I am trying to search in a collection by a word. So I have record like this:
{
"_id" : ObjectId("5ec2e9d0543e75377e9f3981"),
"text" : "işlemci",
"question" : ObjectId("5ec2c3f36700e13311592917"),
"createdAt" : ISODate("2020-05-18T20:02:24.641+0000"),
"updatedAt" : ISODate("2020-05-18T20:02:24.641+0000"),
"__v" : NumberInt(0)
}
And i am using following query to find that entry:
var answer = "islemci"
const answerRegex = new RegExp(answer, 'i');
const answers = await Answer
.find({
text: answerRegex,
question: questionId
})
.populate('question', 'text -_id')
.select('text question');
It doesn't find any records, because we passed "islemci" value to our answer variable. If i try with "işlemci" it finds the entry.
How can i ignore the Turkish characters when i am searching?
Turkish characters: https://en.wikipedia.org/wiki/Wikipedia:Turkish_characters
Language-specific rules for strings comparison can be handled using collation. Basically in your case you can use en_US for locale and specify strength 1 which will ignore any non-english characters.
1 Primary level of comparison. Collation performs comparisons of the base characters only, ignoring other differences such as diacritics and case.
In mongoose collation can be specified on the schema level:
const yourSchema = new Schema(
{
text: String,
question: Schema.Types.ObjectId,
createdAt: Date,
updatedAt: Date,
},
{ collation: { locale: 'en_US', strength: 1 } }
);
Whenever you call .find like this:
let doc = await Model.find({ text: 'islemci' });
mongoose will run following query:
db.col.find({ text: 'islemci' }, { collation: { locale: 'tr', strength: 1 }, projection: {} })
It works for equality comparisons but unfortunately is not applicable for $regex:
The $regex implementation is not collation-aware
Related
it's my first post.
I work to Quasar (Vue.js)
I have list of jobs, and in this list, i have words with special caractere.
Ex :
[ ...{ "libelle": "Agent hôtelier" },{"libelle": "Agent spécialisé / Agente spécialisée des écoles maternelles -ASEM-"},{ "libelle": "Agriculteur / Agricultrice" },{ "libelle": "Aide aux personnes âgées" },{ "libelle": "Aide de cuisine" },...]
And on "input" i would like to search "Agent spécialisé" but i want to write "agent specialise" (without special caractere) or the initial name, i want to write both and autocomplete my "input".
I just don't fin the solution for add to my filter code ...
My input :
<q-select
filled
v-model="model"
use-input
hide-selected
fill-input
input-debounce="0"
:options="options"
hint="Votre métier"
style="width: 250px; padding-bottom: 32px"
#filter="filterFn"
>
</q-select>
</div>
My code :
export default {
props: ['data'],
data() {
return {
jobList: json,
model: '',
options: [],
stringOptions: []
}
},
methods: {
jsonJobsCall(e) {
this.stringOptions = []
json.forEach(res => {
this.stringOptions.push(res.libelle)
})
},
filterFn(val, update) {
if (val === '') {
update(() => {
this.jsonJobsCall(val)
this.options = this.stringOptions
})
return
}
update(() => {
const regex = /é/i
const needle = val.toLowerCase()
this.jsonJobsCall(val)
this.options = this.stringOptions.filter(
v => v.replace(regex, 'e').toLowerCase().indexOf(needle) > -1
)
})
},
}
}
To sum up : i need filter for write with or witouth special caractere in my input for found in my list the job which can contain a special character.
I hope i was clear, ask your questions if i haven't been.
Thanks you very much.
I am not sure if its work for you but you can use regex to create valid filter for your need. For example, when there is "e" letter you want to check "e" or "é" (If I understand correctly)
//Lets say we want to match "Agent spécialisé" with the given search text
let searchText = "Agent spe";
// Lets create a character map for matching characters
let characterMap = {
e: ['e', 'é'],
a: ['a', '#']
}
// Replacing special characters with a regex part which contains all equivelant characters
// !Remember replaceAll depricated
Object.keys(characterMap).forEach((key) => {
let replaceReg = new RegExp(`${key}`, "g")
searchText = searchText.replace(replaceReg, `[${characterMap[key].join("|")}]`);
})
// Here we create a regex to match
let reg = new RegExp(searchText + ".*")
console.log("Agent spécialisé".match(reg) != null);
Another approach could be the reverse of this. You can normalize "Agent spécialisé". (I mean replace all é with normal e with a regex like above) and store in the object along with the original text. But search on this normalized string instead of original.
I need to perform a case-insensitive find.
But I am getting a case-insensitive "like" returned, where things that are "like" my string match
I can overcome this in the console or tool by adding ^ and $ - however I cannot figure out how to do that in code, when Im passing a var into the query.
module.exports.getCollege = function( name, callback ) {
const query = [
{
$match: {
'name': { $regex: name, $options: 'i' }
}
},
{
$project: {
'address': 1,
'name': 1
}
}
];
College.aggregate( query ).exec( callback );
}
This returns
University of Michigan (object),
University of Michigan Flint campus (object)
I just want University of Michigan (object)
How do I get a LITERAL match, but case insensitive???
+++++++++++++++++++++++++++
Response to D. SM - "use collation..."
Returns correct because string is correct..
However - case insensitive not working
How do I get a LITERAL match, but case insensitive???
Specify collation in your query and use $eq instead of $regex.
I am so sorry, but after one day researching and trying all different combinations and npm packages, I am still not sure how to deal with the following task.
Setup:
MongoDB 2.6
Node.JS with Mongoose 4
I have a schema like so:
var trackingSchema = mongoose.Schema({
tracking_number: String,
zip_code: String,
courier: String,
user_id: Number,
created: { type: Date, default: Date.now },
international_shipment: { type: Boolean, default: false },
delivery_info: {
recipient: String,
street: String,
city: String
}
});
Now user gives me a search string, a rather an array of strings, which will be substrings of what I want to search:
var search = ['15323', 'julian', 'administ'];
Now I want to find those documents, where any of the fields tracking_number, zip_code, or these fields in delivery_info contain my search elements.
How should I do that? I get that there are indexes, but I probably need a compound index, or maybe a text index? And for search, I then can use RegEx, or the $text $search syntax?
The problem is that I have several strings to look for (my search), and several fields to look in. And due to one of those aspects, every approach failed for me at some point.
Your use case is a good fit for text search.
Define a text index on your schema over the searchable fields:
trackingSchema.index({
tracking_number: 'text',
zip_code: 'text',
'delivery_info.recipient': 'text',
'delivery_info.street': 'text',
'delivery_info.city': 'text'
}, {name: 'search'});
Join your search terms into a single string and execute the search using the $text query operator:
var search = ['15232', 'julian'];
Test.find({$text: {$search: search.join(' ')}}, function(err, docs) {...});
Even though this passes all your search values as a single string, this still performs a logical OR search of the values.
Why just dont try
var trackingSchema = mongoose.Schema({
tracking_number: String,
zip_code: String,
courier: String,
user_id: Number,
created: { type: Date, default: Date.now },
international_shipment: { type: Boolean, default: false },
delivery_info: {
recipient: String,
street: String,
city: String
}
});
var Tracking = mongoose.model('Tracking', trackingSchema );
var search = [ "word1", "word2", ...]
var results = []
for(var i=0; i<search.length; i++){
Tracking.find({$or : [
{ tracking_number : search[i]},
{zip_code: search[i]},
{courier: search[i]},
{delivery_info.recipient: search[i]},
{delivery_info.street: search[i]},
{delivery_info.city: search[i]}]
}).map(function(tracking){
//it will push every unique result to variable results
if(results.indexOf(tracking)<0) results.push(tracking);
});
Okay, I came up with this.
My schema now has an extra field search with an array of all my searchable fields:
var trackingSchema = mongoose.Schema({
...
search: [String]
});
With a pre-save hook, I populate this field:
trackingSchema.pre('save', function(next) {
this.search = [ this.tracking_number ];
var searchIfAvailable = [
this.zip_code,
this.delivery_info.recipient,
this.delivery_info.street,
this.delivery_info.city
];
for (var i = 0; i < searchIfAvailable.length; i++) {
if (!validator.isNull(searchIfAvailable[i])) {
this.search.push(searchIfAvailable[i].toLowerCase());
}
}
next();
});
In the hope of improving performance, I also index that field (also the user_id as I limit search results by that):
trackingSchema.index({ search: 1 });
trackingSchema.index({ user_id: 1 });
Now, when searching I first list all substrings I want to look for in an array:
var andArray = [];
var searchTerms = searchRequest.split(" ");
searchTerms.forEach(function(searchTerm) {
andArray.push({
search: { $regex: searchTerm, $options: 'i'
}
});
});
I use this array in my find() and chain it with an $and:
Tracking.
find({ $and: andArray }).
where('user_id').equals(userId).
limit(pageSize).
skip(pageSize * page).
exec(function(err, docs) {
// hooray!
});
This works.
I have a field of phone numbers where a random variety of separators have been used, such as:
932-555-1515
951.555.1255
(952) 555-1414
I would like to go through each field that already exists and remove the non numeric characters.
Is that possible?
Whether or not it gets stored as an integer or as a string of numbers, I don't care either way. It will only be used for display purposes.
You'll have to iterate over all your docs in code and use a regex replace to clean up the strings.
Here's how you'd do it in the mongo shell for a test collection with a phone field that needs to be cleaned up.
db.test.find().forEach(function(doc) {
doc.phone = doc.phone.replace(/[^0-9]/g, '');
db.test.save(doc);
});
Based on the previous example by #JohnnyHK, I added regex also to the find query:
/*
MongoDB: Find by regular expression and run regex replace on results
*/
db.test.find({"url": { $regex: 'http:\/\/' }}).forEach(function(doc) {
doc.url = doc.url.replace(/http:\/\/www\.url\.com/g, 'http://another.url.com');
db.test.save(doc);
});
Starting in Mongo 4.4, the $function aggregation operator allows applying a custom javascript function to implement behaviour not supported by the MongoDB Query Language.
And coupled with improvements made to db.collection.update() in Mongo 4.2 that can accept an aggregation pipeline, allowing the update of a field based on its own value,
We can manipulate and update a field in ways the language doesn't easily permit and avoid an inefficient find/foreach pattern:
// { "x" : "932-555-1515", "y" : 3 }
// { "x" : "951.555.1255", "y" : 7 }
// { "x" : "(952) 555-1414", "y" : 6 }
db.collection.updateMany(
{ "x": { $regex: /[^0-9]/g } },
[{ $set:
{ "x":
{ $function: {
body: function(x) { return x.replace(/[^0-9]/g, ''); },
args: ["$x"],
lang: "js"
}}
}
}
])
// { "x" : "9325551515", "y" : 3 }
// { "x" : "9515551255", "y" : 7 }
// { "x" : "9525551414", "y" : 6 }
The update consist of:
a match query { "x": { $regex: /[^0-9]/g } }, filtering documents to update (in our case any document that contains non-numeric characters in the field we're interested on updating).
an update aggreation pipeline [ { $set: { active: { $eq: [ "$a", "Hello" ] } } } ] (note the squared brackets signifying the use of an aggregation pipeline). $set is a new aggregation operator and an alias for $addFields.
$function takes 3 parameters:
body, which is the function to apply, whose parameter is the string to modify. The function here simply consists in replacing characters matching the regex with empty characters.
args, which contains the fields from the record that the body function takes as parameter. In our case, "$x".
lang, which is the language in which the body function is written. Only js is currently available.
in mongodb version 4.2 you have regexFind project operator which can be used together with substr inside an aggregation without looping through all the documents in client
var thename = 'Andrew';
db.collection.find({'name':thename});
How do I query case insensitive? I want to find result even if "andrew";
Chris Fulstow's solution will work (+1), however, it may not be efficient, especially if your collection is very large. Non-rooted regular expressions (those not beginning with ^, which anchors the regular expression to the start of the string), and those using the i flag for case insensitivity will not use indexes, even if they exist.
An alternative option you might consider is to denormalize your data to store a lower-case version of the name field, for instance as name_lower. You can then query that efficiently (especially if it is indexed) for case-insensitive exact matches like:
db.collection.find({"name_lower": thename.toLowerCase()})
Or with a prefix match (a rooted regular expression) as:
db.collection.find( {"name_lower":
{ $regex: new RegExp("^" + thename.toLowerCase(), "i") } }
);
Both of these queries will use an index on name_lower.
You'd need to use a case-insensitive regular expression for this one, e.g.
db.collection.find( { "name" : { $regex : /Andrew/i } } );
To use the regex pattern from your thename variable, construct a new RegExp object:
var thename = "Andrew";
db.collection.find( { "name" : { $regex : new RegExp(thename, "i") } } );
Update: For exact match, you should use the regex "name": /^Andrew$/i. Thanks to Yannick L.
I have solved it like this.
var thename = 'Andrew';
db.collection.find({'name': {'$regex': thename,$options:'i'}});
If you want to query for case-insensitive and exact, then you can go like this.
var thename = '^Andrew$';
db.collection.find({'name': {'$regex': thename,$options:'i'}});
With Mongoose (and Node), this worked:
User.find({ email: /^name#company.com$/i })
User.find({ email: new RegExp(`^${emailVariable}$`, 'i') })
In MongoDB, this worked:
db.users.find({ email: { $regex: /^name#company.com$/i }})
Both lines are case-insensitive. The email in the DB could be NaMe#CompanY.Com and both lines will still find the object in the DB.
Likewise, we could use /^NaMe#CompanY.Com$/i and it would still find email: name#company.com in the DB.
MongoDB 3.4 now includes the ability to make a true case-insensitive index, which will dramtically increase the speed of case insensitive lookups on large datasets. It is made by specifying a collation with a strength of 2.
Probably the easiest way to do it is to set a collation on the database. Then all queries inherit that collation and will use it:
db.createCollection("cities", { collation: { locale: 'en_US', strength: 2 } } )
db.names.createIndex( { city: 1 } ) // inherits the default collation
You can also do it like this:
db.myCollection.createIndex({city: 1}, {collation: {locale: "en", strength: 2}});
And use it like this:
db.myCollection.find({city: "new york"}).collation({locale: "en", strength: 2});
This will return cities named "new york", "New York", "New york", etc.
For more info: https://jira.mongodb.org/browse/SERVER-90
... with mongoose on NodeJS that query:
const countryName = req.params.country;
{ 'country': new RegExp(`^${countryName}$`, 'i') };
or
const countryName = req.params.country;
{ 'country': { $regex: new RegExp(`^${countryName}$`), $options: 'i' } };
// ^australia$
or
const countryName = req.params.country;
{ 'country': { $regex: new RegExp(`^${countryName}$`, 'i') } };
// ^turkey$
A full code example in Javascript, NodeJS with Mongoose ORM on MongoDB
// get all customers that given country name
app.get('/customers/country/:countryName', (req, res) => {
//res.send(`Got a GET request at /customer/country/${req.params.countryName}`);
const countryName = req.params.countryName;
// using Regular Expression (case intensitive and equal): ^australia$
// const query = { 'country': new RegExp(`^${countryName}$`, 'i') };
// const query = { 'country': { $regex: new RegExp(`^${countryName}$`, 'i') } };
const query = { 'country': { $regex: new RegExp(`^${countryName}$`), $options: 'i' } };
Customer.find(query).sort({ name: 'asc' })
.then(customers => {
res.json(customers);
})
.catch(error => {
// error..
res.send(error.message);
});
});
To find case Insensitive string use this,
var thename = "Andrew";
db.collection.find({"name":/^thename$/i})
I just solved this problem a few hours ago.
var thename = 'Andrew'
db.collection.find({ $text: { $search: thename } });
Case sensitivity and diacritic sensitivity are set to false by default when doing queries this way.
You can even expand upon this by selecting on the fields you need from Andrew's user object by doing it this way:
db.collection.find({ $text: { $search: thename } }).select('age height weight');
Reference: https://docs.mongodb.org/manual/reference/operator/query/text/#text
You can use Case Insensitive Indexes:
The following example creates a collection with no default collation, then adds an index on the name field with a case insensitive collation. International Components for Unicode
/*
* strength: CollationStrength.Secondary
* Secondary level of comparison. Collation performs comparisons up to secondary * differences, such as diacritics. That is, collation performs comparisons of
* base characters (primary differences) and diacritics (secondary differences). * Differences between base characters takes precedence over secondary
* differences.
*/
db.users.createIndex( { name: 1 }, collation: { locale: 'tr', strength: 2 } } )
To use the index, queries must specify the same collation.
db.users.insert( [ { name: "Oğuz" },
{ name: "oğuz" },
{ name: "OĞUZ" } ] )
// does not use index, finds one result
db.users.find( { name: "oğuz" } )
// uses the index, finds three results
db.users.find( { name: "oğuz" } ).collation( { locale: 'tr', strength: 2 } )
// does not use the index, finds three results (different strength)
db.users.find( { name: "oğuz" } ).collation( { locale: 'tr', strength: 1 } )
or you can create a collection with default collation:
db.createCollection("users", { collation: { locale: 'tr', strength: 2 } } )
db.users.createIndex( { name : 1 } ) // inherits the default collation
This will work perfectly
db.collection.find({ song_Name: { '$regex': searchParam, $options: 'i' } })
Just have to add in your regex $options: 'i' where i is case-insensitive.
To find case-insensitive literals string:
Using regex (recommended)
db.collection.find({
name: {
$regex: new RegExp('^' + name.replace(/[-\/\\^$*+?.()|[\]{}]/g, '\\$&') + '$', 'i')
}
});
Using lower-case index (faster)
db.collection.find({
name_lower: name.toLowerCase()
});
Regular expressions are slower than literal string matching. However, an additional lowercase field will increase your code complexity. When in doubt, use regular expressions. I would suggest to only use an explicitly lower-case field if it can replace your field, that is, you don't care about the case in the first place.
Note that you will need to escape the name prior to regex. If you want user-input wildcards, prefer appending .replace(/%/g, '.*') after escaping so that you can match "a%" to find all names starting with 'a'.
Regex queries will be slower than index based queries.
You can create an index with specific collation as below
db.collection.createIndex({field:1},{collation: {locale:'en',strength:2}},{background : true});
The above query will create an index that ignores the case of the string. The collation needs to be specified with each query so it uses the case insensitive index.
Query
db.collection.find({field:'value'}).collation({locale:'en',strength:2});
Note - if you don't specify the collation with each query, query will not use the new index.
Refer to the mongodb doc here for more info - https://docs.mongodb.com/manual/core/index-case-insensitive/
The following query will find the documents with required string insensitively and with global occurrence also
db.collection.find({name:{
$regex: new RegExp(thename, "ig")
}
},function(err, doc) {
//Your code here...
});
An easy way would be to use $toLower as below.
db.users.aggregate([
{
$project: {
name: { $toLower: "$name" }
}
},
{
$match: {
name: the_name_to_search
}
}
])