Disabling assert macro in C++ - c++

I'm trying to disable the assert macro in C++ in this way:
#include <stdio.h> /* printf */
#include <assert.h> /* assert */
#define NDEBUG
void print_number(int* myInt) {
assert (myInt != NULL);
printf ("%d\n", *myInt);
}
int main ()
{
int a = 10;
int * b = NULL;
int * c = NULL;
b = &a;
print_number (b);
print_number (c);
return 0;
}
The official website says that if I define NDEBUG, all the assert macro will be disable. This way doesn't work. Can you tell me how fix it?

The NDEBUG define controls the definition of the assert macro, not its expansion. In order for it to be effective, you need to define it before the macro itself is defined, which happens in assert.h.
There are two ways to achieve that:
put the #define NDEBUG before the line that says #include <assert.h>; or
define NDEBUG on the command line, by doing something like:
cc -DNDEBUG main.c
Perhaps you should also take a step back and consider why you are trying to disable assertions. After all, the assertions are there for a reason, so unless you are running on a 40MHz SPARCstation, you should probably not be disabling them.

Related

How to achieve a c++ macros like this

#define idebug(...) \
\#ifdef _DEBUG\
printf(__VA_ARGS__);\
\#endif\
#endif
It is difficult to describe the intention,
which generally means that i predefine a macros idebug which to save some code.
If _ DEBUG flag is predefined, then print the output.
Or pretend nothing happened.
if we achieve it using a function ,it will look like this:
void idebug(...)
{
#ifdef _DEBUG
printf(...);
#endif
}
Suppose there is a program
int main()
{
int a = 10;
idebug("a:%d\n",a);
}
when we are in the debugging phase, we want a output by complier:
int main()
{
int a = 10;
printf("a:%d\n",a);
}
if we are in the release phase, we want a output by complier:
int main()
{
int a = 10;
}
Do it the other way:
#ifdef _DEBUG
# define idebug(...) printf(__VA_ARGS__)
#else
# define idebug(...) ((void)0)
#endif

Get a different value with macro every time it's used [duplicate]

I'm writing a bunch of related preprocessor macros, one of which generates labels which the other one jumps to. I use them in this fashion:
MAKE_FUNNY_JUMPING_LOOP(
MAKE_LABEL();
MAKE_LABEL();
)
I need some way to generate unique labels, one for each inner MAKE_LABEL call, with the preprocessor. I've tried using __LINE__, but since I call MAKE_LABEL inside another macro, they all have the same line and the labels collide.
What I'd like this to expand to is something like:
MAKE_FUNNY_JUMPING_LOOP(
my_cool_label_1: // from first inner macro
...
my_cool_label_2: // from second inner macro
...
)
Is there a way to generate hashes or auto-incrementing integers with the preprocessor?
If you're using GCC or MSVC, there is __COUNTER__.
Other than that, you could do something vomit-worthy, like:
#ifndef USED_1
#define USED_1
1
#else
#ifndef USED_2
#define USED_2
2
/* many many more */
#endif
#endif
I use this:
#define MERGE_(a,b) a##b
#define LABEL_(a) MERGE_(unique_name_, a)
#define UNIQUE_NAME LABEL_(__LINE__)
int main()
{
int UNIQUE_NAME = 1;
return 0;
}
... and get the following:
int main()
{
int unique_name_8 = 1;
return 0;
}
As others noted, __COUNTER__ is the easy but nonstandard way of doing this.
If you need extra portability, or for other cool preprocessor tricks, the Boost Preprocessor library (which works for C as well as C++) will work. For example, the following header file will output a unique label wherever it's included.
#include <boost/preprocessor/arithmetic/inc.hpp>
#include <boost/preprocessor/slot/slot.hpp>
#if !defined(UNIQUE_LABEL)
#define UNIQUE_LABEL
#define BOOST_PP_VALUE 1
#include BOOST_PP_ASSIGN_SLOT(1)
#undef BOOST_PP_VALUE
#else
#define BOOST_PP_VALUE BOOST_PP_INC(BOOST_PP_SLOT(1))
#include BOOST_PP_ASSIGN_SLOT(1)
#undef BOOST_PP_VALUE
#endif
BOOST_PP_CAT(my_cool_label_, BOOST_PP_SLOT(1)):
Sample:
int main(int argc, char *argv[]) {
#include "unique_label.h"
printf("%x\n", 1234);
#include "unique_label.h"
printf("%x\n", 1234);
#include "unique_label.h"
return 0;
}
preprocesses to
int main(int argc, char *argv[]) {
my_cool_label_1:
printf("%x\n", 1234);
my_cool_label_2:
printf("%x\n", 1234);
my_cool_label_3:
return 0;
}
I can't think of a way to automatically generate them but you could pass a parameter to MAKE_LABEL:
#define MAKE_LABEL(n) my_cool_label_##n:
Then...
MAKE_FUNNY_JUMPING_LOOP(
MAKE_LABEL(0);
MAKE_LABEL(1);
)
You could do this:
#define MAKE_LABEL() \
do { \
my_cool_label: \
/* some stuff */; \
goto my_cool_label; \
/* other stuff */; \
} while (0)
This keeps the scope of the label local, allowing any number of them inside the primary macro.
If you want the labels to be accessed more globally, it's not clear how your macro "MAKE_FUNNY_JUMPING_LOOP" references these labels. Can you explain?
It doesn't seem possible with a standard preprocessor, although you could fake it out by putting parameters within MAKE_LABEL or MAKE_FUNNY_JUMPING_LOOP, and use token pasting to create the label.
There's nothing preventing you from making your own preprocessing script that does the automatic increment for you. However, it won't be a standard C/C++ file in that case.
A list of commands available: http://www.cppreference.com/wiki/preprocessor/start

Disable multiline statements with c/c++ macro

Is it possible to disable chunks of code with c/c++ preprocessor depending on some definition, without instrumenting code with #ifdef #endif?
// if ENABLE_TEST_SONAR is not defined, test code will be eliminated by preprocessor
TEST_BEGIN(SONAR)
uint8_t sonar_range = get_sonar_measurement(i);
TEST_ASSERT(sonar_range < 300)
TEST_ASSERT(sonar_range > 100)
TEST_END
Functionally equivalent to something as follows:
#ifdef TEST_SONAR
serial_print("test_case sonar:\r\n");
uint8_t sonar_range = get_sonar_measurement(i);
serial_print(" test sonar_range < 300:%d\r\n", sonar_range < 300);
serial_print(" test sonar_range > 100:%d\r\n", sonar_range > 100);
#endif TEST_SONAR
Multiple lines can be disabled only with #ifdef or #if but single lines can be disabled with a macro. Note that multiple lines can be combined with \
#ifdef DOIT
#define MYMACRO(x) \
some code \
more code \
even more \
#else
#define MYMACRO(x)
#endif
Then when you call MYMACRO anplace that code will either be included or not based on whether DOIT is defined
That's the closest you can come and is used frequently for debugging code
EDIT: On a whim I tried the following and it seems to work (in MSVC++ and g++):
#define DOIT
#ifdef DOIT
#define MYMACRO(x) x
#else
#define MYMACRO(x)
#endif
void foo(int, int, int)
{
}
int main(int, char **)
{
int x = 7;
MYMACRO(
if (x)
return 27;
for (int i = 0; i < 10; ++i)
foo(1, 2, 3);
)
}
No, the only way to disable sections of codes effectively using preprocessing is by #ifdef #endif. Theoretically, you could use #if identifier, but it's better to stick to checking whether a variable is defined.
Another option (perhaps) is to use a preprocessing macro:
Edit:
Perhaps using plain functions and #ifdef might work better?
function test_function() {
/* Do whatever test */
}
#define TESTING_IDENTIFIER
#define TEST( i, f ) if ((i)) do { f } while (0)
Then, for each test, you define a unique identifier and call it by providing the identifier first and the function (with parenthesis) second.
TEST( TESTING_IDENTIFIER, test_function() );
Finally, f can be anything that's syntactically correct -- You don't have to create a function for every test, you can put the code inline.
I will anyway mention an obvious solution of
#define DO_TEST_SONAR
#ifdef DO_TEST_SONAR
#define TEST_SONAR if(true) {
#else
#define TEST_SONAR if(false) {
#endif
#define TEST_SONAR_END }
...
TEST_SONAR
code
TEST_SONAR_END
The code will still get compiled, not completely removed, but some smart compilers might optimize it out.
UPD: just tested and
#include <iostream>
using namespace std;
//#define DO_TEST_SONAR
#ifdef DO_TEST_SONAR
#define TEST_SONAR if(true) {
#else
#define TEST_SONAR if(false) {
#endif
#define TEST_SONAR_END }
int main() {
TEST_SONAR
cout << "abc" << endl;
TEST_SONAR_END
}
produces absolutely identical binaries with cout line commented out and non commented, so indeed the code is stripped. Using g++ 4.9.2 with -O2.

c++ force compiler to opt out some piece of code

I have a piece of code:
// some code, which only do sanity check
expensive checks
// sanity check end
Now how do I tell the compiler to force it to opt out
this piece? Basically it means when I compile with -O2 or
O3, I don't want it to be there...
Thanks!
You can accomplish this with a constant and a single if/def pair. This allows the code to still be compiled and checked for errors but omitted during optimization. This can prevent changes that might break the check code from going undetected.
#if defined(USE_EXPENSIVE_CHECKS) || defined(DEBUG)
#define USE_EXPENSIVE_CHECKS_VALUE true
#else
#define USE_EXPENSIVE_CHECKS_VALUE false
#endif
namespace {
const bool useExpensiveChecks = USE_EXPENSIVE_CHECKS_VALUE;
};
void function()
{
if(useExpensiveChecks == true)
{
// expensive checks
}
}
Instead of relying on the compiler to optimize the code out, you could pass the compiler an additional symbol definition only when you want the code to run:
// some code, which only do sanity check
#ifdef my_symbol
expensive checks
#endif
// sanity check end
Using macros and conditionals in the preprocessor is really the only way to avoid code being generated by the compiler.
So, here's how I would do it:
#ifdef NEED_EXPENSIVE_CHECKS
inline expensive_checking(params...)
{
... do expensive checking here ...
}
#else
inline expensive_checking(params...)
{
}
#endif
Then just call:
some code
expensive_checking(some_parameters...)
some other code
An empty inlined function will result in "no code" in any decent, modern compiler. Use -DNEED_EXPENSIVE_CHECKS in your debug build settings, and don't use that in release build.
I have also been known to use a combination of macro and function, such as this:
#ifdef NEED_EXPENSIVE_CHECKS
#define EXPENSIVE_CHECKS(stuff...) expensive_checks(__FILE__, __LINE__, stuff...)
inline expensive_checks(const char *file, int line, stuff ...)
{
if (some_checking)
{
cerr << "Error, some_checking failed at " << file << ":" << line << endl;
}
}
#else
#define EXPENSIVE_CHECKS(stuff...)
#endif
Now, you get information on which file and what line when something fails, which can be very useful if the checks are made in many places (and you can use __function__ or __pretty_function__ to get the function name as well, if you wish).
Obviously, the assert() macro will essentially do what my macro solution does, except it usually doesn't provide the filename and line-number.
Move your checks into a different function, then import cassert and write assert(expensive_check()). When you want to disable the checks, use #define NDEBUG before the inclusion of cassert.

C++ macro without spaces

I need a macro to expand to a c++ comment, is that possible?
I've got this:
#define SLASH(x,y) x y
#define OUT SLASH(/,/)
int main(int argc, char *argv[])
{
OUT << "text";
return 0;
}
And need to expand to this:
{
// << "text";
return 0;
}
I've also tried this:
#define SLASH(x) /x
#define OUT SLASH(/)
But the result is still the same:
int main(int argc, char *argv[])
{
/ / << "text";
return 0;
}
No it's not possible because in C++ comments are removed before macros are expanded.
(See 2.1 of the standard, comment removal happens in phase 3, macro expansion in phase 4.)
What about replacing it with a function object that does nothing instead?
static class NullOutput {
public:
template <typename T>
const NullOutput &operator<<(T arg) const {
return *this;
}
} NullOutputObj;
#define OUT NullOutputObj
The net result is that the object is removed from the code and replaced by inlined template expansions, that are then optimized out as they do nothing. Result is absolutely no code overhead.
As others mentioned there is no guaranteed way to define the kind of macro you are looking for. Other ways to achieve results that are similar to what you seem to be trying to achieve are wrapping your output statement in a conditional block or define a custom output stream that just discarded all output. The two approaches may even be combined so that behaviour could be switched by changing a single macro definition.
Comments are removed from the source code before the preprocessor runs. So you cannot do this.
an alternate to what you want to achieve would be this :
http://donjaffer.blogspot.in/2012/09/dprintf-debug-macro-in-c.html
#define DEBUG // comment if you do not want the debug statments to appear.
#ifdef DEBUG
#define DPRINTF(fmt, ...) \
do { printf("my_file: " fmt, ## __VA_ARGS__); } while (0)
#else
#define DPRINTF(fmt, ...) \
do { } while (0)
#endif
wherever you are trying to print the statements, instead of COUT << you can use
DPRINTF("Your text here\n");