Separate integers in a file by tabs into an array - c++

Question

Honestly, its a file of 200k integers and have no idea how to error check if the way I am doing it is correct so I'd like some help! There are 10 integers per line and 20k lines total.
Here's my code:
void readFile(int searchValues[VALUES], string fileName, string fileExtension, string filePath){
string fileLine;
ifstream myFile (fileName + fileExtension);
int currentIndex = 0;
if (myFile.is_open()){
while (getline(myFile,fileLine)){
for (int i = 0; i < 10; i++){
searchValues[currentIndex] = stoi(fileLine.substr(0, fileLine.find('\t')));
fileLine = fileLine.substr(fileLine.find('\t') + 1, fileLine.length()-1);
currentIndex++;
}
}
}
}

Answer 1

Here is a working example for 3 integers ... do the same for 10.
#include <stdio.h>
#include <stdlib.h>
int main(int argc, char **argv)
{
FILE *fl=fopen(argv[1],"rt");
int a,b,c,line=0;
while (3 == fscanf(fl,"%d\t%d\t%d",&a,&b,&c))
{
printf(
"line %d contains ints: %d %d %d\n",
line++,
a,
b,
c);
}
fclose(fl);
}

Answer 2

I'm not sure what is the use of VALUES. Also if you're gonna put all the 200k values inside a single array, then why reading only 10 values? I assume you're gonna put each 10 values in a seperate array for example? Anyways, here is a code that reads VALUES amount of integers and stores them in an array. Also note that the parameter filePath is not used
input.txt:
0 1 2 3 4 5 6 7 8 9
#include <iostream>
#include <string>
#include <fstream>
const int VALUES = 10;
void readFile(int searchValues[VALUES], std::string fileName, std::string fileExtension, std::string filePath){
if (!filePath.empty() && filePath.back() != '/')
filePath.push_back('/');
std::string fullPath = filePath + fileName + '.' + fileExtension;
std::ifstream input(fullPath);
if (input.is_open())
{
int i = 0;
while (i < VALUES && input >> searchValues[i]) i++;
}
}
int main()
{
int arr[VALUES];
readFile(arr, "input", "txt", "");
for (int i : arr)
std::cout << i << ' ';
}
Output:
0 1 2 3 4 5 6 7 8 9