.0999" + "40.0601"
This minimal example confirms your problem. (See, by the way, https://stackoverflow.com/help/mcve for advice on good examples.)
* code
clear
input code
14.2501
14.2501
14.2501
end
tab code if code == 14.2501
tab code if code == float(14.2501)
* results
. tab code if code == 14.2501
no observations
. tab code if code == float(14.2501)
code | Freq. Percent Cum.
------------+-----------------------------------
14.2501 | 3 100.00 100.00
------------+-----------------------------------
Total | 3 100.00
The keyword is one you use, precision. In Stata, search precision for resources, starting with blog posts by William Gould. A decimal like 14.2501 is hard (impossible) to hold exactly in binary and the details of holding a variable as type float can bite.
It's hard to see what you're doing with your last block of code, which you don't explain. The last statement looks puzzling, as you're adding strings. Consider what happens with
. gen whatever = "14.2501" + "14.3901" + "15.0999" + "40.0601"
. di whatever[1]
14.250114.390115.099940.0601
The result is a long string that cannot be a valid cipcode. I suspect that you are reaching towards
... if inlist(cipcode_str, "14.2501", "14.3901", "15.0999", "40.0601")
which is quite different.
But using float() is the minimal trick for this problem.
I have a column with a formula which reads:
Utilisation (Excl. Time-off) = Utilisation_Excl_Timeoff[Billable Hours]/(Utilisation_Excl_Timeoff[Available Hours] - Utilisation_Excl_Timeoff[Timeoff Hours (Excl. Public)])
It gives me a "NaN" error in my calculated column for some of the cells due to divide by zero.
I would like to replace the NaN with a 0% instead so that the column displays correctly in my matrix chart.
Take a look at the DIVIDE function (https://msdn.microsoft.com/en-us/library/jj677276.aspx).
This is a 'safe divide` function with the option to return an alternative value if the division returns an error.
-JP
If you are looking for solution in M, then add conditional column:
Set up Otherwise temporarily to dividend column, here I took [Value] column. After doing this change in editor [Value] to [Value]/[Units]. This returns null wherever Units is 0. You may change returned output to 0% according to thy wish.
Alternatively, you can do it as well by adding this step:
= Table.AddColumn(#"Previous Step", "UnitPrice", each if [Units] = 0 then "0%" else [Value]/[Units])
IFERROR(value, value_if_error) function can do this. MSDN
Utilisation (Excl. Time-off) = IFERROR(Utilisation_Excl_Timeoff[Billable Hours]/(Utilisation_Excl_Timeoff[Available Hours] - Utilisation_Excl_Timeoff[Timeoff Hours (Excl. Public)]), 0)
I need to calculate the Gini coefficient from disposable personal income data at LIS. According to a LIS training document, the Stata code to do this is:
di "** INCOME DISTRIBUTION II – Exercise 13 **"
program define bottop
qui sum ey [w=hweight*d4]
replace ey = .01*r(mean) if ey<.01*r(mean)
qui sum dpi [w=hweight*d4], de
replace ey = (10*r(p50)/(d4^.5)) if dpi>10*r(p50)
end
foreach file in $us00h $fi00h {
display "`file'"
use hweight d4 dpi if (!mi(dpi) & !(dpi==0)) using "`file'", clear
gen ey=dpi/(d4^0.5)
bottop
ineqdeco ey [w=hweight*d4]
}
I have simply copied and pasted this code from the training document. The snippets
qui sum ey [w=hweight*d4]
replace ey=0.01*r(mean) if ey<0.01*r(mean)
and
qui sum dpi [w=hweight*d4], de
replace ey=(10*r(p50)/(d4^0.5)) if dpi>10*r(p50)
are bottom and top coding, respectively.
When I tried to run this code, the variable hweight was not found. Does anyone know what the new name of hweight is at LIS? Or can anyone suggest how I might otherwise overcome this impasse?
I'm familiar with stata, but the sophistication of this code is beyond my ken.
Much appreciated.
Based on the varaiable definition list at the LIS Documentation page, it looks like the variable is now called HWGT
This is more of a second-best solution. However, the census of population provides income by brackets. If you are willing to do that, you can get the counts for every bracket. Have a top-coded bracket for the last one. Use the median income value within each bracket. Then you can directly apply the formula for the Gini coefficient. It is a second best because it is an approximation for the individaul-level data.
Why don't you try the fastgini command:
http://www.stata.com/statalist/archive/2007-02/msg00524.html
ssc install fastgini
fastgini income
return list
this should give you the gini for the variable income.
This package also allows for weights. Type
help fastgini
for more information