d=[[5,3,2],[5,1,9],[6,8,3]]
I need to divide this nested list by '2'
Code which I tried.
m=[]
jj=2
for k,v in zip(d,jj):
m.append([k2/v2 for k2,v2 in zip(k,v)])
print(m)
So the output could be like below
d=[[2.5,1.5,1],[2.5,0.5,4.5],[3,4,1.5]
d=[[5,3,2],[5,1,9],[6,8,3]]
result = [[j/2 for j in i] for i in d]
print(result)
Related
I have a list like below and need to firs add items in each list and then multiply all results 2+4 = 6 , 3+ (-2)=1, 2+3+2=7, -7+1=-6 then 6*1*7*(-6) = -252 I know how to do it by accessing indexes and it works (as below) but I also need to do it in a way that it will work no matter how many sublist there is
nested_lst = [[2,4], [3,-2],[2,3,2], [-7,1]]
a= nested_lst[0][0] + nested_lst[0][1]
b= nested_lst[1][0] + nested_lst[1][1]
c= nested_lst[2][0] + nested_lst[2][1] + nested_lst[2][2]
d= nested_lst[3][0] + nested_lst[3][1]
def sum_then_product(list):
multip= a*b*c*d
return multip
print sum_then_product(nested_lst)
I have tried with for loop which gives me addition but I don't know how to perform here multiplication. I am new to it. Please, help
nested_lst = [[2,4], [3,-2],[2,3,2], [-7,1]]
for i in nested_lst:
print sum(i)
Is this what you are looking for?
nested_lst = [[2,4], [3,-2],[2,3,2], [-7,1]] # your list
output = 1 # this will generate your eventual output
for sublist in nested_lst:
sublst_out = 0
for x in sublist:
sublst_out += x # your addition of the sublist elements
output *= sublst_out # multiply the sublist-addition with the other sublists
print(output)
I want to count total number of '1's in binary format of a number which is in a list.
z = ['0b111000','0b1000011'] # z is a list
d = z.count('1')
print(d)
The output is 0.
Whereas the required output should be in the form of [3,3]
which is number of ones in every element that Z is containing :
Here it is :
z=['0b111000','0b1000011']
finalData = []
for word in z:
finalData.append(word.count('1'))
print(finalData)
The problem with your code was you were trying to use count() method on list type and it is used for string. You first need to get the string from the list and then use count() method on it.
Hope this helps :)
z = ['0b111000','0b1000011']
d = z.count('1')
This attempts to find the number of times the string '1' is in z. This obviously returns 0 since z contains '0b111000' and '0b1000011'.
You should iterate over every string in z and count the numbers of '1' in every string:
z = ['0b111000','0b1000011']
output = [string.count('1') for string in z]
print(output)
# [3, 3]
list.count(x) will count the number of occurrences such that it only counts the element if it is equal to x.
Use list comprehension to loop through each string and then count the number of 1s. Such as:
z = ['0b111000','0b1000011']
d = [x.count("1") for x in z]
print(d)
This will output:
[3, 3]
I have this list: l = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20] and I would like to iterate on it, printing something like
0: [1,2,3,4]
1: [2,3,4,5]
2: [3,4,5,6]
...
n: [17,18,19,20]
So far I made this code to print 5 elements at a time, but the last iteration prints 3:
for index, item in enumerate(l):
if index == 0 or index == 1 or index == 2:
continue
print index, l[index - 3:index + 2]
How can I solve this?
You're on the right track with your list slices. Here's a tweak to make it easier:
sub_len = 4
for i in range(len(mylist) - sub_len + 1):
print l[i:i + sub_len]
Where sub_len is the desired length of the slices you print.
demo
trying to write this code to see how many times the numbers in list 1 appear in the list two, can use a nested for or while loop but I came up with this it doesn't work. I don't want to use count.
list1 = [4,7,2]
list2 = [2,3,4,2,5,6,3,2,6,7,3,4]
def compare(list1, list2):
freq = ([i for i in list1 if i == num])
return
print('The number 4 occurs in list2', freq, 'times')
print('The number 7 occurs in list2', freq, 'times')
print('The number 2 occurs in list2', freq, 'times')
I'm not completely sure that I understand the question,
but this code seems to work, though if it may be slow if you need it for an interactive program.
Hope this helps!
list1 = [4,7,2]
list2 = [2,3,4,2,5,6,3,2,6,7,3,4]
occurrences = [0,0,0]
for i in range(len(list1)):
for j in list2:
if list1[i] == j:
occurrences[i]+=1
print occurrences
try this:
list1 = [4,7,2]
list2 = [2,3,4,2,5,6,3,2,6,7,3,4]
occurrences = [0,0,0]
for i in range(len(list1)):
for j in list2:
if list1[i] == j:
occurrences[i]+=1
print occurrences
i want to calculte the specfic numbers of words from the given sentence...words are alredy save in my dictonary and sentence is will be input from user.....
Here is my code.
from collections import Counter
Find_word= raw_input('Write Sentence:')
wordTosearch=['is', 'am']
sentence= Find_word.split()
cnt = Counter(sentence)
for k in sentence:
if k in wordTosearch:
print k, wordTosearch[k]
if cnt[wordTosearch]>1:
print "aggresive"
else:
print "Not agressive"
from collections import Counter
Find_word= raw_input('Write Sentence:')
sentence= Find_word.split()
cnt = Counter(sentence)
wordTosearch=['is', 'am']
for k in wordTosearch:
print k, cnt[k]
if all( cnt[x] > 1 for x in wordTosearch ):
print "aggresive"
else:
print "Not agressive"
I dont know what the bottom part should do though.
wordTosearch is a list of words.
The following is iterating through that list of words:
if k in wordTosearch:
print k, wordTosearch[k] # <----
where k is a word, and wordTosearch[k] is the attempt to access a list value by a string key which gives you "TypeError: list indices must be integers, not str".
You can not access list values by string indices as Python lists are "numbered" sequences