lambda capture of std function - c++

The following code causes segmentation fault, but I can't understand why:
#include <iostream>
#include <vector>
#include <functional>
class State {public:int x; int y; State(int _x,int _y):x(_x),y(_y){}};
typedef std::function<bool (const State &s)> FuncT;
std::vector<FuncT> funcs_outside;
class Manager
{
private: std::vector<FuncT> funcs;
public: void insert(const FuncT &g){funcs.push_back(g);}
// public: void insert(const FuncT &g){funcs_outside.push_back(g);}
public: FuncT getAnd()
{
// this should capture everything, no?
return [=](const State &s)
{
bool b=true;
for (const auto f:funcs)
// for (const auto f:funcs_outside)
{
b = b && f(s);
}
return b;
};
}
};
FuncT foo(void)
{
Manager m;
m.insert([=](const State &s){return s.x<=s.y;});
m.insert([=](const State &s){return s.x>=s.y;});
return m.getAnd();
}
int main(int argc, char **argv)
{
auto h = foo();
std::cout << "h(3,3) = " << h(State(3,3)) << "\n";
std::cout << "h(3,4) = " << h(State(3,4)) << "\n";
std::cout << "h(7,2) = " << h(State(7,2)) << "\n";
return 0;
}
The [=] should capture anything the lambda needs right?
When I replace funcs with funcs_outside, everything works well.
What am I doing wrong?

What am I doing wrong?
getAnd returns a function object from a member function, which captures and accesses members.
You call that member function on a local variable, and return the resulting function object to the outside of the scope. The members pointed by the function object no longer exist and calling the function object results in undefined behaviour.
When I replace funcs with funcs_outside, everything works well.
funcs_outside is a global object and you access it within its lifetime, so there is no problem.
how can I fix this?
You could for example capture a copy of the member instead:
return [funcs = this->funcs](const State &s)

Related

How can I access the `typeid` of a captured this pointer in a lambda?

I have the following code:
#include <iostream>
class Bobo
{public:
int member;
void function()
{
auto lambda = [this]() { std::cout << member << '\n'; };
auto lambda2 = [this]() { std::cout << typeid(*this).name() << '\n'; };
lambda();
lambda2();
}
};
int main()
{
Bobo bobo;
bobo.function();
}
The line std::cout << typeid(*this).name(); in lambda2() understandably prints out:
class <lambda_49422032c40f80b55ca1d0ebc98f567f>
However how can I access the 'this' pointer that's been captured so the typeid operator can return type class Bobo?
Edit: The result I get is from compiling this code in Visual Studio Community 2019.
This seems to be VS's bug; when determining the type of this pointer in lambda:
For the purpose of name lookup, determining the type and value of the
this pointer and for accessing non-static class members, the body of
the closure type's function call operator is considered in the context
of the lambda-expression.
struct X {
int x, y;
int operator()(int);
void f()
{
// the context of the following lambda is the member function X::f
[=]()->int
{
return operator()(this->x + y); // X::operator()(this->x + (*this).y)
// this has type X*
};
}
};
So the type of this should be Bobo* in the lambda.
As #songyuanyao suggests, your could should work and produce the appropriate typeid, so it's probably a bug. But - here's a workaround for you:
#include <iostream>
class Bobo
{public:
int member;
void function() {
auto lambda = [this]() { std::cout << member << '\n'; };
auto lambda2 = [my_bobo = this]() {
std::cout << typeid(std::decay_t<decltype(*my_bobo)>).name() << '\n';
};
lambda();
lambda2();
}
};
int main() {
Bobo bobo;
bobo.function();
}
Note that you can replaced typeid(...).name() with the proper type name, obtained (at compile-time!) as per this answer:
std::cout << type_name<std::decay_t<decltype(*my_bobo)>>() << '\n';

How to pass a private member function as an argument

In ROS, there is a function called NodeHanle::subscribe(Args...): NodeHandle::subscribe. Which lets u pass a PRIVATE member function as callback.
However, when I tried it myself (passing private member function using std::bind), my compiler always fails and complaining about Foo::foo() is a private member function. When I change Foo::foo to public function, everything goes to normal.
template<typename T>
void getWrapper1(void(T::*fn)(int), T *t) {
return [&](int arg) {
std::cout << "process before function with wrapper" << std::endl;
(t->*fn)(arg);
std::cout << "process after function with wrapper" << std::endl;
};
}
void getWrapper2(std::function<void(int)> fn) {
return [=](int arg) {
std::cout << "process before function with wrapper" << std::endl;
fn(arg);
std::cout << "process after function with wrapper" << std::endl;
}
}
class Foo {
private:
void foo(int a) {
std::cout << __FUNCTION__ << a << std::endl;
}
}
int main(int argc, char** argv) {
Foo foo_inst;
auto func1 = getWrapper1(&Foo::foo, &foo_inst); // fail because foo is private
auto func2 = getWrapper2(std::bind(&Foo::foo, &foo_inst, std::placeholders::_1)); // fail because foo is private
func1(1);
func2(2);
return 0;
}
from this answer, using std::function can also passing private member function. But what I tried it different.
It worths to mention that in getWrapper2 I use [=] instead of [&] because using [&] may cause seg fault. Why it has to be a "value capture"?
platform: GCC 5.4.0, c++14, ubuntu16.04
You must pass it from the inside. You cannot access private function from the outside of the class. Not even pointer to private stuff. Private is private.
class Foo {
void foo(int a) {
std::cout << __FUNCTION__ << a << std::endl;
}
public:
auto getWrapper() {
// using a lambda (recommended)
return getWrapper2([this](int a) {
return foo(a);
});
// using a bind (less recommended)
return getWrapper2(std::bind(&Foo::foo, this, std::placeholders::_1));
}
}
Why it has to be a "value capture"?
Both wrapper need to value capture. Your Wrapper1 have undefined behaviour.
Consider this:
// returns a reference to int
auto test(int a) -> int& {
// we return the local variable 'a'
return a;
// a dies when returning
}
The same thing happen with a lambda:
auto test(int a) {
// we capture the local variable 'a'
return [&a]{};
// a dies when returning
}
auto l = test(1);
// l contain a captured reference to 'a', which is dead
Pointers are passed by value. A pointer is itself an object. A pointer has itself a lifetime and can die.
auto test(int* a) -> int*& {
// we are still returning a reference to local variable 'a'.
return a;
}
And... you guessed it, the same thing for std::function:
auto test(std::function<void(int)> a) {
// return a lambda capturing a reference to local variable 'a'.
return [&a]{};
}

Use std::function as member function, which capture `this`, and access it from the copied lambda after destructor

Flex Ferrum post a code sample here (I think it is Minimal, Complete, and Verifiable enough):
#include <iostream>
#include <functional>
using namespace std;
class Bang
{
public:
Bang(int i = 0) : m_val(i)
{
m_foo = [this] {std::cout << m_val << std::endl;};
}
~Bang()
{
m_val = -1;
}
void Foo()
{
m_foo();
}
private:
int m_val;
std::function<void ()> m_foo;
};
Bang GetBang()
{
return Bang(100500);
}
int main() {
Bang b(100500);
b.Foo();
b = GetBang();
b.Foo();
return 0;
}
Our nice Flex also offer a live demo
After a rough look, I thought it will output 100500, but the real output is:
-1
Why? What's behind it?
How to fix it?(output 100500, not -1)
I have written some my own reasonings in the ask box, but found it is more fit to be posted as an answer(will make the question too long). If my answer is wrong, please correct it and more answers are welcome
Ah, it should blame the destructor of temporary - Bang(100500), which returns form GetBang, is prvalue, and has temporary object lifetime.
[this] will be stored as reference of *this, like this:
class Lambda
{
public:
void operator()() const
{
//output
}
private:
Bang& bang;
public:
Lambda(Bang& bang) : bang{bang}
{
}
} lambda{*this};
...
m_foo = lambda;
Because here is no RVO, so, the temporary Bang(100500) will first be assigned to b, then be destroyed.
Custorm operator(), constructor, and destructor to output some information:
#include <iostream>
#include <functional>
using namespace std;
class Bang
{
public:
Bang(int i = 0) : m_val(i)
{
std::cout << "Bang(int i = 0) m_val address is " << &m_val << '\n';
class Lambda
{
public:
void operator()() const
{
std::cout << "operator() m_val address is " << &bang.m_val << '\n';
std::cout << bang.m_val << std::endl;
}
private:
Bang &bang;
public:
Lambda(Bang &bang) : bang{bang}
{
}
} lambda{*this};
m_foo = lambda;
}
~Bang()
{
std::cout << "~Bang()\n";
m_val = -1;
}
void Foo()
{
m_foo();
}
private:
int m_val;
std::function<void()> m_foo;
};
Bang GetBang()
{
return Bang(100500);
}
int main()
{
Bang b;
b = GetBang();
b.Foo();
return 0;
}
live demo
Output:
Bang(int i = 0) m_val address is 0x7ffd202c48b0
Bang(int i = 0) m_val address is 0x7ffd202c48e0
~Bang()
operator() m_val address is 0x7ffd202c48e0
-1
~Bang()
shows:
dtor will be called before output, That means that the temporary object has been destroyed.
m_value's address doesn't change.
The two guaranteed we still access the temporary's m_value from the b's m_foo().
It should be Undefined Behaviour to access an object which has be destroyed, but no warning and errors required.
Update
To solve the problem, there two solutions:
Like #Killzone Kid points out, capture with an initializer: [bang = *this]. This requires c++14.
More simpler way to capture of the current object by-copy: [*this]. This requires c++17. live demo
You probably want to pass current object to lambda by value *this so that it can be stored and copied when you copy assign Bang. Passing pointer this will store and copy pointer to the temp object that has been destroyed when you copy assign Bang.
This works as it should:
#include <iostream>
#include <functional>
class Bang
{
public:
Bang(int i = 0) : m_val(i)
{
m_foo = [bang = *this] { std::cout << bang.m_val << std::endl; };
}
~Bang()
{
m_val = -1;
}
void Foo()
{
m_foo();
}
private:
int m_val;
std::function<void()> m_foo;
};
Bang GetBang()
{
return Bang(100500);
}
int main()
{
Bang b;
b = GetBang();
b.Foo();
return 0;
}
Demo: https://ideone.com/LUDrBb

How can I make a C++ member function by binding the arguments of another member function?

I am having problems with creating a variable of pointer-to-member-function (PTMF) type "on the fly" (that is, by pinning some arguments of an existing member function via std::bind). My question is if it is ever possible with C++11 or post-C++11 standard.
Preambula: I have a class that stores a static const array of std::functions initialized from PTMFs, hereinafter referred to as "handlers". Originally, they were regular member functions with a name and implementation so I didn't ever use C++11 and std::function. Then, I decided that many of them are nearly similar, and decided to generate them with a "generator function". I would like to avoid using templates for the generation because the number of these nearly similar handlers is going to dramatically increase in future (around 200+) and templatizing will just lead to code bloat.
If the PTMFs in question were static, I would have no problems with generating the handlers via std::bind. A simplified example:
#include <iostream>
#include <functional>
using namespace std;
struct A {
typedef function<void(int)> HandlerFn;
static void parametrized_handler(int i, const char *param) {
cout << "parametrized handler: " << param << endl;
}
static void handler(int i) { cout << "handler 1" << endl; }
int mm;
};
static const A::HandlerFn handler2 = [](int) { cout << "handler 2" << endl; };
static const A::HandlerFn handler3 = bind(A::parametrized_handler,
placeholders::_1,
"test_param");
int main()
{
A::handler(42);
handler2(42);
handler3(42);
return 0;
}
Output:
$ ./a.out
handler 1
handler 2
parametrized handler: test_param
The problem arises when I turn to non-static member functions. std::bind is not able to generate a function object that acts like a PTMF. I know that I can pass a real object as a first argument to bind and get a working function but that is not what I want: when I am initializing a static const array, there are no objects at all, and the result of bind will act as a regular non-member function anyway.
An expected implementation for non-static member functions (with an imaginary std::bind_mem binder):
#include <iostream>
#include <functional>
using namespace std;
struct A;
struct A {
typedef function<void(int)> HandlerFn;
void parametrized_handler(int i, const char *param) {
mm;
cout << "parametrized handler: " << param << endl;
}
void handler(int i) const { mm; cout << "handler 1" << endl; }
const HandlerFn handler2 = [this](int i) { mm; cout << "handler 2" << endl; };
int mm;
};
// An imaginary PTMF binder
// static const A::HandlerFn handler3 = bind_mem(A::parametrized_handler,
// placeholders::_1,
// "test_param");
int main()
{
A a;
(a.handler)(42);
(a.handler2)(42);
//(a.handler3)(42);
return 0;
}
Output:
$ ./a.out
handler 1
handler 2
So is there a way to implement a PTMF argument binding?
For binding a pointer to non static member function, you need an object.
#include<functional>
struct A {
typedef std::function<void(int)> HandlerFn;
void mem(int);
void static static_mem(int);
};
void foo() {
A a;
A::HandlerFn h1 = A::static_mem;
//This captures a by ref
A::HandlerFn h2 = std::bind(&A::mem, std::ref(a), std::placeholders::_1);
//This captures a by copy
A::HandlerFn h3 = std::bind(&A::mem, a, std::placeholders::_1);
//Change to =a for copy
A::HandlerFn h4 = [&a](int i){
a.mem(i);
};
h1(34);
h2(42);
}
Link:https://godbolt.org/g/Mddexq

Class non-static method pointer to global function

I'm trying to point a class method to a global function, i've seen this
but how i can't do it without instance?.
Consider this:
class x
{
public:
int(x::*GetVal)(int);
};
int RtX(int a)
{
return a * 4;
}
// declaration
int(x::*GetVal)(int) = (int(x::*)(int))&::Rtx; // :: global? // error
int main()
{
x a;
cout << (a.*GetVal)(4) << endl;
}
This returns me the error:
[Error] invalid cast from type 'int ()(int)' to type 'int
(x::)(int)'
x::GetX is a pointer to member. These are deeply complicated beasts, and you can't get them to point to non-member functions. The following code will work:
#include <iostream>
int RtX(int a) // Global non-member function
{
return a * 4;
}
class x
{
public:
int(x::*GetVal)(int);
// This is an instance member function which acts as a proxy and calls the
// the global function
int RtX(int a) { return ::RtX(a); }
};
int main()
{
x a;
a.GetVal =&x.RtX; // Assign the member variable. Could do this in the
// constructor. **NOTE** No casts!
std::cout << (a.*GetVal)(4) << std::endl;
}
If you find yourself reaching for a cast when dealing with function pointers and pointers-to-member-functions, stop - you are almost certainly doing it wrong, and while it will compile, it is very likely not to run properly.
Alternatively, as noted in the comments, use std::function.
#include <iostream>
#include <functional>
int RtX(int a)
{
return a * 4;
}
class x
{
public:
std::function<int(int)> GetVal;
// Initialize GetVal in the constructor.
x() : GetVal(RtX)
{}
// Alternatively, you can initialize the variable in with a default
// initialization. You can also declare the member const if you don't want to
// change it later.
const std::function<int(int)> gv = RtX;
/*
};
int main()
{
x a;
std::cout << a.GetVal(4) << std::endl;
}
Non static member functions need an instance in order to be called. You might consider using a static function member instead and if you also use std::function, you might get a simple code to assign your member function without instance:
#include <iostream>
#include <functional>
int RtX(int a)
{
return a * 4;
}
class x
{
public:
static std::function<int(int)> GetVal;
};
std::function<int(int)> x::GetVal = RtX;
int main()
{
x a;
std::cout << (a.GetVal)(4) << std::endl;
}