Iterate though array of int by prime numbers at C++ - c++

Question

I leave the complete code so that you can understand the context.
My problem is on line 53 (it says "HERE HERE...")...
The purpose of the code is to decompose a number(n) dividing it by prime numbers and printing at all in a chart.
Basically the problem is how to iterate through an int array by prime numbers.
I hope find help...
Please let me know any feedback
#include <iostream>
#include <math.h>
using namespace std;
int main (){
char slot;
int primo, div = 0;
int m;
//Ask to user, the size(slot) of our Array (memory[])
cout << "Escoga la memoria que mas se acomode a su necesidad y RAM: \t\n"
<< " A) 512 slots\n"
<< " B) 128 slots\n"
<< " C) 64 slots\n"
<< " > ";
cin >> slot;
if (slot == 'a' || 'A')
{
m = 512;
}
if (slot == 'b' || 'B')
{
m = 128;
}
if (slot == 'c' || 'C')
{
m = 64;
}
int memory[m];
// Storage in Array memory all prime numbers between 1 and m.
for (int i = 1; i <= m; i++)
{
primo = 0;
for (div = 2; div < i - 1 && primo == 0; div++)
{
if (i % div == 0) primo = 1;
}
if (primo == 0)
memory[i] = i;
}
//Ask to user, for give a number.
//n = The number that we gonna descompose arithmetically
cout << "Inserte un numero: ";
cin >> n;
cout << " | " << n << "\n";
<< "-------\n";
//HERE HERE HERE
//Iterate through memory [] printing the descompose of n
for ("HERE I NEED ITERATE FROM" memory[2] "UNTIL" memory[63])
{
do
{
n /= j;
cout << " " << j << " | " << n << "\n";
}while((n % j) == 0);
}
}

Answer 1

#include <array>
#include <iostream>
const int SIZE = 10;
int main()
{
int m = 8;
std::array<int, SIZE> arr{1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
for (auto i : arr) { // How to iterate all elements of std::array
std::cout << i << ' ';
}
std::cout << '\n';
// Another way to do the same thing (print all elements)
std::copy(arr.begin(), arr.end(), std::ostream_iterator<int>(std::cout, " "));
// Getting to your actual question
if (m < arr.size()) {
for (int i = 2; i < m; ++i) {
std::cout << arr[i] << ' ';
}
std::cout << '\n';
}
}