I have a text in which I want to get only the hexadecimal codes.
Like: "thisissometextthisistext\x64\x6f\x6e\x74\x74\x72\x61\x6e\x73\x6c\x61\x74\x65somemoretextoverhere"
It's possible to get the hex codes with \x..
But it doesn't seems I can do something like (^\x..) to select everything but the hex codes.
Any workarounds?
You may use a (?s)((?:\\x[a-fA-F0-9]{2})+)|. regex (that will match and capture into Group 1 any 1+ sequences of hex values OR will just match any other char including a line break char) and replace with a conditional replacement pattern (?{1}$1\n:) (that will reinsert the hex value chain or will replace the match with an empty string):
Find What: (?s)((?:\\x[a-fA-F0-9]{2})+)|.
Replace With: (?{1}$1\n:)
Regex Details:
(?s) - same as . matches newline option ON
((?:\\x[a-fA-F0-9]{2})+) - Group 1 capturing one or more sequences of
\\x - a \\x
[a-fA-F0-9]{2} - 2 letters from a to f or digits
| - or
. - any single char.
Replacement pattern:
(?{1} - if Group 1 matches:
$1\n - replace with its contents + a newline
: - else replace with an empty string
) - end of the replacement pattern.
try ^.*?((\\x[a-f0-9]{2})+).*$ and replace with $1
and it should just leave the hex code
then after replace
If you are already able to find the hexcodes with your regex, couldn't you just use that information to delete all of the hexcodes from the string (or from a clone of the string if you need to preserve the original) and you would be left with all text except for hexcodes.
^ acts as a negation token only inside (and at the beginning) of a character class, you can't use it to negate substrings of several characters.
To select all that isn't \xhh you can use this pattern:
\G(?:\\x[a-f0-9]{2})*+\K(?=.|\n)[^\\]*(?:\\(?!x[a-f0-9]{2})[^\\]*)*
it matches the \xhhs first and removes them from the match using the \K feature (that removes all on the left). The other part of the pattern [^\\]*(?:\\(?!x[a-f0-9]{2})[^\\]*)* matches all that isn't a \xhh. Since this subpattern can match the empty string at the end of the string, I added the lookahead (?=.|\n) to ensure there's at least one character.
\G forces all matches to be contigous. In other words it matches the position at the end of the previous match.
Related
So I am trying to make a regex match for strings of the form:
"catalog.schema.'tablename'" .
The output I am looking for is just catalog.schema.'tablename' leaving out the quotes at the end position.
Can anyone help me out
I tried to do it with the expression
/(?!^|.$)+[^\s]/ which leaves out the end quotes but matches each character.
So I modified it to /(?!^|.$)+[^\s]+/g . This matches the whole sentence but doesn't ignore the end quote.
Depends on the data arround your string and quotationmarks may be within the string.
Why not just this: "(.*?)"
https://regex101.com/r/oaS8o0/1
To answer the question in the title you might simply use:
^.(.*)?.$
https://regex101.com/r/FxJgtW/1
You can just use
(?<=.).+(?=.)
Or, if you cannot use lookbehind:
(?!^).+(?!$)
See the regex demo #1 and regex demo #2.
Since . matches any char other than line break chars, the patterns just match any strings without their start and end chars.
If you don't want to match the first and the last character, you can just use a capture group instead of lookarounds and use the group 1 value.
The first . matches the first of (any) characters, the (.+) is a capture group that matches 1 or more characters, and the . at the end matches the last character of the string.
.(.+).
Regex demo
Or to get the text between the double quotes at the start and the end of the string using a negated character class and a capture group:
^"([^"]+)"$
Regex demo
I've a list below:
7080508136242611718:7080508978035787525:7549dda86ba9af19:31050:install_id=7080508978035787525; store-country-code=us; store-idc=useast5; ttreq=1$fd2f36282a10633c5638a02cc54c19ff13f60755; passport_csrf_token=13bf74c4e5fe04307f0a99de9aed53f9; passport_csrf_token_default=13bf74c4e5fe04307f0a99de9aed53f9; odin_tt=11ed1b48fba2d7a9fe3d86929b3d52cebbad0ca7f7dbd127e220cfb3be279621ba04487517b536050a6ded9fbe50e300cd11615e2e9551523478e5484896a9dda800e55e428842872fcf862e8c57d439:1648559503:351451268482810:3f:49:8c:b7:8c:cb:c5379d41-6cf3-4152-9d48-7aa45f7f611c:79375640-197c-4aaa-86cf-4ef8e7238be2:1:AgICAw0AFockF-RPsNA-7qeIMtk5-CKdkW2eP4TZYMDY7A
7080507996291827206:7080508977079666438:6742591cc0d20580:31050:install_id=7080508977079666438; store-country-code=us; store-idc=useast5; ttreq=1$a119611bfe79541b0b4c029fe910b6507123eec2; passport_csrf_token=fb42bbd472462c17f45acb531deb057a; passport_csrf_token_default=fb42bbd472462c17f45acb531deb057a; odin_tt=6c3b06ff01fd67f42e3dccb60a1e69ca67cb8654f49662017acc209f7176517bcd13a374311f7a1b3538e6407fb237267abf43578d3180d8c834e7df886fa4377a9b950dbb6ff146e3fabf37158dcfa8:1648559508:351451233766930:dd:9e:82:59:5f:7f:596da881-89e8-4f60-b644-5fef23f0a422:f04adc87-56de-4191-a25f-843bec1d5818:1:AgICAw0AFockF-RPsNA-7qeIMtk5-CKdsYPWv4TZYMDY7A
7080509102451394054:7080509820378072837:e36dc9aceecfc1cc:31050:install_id=7080509820378072837; store-country-code=us; store-idc=useast5; ttreq=1$d94700921d5ee2b21992910a2a4e84dd0ade1ec8; passport_csrf_token=2d4f4eca772dbfcbb37548ff02da3166; passport_csrf_token_default=2d4f4eca772dbfcbb37548ff02da3166; odin_tt=53d6999ebe29c0d5144a9669331ce3307a290891370914dabadbfa0520114e6e76b9103c9a6db5476e139251ee478f3a305577a89e3fa07288b7aca00774d3fccbd03566687dbcfdce31700065295939:1648559700:351451299637010:71:de:41:2b:ad:b4:1eba1ae9-3216-40e1-be7f-00303e524c27:2713cbd3-7a4f-493e-b76f-ac6d56ab8045:5:AgMNAgIAhyQWF-RPsNA-7qeIMtk5-CKcsBcWP4TZYMDY7w
7080509086894851590:7080509909225604870:98be64e38551984d:31050:install_id=7080509909225604870; store-country-code=us; store-idc=useast5; ttreq=1$05929375d8605739d8ebdbb5ce15eb406da5c467; passport_csrf_token=c95c71ad206a1d371e5b67505ae25be8; passport_csrf_token_default=c95c71ad206a1d371e5b67505ae25be8; odin_tt=6ddaa02f6133e61a4c591ef2a872f0ec2339d8b6a3fc480575fe279b13ded615e1fa7de979e18565f3ac8b8229a19a98bdf79aa1804071dcc025e1a4cd5314522cf40a62ca961770baea1d5d653d6d64:1648559720:351451292934660:9d:cf:c3:92:f6:f5:787dfb42-f4bf-43fa-9c64-ded19a1b1660:366c3024-217d-4f85-90dd-d95a0fd3e296:4:AgICAw0AFockF-RPsNA-7qeIMtk5-CKcs7bUP4TZYMDY7w
7080509183397299718:7080509974838085382:f39db5d314071713:31050:install_id=7080509974838085382; store-country-code=us; store-idc=useast5; ttreq=1$561ee2083cb13f0849a9f09e7f89edfe08c7ce6c; passport_csrf_token=721a8fee6f4f97c16ed1923ad3bbc72d; passport_csrf_token_default=721a8fee6f4f97c16ed1923ad3bbc72d;
I'd like to extract first two options aka below:
7080508136242611718:7080508978035787525
7080507996291827206:7080508977079666438
7080509102451394054:7080509820378072837
7080509086894851590:7080509909225604870
7080509183397299718:7080509974838085382
I've tried: *.: but its remove the reset of text. and keeps only first.
I've tried ^.*[0-9]+.*$ to get the second one. but no success.
Hopefully somebody can help me with accurate regex.
Thank you in advance.
This pattern *.: by itself is not a valid regex, and this pattern ^.*[0-9]+.*$ matches the whole string with at least a single digit.
If you want to match the digits and : you could make use of \K to forget what is matched so far and then match the rest of the line.
In the replacement use an empty string.
^\d+:\d+\K.*
^ Start of string
\d+:\d+ Match 1+ digits with : in between
\K.* Clear the current match, and match the rest of the line
Regex demo
^[^:]*:[^:]*\K.*
When matching things with delimiters I will use a negated character set to match the contents. In this case, the delimiter is a colon, so I want to match everything that isn't a colon until there's a colon. Then I want to match everything that isn't a colon. This will match everything up until the second colon. Because I want to keep what I just matched, I am using .* after \K, which resets the match at that point and matches everything else.
That pattern can be replaced with nothing, and the result is the first two columns of each line left.
You can use
Find: ^(\d+:\d+).*
Replace: $1
See this regex demo online.
The ^(\d+:\d+).* regex matches and captures into Group 1 one or more digits + : + one or more digits (with (\d+:\d+)) at the beginning of a line (^) and then matches the rest of the line (with .*).
The $1 replacement replaces the match with the Group 1 value.
See the demo and settings screenshot:
As an alternative, if there are chars other than digits you can also use
^([^:\v]+:[^:\v]+).*
where [^:\v]+ matches one or more chars other than a comma and any vertical whitespace.
I am working with ToolsVersion="3.5".
I wanted to match from end of the string till 2-nd last dot (.).
For Example for given value 123.456.78.910.abcdefgh I wanted to get 910.abcdefgh only.
I tried with
<RegexReplace Input="$(big_number)" Expression="/(\w+\.\w+)$/gm" Replacement="$1" count="1">
<Output ItemName ="big_number_tail" TaskParameter="Output"/>
</RegexReplace>
But it is returning entire string only.
Any idea what went wrong ?
First of all, do not use a regex literal in a text attribute. When you define regex via strings, not code, regex literal notation (like /.../gm) is not usually used and in these cases / regex delimiters and g, m, etc. flags are treated as part of a pattern, and as a result, it never matches.
Besides, when you extract via replacing as here, you need to make sure you match the whole string with your pattern, and only capture the part you want to extract. Note you may have more than 1 capturing group, and then you could use $2, $3, etc. in the replacement.
You can use
<RegexReplace Input="$(big_number)" Expression=".*\.([^.]*\.[^.]*)$" Replacement="$1" count="1">
See the regex demo. Details:
.* - any zero or more chars other than line break chars, as many as possible
\. - a . char
([^.]*\.[^.]*) - Group 1 ($1 refers to this part): zero or more non-dot chars, a . char, and again zero or more chars other than dots
$ - end of string.
I have a text in which I want to get only the hexadecimal codes.
Like: "thisissometextthisistext\x64\x6f\x6e\x74\x74\x72\x61\x6e\x73\x6c\x61\x74\x65somemoretextoverhere"
It's possible to get the hex codes with \x..
But it doesn't seems I can do something like (^\x..) to select everything but the hex codes.
Any workarounds?
You may use a (?s)((?:\\x[a-fA-F0-9]{2})+)|. regex (that will match and capture into Group 1 any 1+ sequences of hex values OR will just match any other char including a line break char) and replace with a conditional replacement pattern (?{1}$1\n:) (that will reinsert the hex value chain or will replace the match with an empty string):
Find What: (?s)((?:\\x[a-fA-F0-9]{2})+)|.
Replace With: (?{1}$1\n:)
Regex Details:
(?s) - same as . matches newline option ON
((?:\\x[a-fA-F0-9]{2})+) - Group 1 capturing one or more sequences of
\\x - a \\x
[a-fA-F0-9]{2} - 2 letters from a to f or digits
| - or
. - any single char.
Replacement pattern:
(?{1} - if Group 1 matches:
$1\n - replace with its contents + a newline
: - else replace with an empty string
) - end of the replacement pattern.
try ^.*?((\\x[a-f0-9]{2})+).*$ and replace with $1
and it should just leave the hex code
then after replace
If you are already able to find the hexcodes with your regex, couldn't you just use that information to delete all of the hexcodes from the string (or from a clone of the string if you need to preserve the original) and you would be left with all text except for hexcodes.
^ acts as a negation token only inside (and at the beginning) of a character class, you can't use it to negate substrings of several characters.
To select all that isn't \xhh you can use this pattern:
\G(?:\\x[a-f0-9]{2})*+\K(?=.|\n)[^\\]*(?:\\(?!x[a-f0-9]{2})[^\\]*)*
it matches the \xhhs first and removes them from the match using the \K feature (that removes all on the left). The other part of the pattern [^\\]*(?:\\(?!x[a-f0-9]{2})[^\\]*)* matches all that isn't a \xhh. Since this subpattern can match the empty string at the end of the string, I added the lookahead (?=.|\n) to ensure there's at least one character.
\G forces all matches to be contigous. In other words it matches the position at the end of the previous match.
I'm trying to parse a list of filenames to a CSV file by converting the first 2 - characters per line into a |. The problem is that the filenames themselves also contain the character I'm searching for.
My raw data looks something like this:
12055371-1-Florence - BW Letter of Intent HB Comments 9-4-14-2.DOCX
12057668-2-EB-DUE-M- SBuxbaum FHA Benefit Plans-2.DOCX
12058210-1-Redline Letter of Intent-2.PDF
12058029-3-Florence Hospital--Order Establishing Bid Procedures-HB 9-23-14-2.DOCX
12058020-10-Florence - BW Letter of Intent 10,10,14 Revisions-2.DOCX
Using Notepadd++ to replace on the fly, but I'm not sure what regex will work to identify and replace these items.
Don't match -, match the beginning of the lines up to the second - :
match ^(.*?)-(.*?)-
replace by \1|\2|
Explanation :
^ matches the beginning of the line (0-width match).
(.*?) matches any character in a non-greedy way : if the next token of the regex can match, it will let it do so. The result is grouped so it can be referenced later.
\1 and \2 are back-references and refers to the two (.*?) groups.
Note : for efficiency you could replace the non-greedy matches by the negated class [^\-], which means every character but -, the - being escaped because it's a special character in this context. The groups would then become ([^\-]*). Of course it really does not matter if it's a one-time operation.