Regex Last Character or Position from Found String - regex

Question

I've looked through Regex Last occurrence? but cannot get the regex to work for my example string ("https://www.fakesite.com test one"). I need to return the last character of the website name only (or the position). I have the expressions for both capturing the site and obtaining the last character but cannot get the expression to get the right look behind.
(https?:\/\/(?:www\.|(?!www))[a-zA-Z0-9][a-zA-Z0-9-]+[a-zA-Z0-9]\.[^\s]
{2,}|www\.[a-zA-Z0-9][a-zA-Z0-9-]+[a-zA-Z0-9]\.[^\s]{2,}|https?:\/\/(?:www\.|
(?!www))[a-zA-Z0-9]+\.[^\s]{2,}|www\.[a-zA-Z0-9]+\.[^\s]{2,}) <- Regular Expression for website
(?=.?$). <- Regular Expression for retrieving last character
I've been using https://regex101.com/ to try and find, but no luck.
How can I retrieve the last character or position?
--Edit--
How can I retrieve just the last character of any string? (I need just the letter 'r' in System Engineer). 'System Engineer' is dynamic.
"for the position of System Engineer located in"
(?<=position of )(.*)(?= located) <- regex to capture System Engineer between words 'position of' and 'located'

Answer 1

You may try the below regex. The below regex will check for valid url address as well as will get you the last character of your url.
https?:\/\/(?:www\.)?[-a-zA-Z0-9#:%._\+~#=]{1,256}\.[a-zA-Z0-9()]{1,6}(\w)\b(?:[-a-zA-Z0-9()#:%_\+.~#?&\/\/=]*)
Explanation of the above regex:
https?:\/\/(?:www\.)?[-a-zA-Z0-9#:%._\+~#=]{1,256} - Matches the http/https:// part of the regex along with www and the domain name before the first ..
[a-zA-Z0-9()]{1,6} - This part matches the last of the url part.
(\w) - Represents a capturing group capturing the last character of the url. You may use ([a-zA-Z0-9]) manually if you don't want to include _.
\b(?:[-a-zA-Z0-9()#:%_\+.~#?&\/\/=]*) - Matches the rest part of the url like .uk or .in, etc. zero or more times.
You can find the demo of the above regex in here.
Reference: The regex for matching the valid url is taken from this answer.
If you want to get amendments in your regex; just add [a-zA-Z] after your regex. You can find the demo here.