I'am working on a program where there are first names, last names and a numbers on a file and i need to read that information into my program. My actual problem is that there is people who doesnt have a second name or second last name. To solve the issue I started trying to read from a file until a specific character is found, For example:
Robert, Ford Black,208 //Where Robert is the first name, and Ford Black are his two last names
George Richard, Bradford,508 //Where George Richard are both his first names, and Bradford is his only last
name
I am saving this information in three separeted string, one that will store first and second name, first last and second last name and the third one for the numbers.
I'm trying to only use native libraries from c++.
I've been reading that getline(a,b,c) and IStringStream can actually solve my problem but I don't know how to correctly implement it
It's just a matter of using std::getline with a delimiter character to read out of the string stream. See a simplified example (no error checking) below:
for (std::string line; std::getline(std::cin, line); )
{
std::string firstName, lastName;
std::istringstream iss(line);
std::getline(iss, firstName, ','); // A comma delimits end-of-input
iss >> std::ws; // Skip over any whitespace characters
std::getline(iss, lastName); // Read remaining line
std::cout << "First Name: " << firstName << std::endl;
std::cout << "Last Name: " << lastName << std::endl;
}
Note the line iss >> std::ws; using std::ws from <iomanip> is there to eat up extra whitespace characters (which appear after your comma, in your example).
I'm assuming the C++ line comments in the input are only an annotation for this question, and not part of the actual input.
#include<bits/stdc++.h>
using namespace std;
int main()
{
ifstream myfile("files.txt");
string fullname;
while(getline(myfile,fullname,'/')) break; //here im reading till the first / is acquired and the entire string is stored in "fullname"
string firstname,lastname;
size_t pos=fullname.find(',');
firstname=fullname.substr(0,pos); //store the firstname
lastname=fullname.substr(pos+1);// storee the lastname
cout<<firstname<<" "<<lastname;
}
As the question posed was to read names im assuming before the digit if there were a " / " you can read upto the first occurance of /. this will give you the fullname. Then using the substr on the fullname and find the occurance of a comma if at all it exists. All the characters to the left of position of comma will form your first name and the rest on the right of the position of comma will form the lastname.
Related
I'm trying to find a certain word in a string, but find that word alone. For example, if I had a word bank:
789540132143
93
3
5434
I only want a match to be found for the value 3, as the other values do not match exactly. I used the normal string::find function, but that found matches for all four values in the word bank because they all contain 3.
There is no whitespace surrounding the values, and I am not allowed to use Regex. I'm looking for the fastest implementation of completing this task.
If you want to count the words you should use a string to int map. Read a word from your file using >> into a string then increment the map accordingly
string word;
map<string,int> count;
ifstream input("file.txt");
while (input.good()) {
input >> word;
count[word]++;
}
using >> has the benefit that you don't have to worry about whitespace.
All depends on the definition of words: is it a string speparated from others with a whitespace ? Or are other word separators (e.g. coma, dot, semicolon, colon, parenntheses...) relevant as well ?
How to parse for words without regex:
Here an accetable approach using find() and its variant find_first_of():
string myline; // line to be parsed
string what="3"; // string to be found
string separator=" \t\n,;.:()[]"; // string separators
while (getline(cin, myline)) {
size_t nxt=0;
while ( (nxt=myline.find(what, nxt)) != string::npos) { // search occurences of what
if (nxt==0||separator.find(myline[nxt-1])!=string::npos) { // if at befgin of a word
size_t nsep=myline.find_first_of(separator,nxt+1); // check if goes to end of wordd
if ((nsep==string::npos && myline.length()-nxt==what.length()) || nsep-nxt==what.length()) {
cout << "Line: "<<myline<<endl; // bingo !!
cout << "from pos "<<nxt<<" to " << nsep << endl;
}
}
nxt++; // ready for next occurence
}
}
And here the online demo.
The principle is to check if the occurences found correspond to a word, i.e. are at the begin of a string or begin of a word (i.e. the previous char is a separator) and that it goes until the next separator (or end of line).
How to solve your real problem:
You can have the fastest word search function: if ou use it for solving your problem of counting words, as you've explained in your comment, you'll waste a lot of efforts !
The best way to achieve this would certainly be to use a map<string, int> to store/updated a counter for each string encountered in the file.
You then just have to parse each line into words (you could use find_fisrst_of() as suggested above) and use the map:
mymap[word]++;
I have a text file that resembles
1 \t words words words words
2 \t words words words words
where the # is the line #, followed by a tab, then followed by random words
I need to read in the int, store it, then skip the \t, and read in each word individually while keeping track of that words position.
I was hoping I could it with getline(file, word, ' '), and a counter but that grabs my first word as 1 \t words.
Any help or suggestions would be much appreciated.
use stringstream and getline,
getline(file, line);
std::stringstream ssline(line);
int num;
ssline >> num;
std::string word;
while(ssline >> word){
// do whatever you want.
}
Assuming that you can't say how many words there are on a line, then the simple answer is to do it in two steps.
Read a whole line into a string with getline
Place that string into a std::istringstream and read the line number and following words from the std::istringstream
then repeat from step 1
Hi I have a string like this:
word1--tab--word2--tab--word3--tab--word4--tab--word5--tab--word6
I need to extract the third word from the string. I thought of reading character by character and getting the word after reading the second tab. But I guess it is inefficient. Can you show me a more specific way please?
std::string has the find method which returns an index. You can use
find("--", lastFoundIndex + 1)
three times to find the start index of your word, a fourth time for the end index, and then use substr.
assuming "tab" is \t;
std::istringstream str(".....");
std::string temp, word;
str >> temp >> temp >> word;
I have for example
string s = " abc edef";
I create istringstream with this string.
Is there any way to from getline get only "abc"and "edef" ? Beacouse now I get that empty string between pairs of spaces :/
Use the >> operator to get only whitespace-delimited "words".
Programming novice here. I'm trying to allow a user to enter their name, firstName middleName lastName on one line in the console (ex. "John Jane Doe"). I want to make the middleName optional. So if the user enters "John Doe" it only saves the first and last name strings. If the user enters "John Jane Doe" it will save all three.
I was going to use this:
cin >> firstName >> middleName >> lastName;
then I realized that if the user chooses to omit their middle name and enters "John Doe" the console will just wait for the user to enter a third string... I know I could accomplish this with one large string and breaking it up into two or three, but isn't there a simpler way to do it with three strings like above?
I feel like I'm missing something simple here...
Thanks in advance.
Use getline and then parse using a stringstream.
#include <sstream>
string line;
getline( cin, line );
istringstream parse( line );
string first, middle, last;
parse >> first >> middle >> last;
if ( last.empty() ) swap( middle, last );