multiplication of random numbers different from zero - c++

Question

I have a code that generates 10 random numbers and I need to calculate the sum and product of the non-zero numbers and display which numbers have been multiplied. I already have most of the code but I have no idea how to multiply numbers that are nonzero and then display them. Can someone help me?
#include <iostream>
#include <cstdlib>
#include <ctime>
#include <windows.h>
using namespace std;
int main()
{
cout << "draws 10 numbers:" << endl;
Sleep(1000);
cout << endl;
srand(time(0));
int sum=0;
int product=1;
for(int i=0, value=0; i<10; i++, sum+=value, product*=value)
{
value = rand()%10+0;
Sleep(1000);
cout << value << endl;
}
Sleep(1000);
cout << "the sum is " << sum <<endl;
cout << "the product is " << product <<endl;
return 0;
}

Answer 1

To start, it is easier to read and understand if we move the addition and multiplication out of the for loop header.
int sum = 0;
int value = 1;
for(int i = 0; i < 10; i++)
{
int value = rand() % 10;
sum += value;
product *= value;
std::cout << value << std::::endl;
}
Next, we only want to do the multiplication if the value is not equal 0.
int sum = 0;
int value = 1;
for(int i = 0; i < 10; i++)
{
int value = rand() % 10;
sum += value;
if(value != 0)
{
product *= value;
}
std::cout << value << std::::endl;
}
So the whole program looks like this.
#include <iostream>
#include <cstdlib>
#include <ctime>
int main()
{
std::cout << "draws 10 numbers:" << std::endl;
srand(time(0));
int sum = 0;
int product = 1;
int multiplied = 0;
for(int i = 0; i < 10; i++)
{
int value = rand() % 10;
sum += value;
if(value != 0)
{
product *= value;
multiplied += 1;
}
std::cout << value << " ";
}
std::cout << std::endl;
std::cout << "the sum is " << sum << std::endl;
std::cout << "the product is " << product << std::endl;
std::cout << "numbers multiplied is " << multiplied << std::endl;
return EXIT_SUCCESS;
}