Strange Printing in SymPy For Indexed Variables - sympy

I am trying to figure out how I can print an indexed variable in SymPy to make it look cleaner than below. I am not able to use Mathjax for some reason, so I apologize that there is just a photo to work with.
import sympy
from sympy import *
init_printing(use_latex='mathjax')
S = IndexedBase('S')
i,j,t = Idx('i'),Idx('j'),Idx('t')
S[i]

As my previous comment states, it is currently not supported in the existing latex printer.
However, you can manually implement _latex(self, expr) for Idx, or use a custom printer:
from sympy import *
from sympy.printing.latex import LatexPrinter
class CustomLatexPrinter(LatexPrinter):
def _print_Idx(self, expr):
return expr.name
#classmethod
def printer(cls, expr, **kwargs):
return cls(kwargs).doprint(expr)
init_printing(use_latex='mathjax', latex_printer=CustomLatexPrinter.printer)
All I do here is simple implement _print_Idx to return the label as a string (through the name property) and provide a printer function to match the signature init_printing requires for a latex_printer.
Then, following your example

Related

Code is Not able to find my function in Python(Spark) class

I need some help regarding the error in code. My Code consists of retrieving the zomato reviews and storing it in HDFS and again reading it performing Recommender Analtyics on it. I am getting a problem regarding my function is not recognizing in pyspark code. I am not entirely pasting the code as it might be confusing so i am writing a small similar use case for your easy understanding.
I am trying to read a file from local and converting it to dataframe from rdd and performing some operations and again converting it to rdd and performing map operation to have delimiter by '|' and then save it to HDFS.
When i try to call self.filter_data(y) in lambda func of check function its not recognizing and giving me error as
Exception: It appears that you are attempting to reference
SparkContext from a broadcast variable, action, or transformation.
SparkContext can only be used on the driver, not in code that it run
on workers. For more information, see SPARK-5063.
****CAN ANY ONE HELP ME WHY MY FILTER_DATA FUNCTION IS NOT RECOGNISING? SHOULD I NEED TO ADD ANY THING OR ANY THING WRONG IN THE WAY I AM CALLING. PLEASE HELP ME. THANKS IN ADVANCE****
INPUT VALUE
starting
0|0|ffae4f|0|https://b.zmtcdn.com/data/user_profile_pictures/565/aed32fa2eb18bb4a5a3ba426870fd565.jpg?fit=around%7C100%3A100&crop=100%3A100%3B%2A%2C%2A|https://www.zomato.com/akellaram87?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1|2.5|FFBA00|Well...|unknown|16946626|2017-08-01T00-25-43.455182Z|30059877|Have been here for a quick bite for lunch, ambience and everything looked good, food was okay but presentation was not very appealing. We or...|2017-04-15 16:38:38|Big Foodie|6|Venkata Ram Akella|akellaram87|Bad Food|0.969352505662|0|0|0|0|0|0|1|1|0|0|1|0|0|0.782388212399
ending
starting
1|0|ffae4f|0|https://b.zmtcdn.com/data/user_profile_pictures/4d1/d70d7a57e1bfdf296ff4db3d8daf94d1.jpg?fit=around%7C100%3A100&crop=100%3A100%3B%2A%2C%2A|https://www.zomato.com/users/sm4-2011696?utm_source=api_basic_user&utm_medium=api&utm_campaign=v2.1|1|CB202D|Avoid!|unknown|16946626|2017-08-01T00-25-43.455182Z|29123338|Giving a 1.0 rating because one cannot proceed with writing a review, without rating it. This restaurant deserves a 0 star rating. The qual...|2017-01-04 10:54:53|Big Foodie|4|Sm4|unknown|Bad Service|0.964402034541|0|1|0|0|0|0|0|1|0|0|0|1|0|0.814540622345
ending
My code:
if __name__== '__main__':
import os,logging,sys,time,pandas,json;from subprocess
import PIPE,Popen,call;from datetime import datetime, time, timedelta
from pyspark import SparkContext, SparkConf
conf = SparkConf().setAppName('test')
sc = SparkContext(conf = conf,pyFiles=['/bdaas/exe/nlu_project/spark_classifier.py','/bdaas/exe/spark_zomato/other_files/spark_zipcode.py','/bdaas/exe/spark_zomato/other_files/spark_zomato.py','/bdaas/exe/spark_zomato/conf_files/spark_conf.py','/bdaas/exe/spark_zomato/conf_files/date_comparision.py'])
from pyspark.sql import Row, SQLContext,HiveContext
from pyspark.sql.functions import lit
sqlContext = HiveContext(sc)
import sys,logging,pandas as pd
import spark_conf
n = new()
n.check()
class new:
def __init__(self):
print 'entered into init'
def check(self):
data = sc.textFile('file:///bdaas/src/spark_dependencies/classifier_data/final_Output.txt').map(lambda x: x.split('|')).map(lambda z: Row(restaurant_id=z[0], rating = z[1], review_id = z[2],review_text = z[3],rating_color = z[4],rating_time_friendly=z[5],rating_text=z[6],time_stamp=z[7],likes=z[8],comment_count =z[9],user_name = z[10],user_zomatohandle=z[11],user_foodie_level = z[12],user_level_num=z[13],foodie_color=z[14],profile_url=z[15],profile_image=z[16],retrieved_time=z[17]))
data_r = sqlContext.createDataFrame(data)
data_r.show()
d = data_r.rdd.collect()
print d
data_r.rdd.map(lambda x: list(x)).map(lambda y: self.filter_data(y)).collect()
print data_r
def filter_data(self,y):
s = str()
for i in y:
print i.encode('utf-8')
if i != '':
s = s + i.encode('utf-8') + '|'
print s[0:-1]
return s[0:-1]

`setattr()` on Python2 `_sre.SRE_Pattern`

I'm basically attempting py2/3 compatibility by trying to add a a fullmatch method to Python2 re compiled patterns.
I've seen https://stackoverflow.com/a/2982/2694385 on how to add an attribute to an existing instance.
I'm creating the method as given in https://stackoverflow.com/a/30212799/2694385.
Example code
import re
import six
regex = re.compile('some pattern') # Better if we keep this same
if six.PY2:
def fullmatch(self_regex, string, flags=0):
return self_regex.match(string, flags=flags)
regex = re.compile(r'(?:' + regex.pattern + r')\Z', flags=regex.flags)
import types
bound = types.MethodType(fullmatch, regex)
# AttributeError here. None of the following three lines work
regex.fullmatch = bound
regex.__setattr__('fullmatch', bound)
setattr(regex, 'fullmatch', bound)
That ain't gonna work - regex objects are created on the C side and they don't represent your regular instances so you cannot modify their signature from within Python. For example, if you try to extend _sre.SRE_Pattern:
import _sre
class CustomPattern(_sre.SRE_Pattern): pass
You'll get an AttributeError complaining that such object doesn't exist in the _sre module. If you try to cheat it with:
import re
tmp_pattern = re.compile("")
sre_pat = type(tmp_pattern)
class CustomPattern(sre_pat): pass
it will give you a TypeError complaining that _sre.SRE_Pattern (which now 'temporarily' exists as it's being created ad-hoc) is not an acceptable base type.
What you can do instead is to create a full wrapper around the re module (or at least add the missing structures to it) and handle the Python version differences on the Python's side, although I think it's just not worth it.
P.S. If you're not using six anywhere else, there no reason for the overhead just to check your Python version - you can use sys.version_info.major < 3 instead.
See nlpia.regexes.Pattern for something similar to what you want -- a Frankenstein mashup of _sre.Pattern with a fullmatch() method. This monkey-patching "inheritance" approach works in Python 2 and 3.
import re
import regex
class Pattern:
""" "Inherits" _sre.SRE_Pattern and adds .fullmatch() method
>>> pattern = Pattern('Aaron[ ]Swartz')
>>> pattern.match('Aaron Swartz')
<_sre.SRE_Match object; span=(0, 12), match='Aaron Swartz'>
>>> pattern.fullmatch('Aaron Swartz!!')
>>> pattern.match('Aaron Swartz!!')
<_sre.SRE_Match object; span=(0, 12), match='Aaron Swartz'>
"""
def __init__(self, pattern):
self._compiled_pattern = re.compile(pattern)
for name in dir(self._compiled_pattern):
if not name in set(('__class__', '__init__', 'fullmatch')):
attr = getattr(self._compiled_pattern, name)
setattr(self, name, attr)
def fullmatch(self, *args, **kwargs):
return regex.fullmatch(self._compiled_pattern.pattern, *args, **kwargs)

What is the # doing in the following code? [duplicate]

What does the # symbol do in Python?
An # symbol at the beginning of a line is used for class and function decorators:
PEP 318: Decorators
Python Decorators
The most common Python decorators are:
#property
#classmethod
#staticmethod
An # in the middle of a line is probably matrix multiplication:
# as a binary operator.
Example
class Pizza(object):
def __init__(self):
self.toppings = []
def __call__(self, topping):
# When using '#instance_of_pizza' before a function definition
# the function gets passed onto 'topping'.
self.toppings.append(topping())
def __repr__(self):
return str(self.toppings)
pizza = Pizza()
#pizza
def cheese():
return 'cheese'
#pizza
def sauce():
return 'sauce'
print pizza
# ['cheese', 'sauce']
This shows that the function/method/class you're defining after a decorator is just basically passed on as an argument to the function/method immediately after the # sign.
First sighting
The microframework Flask introduces decorators from the very beginning in the following format:
from flask import Flask
app = Flask(__name__)
#app.route("/")
def hello():
return "Hello World!"
This in turn translates to:
rule = "/"
view_func = hello
# They go as arguments here in 'flask/app.py'
def add_url_rule(self, rule, endpoint=None, view_func=None, **options):
pass
Realizing this finally allowed me to feel at peace with Flask.
In Python 3.5 you can overload # as an operator. It is named as __matmul__, because it is designed to do matrix multiplication, but it can be anything you want. See PEP465 for details.
This is a simple implementation of matrix multiplication.
class Mat(list):
def __matmul__(self, B):
A = self
return Mat([[sum(A[i][k]*B[k][j] for k in range(len(B)))
for j in range(len(B[0])) ] for i in range(len(A))])
A = Mat([[1,3],[7,5]])
B = Mat([[6,8],[4,2]])
print(A # B)
This code yields:
[[18, 14], [62, 66]]
This code snippet:
def decorator(func):
return func
#decorator
def some_func():
pass
Is equivalent to this code:
def decorator(func):
return func
def some_func():
pass
some_func = decorator(some_func)
In the definition of a decorator you can add some modified things that wouldn't be returned by a function normally.
What does the “at” (#) symbol do in Python?
In short, it is used in decorator syntax and for matrix multiplication.
In the context of decorators, this syntax:
#decorator
def decorated_function():
"""this function is decorated"""
is equivalent to this:
def decorated_function():
"""this function is decorated"""
decorated_function = decorator(decorated_function)
In the context of matrix multiplication, a # b invokes a.__matmul__(b) - making this syntax:
a # b
equivalent to
dot(a, b)
and
a #= b
equivalent to
a = dot(a, b)
where dot is, for example, the numpy matrix multiplication function and a and b are matrices.
How could you discover this on your own?
I also do not know what to search for as searching Python docs or Google does not return relevant results when the # symbol is included.
If you want to have a rather complete view of what a particular piece of python syntax does, look directly at the grammar file. For the Python 3 branch:
~$ grep -C 1 "#" cpython/Grammar/Grammar
decorator: '#' dotted_name [ '(' [arglist] ')' ] NEWLINE
decorators: decorator+
--
testlist_star_expr: (test|star_expr) (',' (test|star_expr))* [',']
augassign: ('+=' | '-=' | '*=' | '#=' | '/=' | '%=' | '&=' | '|=' | '^=' |
'<<=' | '>>=' | '**=' | '//=')
--
arith_expr: term (('+'|'-') term)*
term: factor (('*'|'#'|'/'|'%'|'//') factor)*
factor: ('+'|'-'|'~') factor | power
We can see here that # is used in three contexts:
decorators
an operator between factors
an augmented assignment operator
Decorator Syntax:
A google search for "decorator python docs" gives as one of the top results, the "Compound Statements" section of the "Python Language Reference." Scrolling down to the section on function definitions, which we can find by searching for the word, "decorator", we see that... there's a lot to read. But the word, "decorator" is a link to the glossary, which tells us:
decorator
A function returning another function, usually applied as a function transformation using the #wrapper syntax. Common
examples for decorators are classmethod() and staticmethod().
The decorator syntax is merely syntactic sugar, the following two
function definitions are semantically equivalent:
def f(...):
...
f = staticmethod(f)
#staticmethod
def f(...):
...
The same concept exists for classes, but is less commonly used there.
See the documentation for function definitions and class definitions
for more about decorators.
So, we see that
#foo
def bar():
pass
is semantically the same as:
def bar():
pass
bar = foo(bar)
They are not exactly the same because Python evaluates the foo expression (which could be a dotted lookup and a function call) before bar with the decorator (#) syntax, but evaluates the foo expression after bar in the other case.
(If this difference makes a difference in the meaning of your code, you should reconsider what you're doing with your life, because that would be pathological.)
Stacked Decorators
If we go back to the function definition syntax documentation, we see:
#f1(arg)
#f2
def func(): pass
is roughly equivalent to
def func(): pass
func = f1(arg)(f2(func))
This is a demonstration that we can call a function that's a decorator first, as well as stack decorators. Functions, in Python, are first class objects - which means you can pass a function as an argument to another function, and return functions. Decorators do both of these things.
If we stack decorators, the function, as defined, gets passed first to the decorator immediately above it, then the next, and so on.
That about sums up the usage for # in the context of decorators.
The Operator, #
In the lexical analysis section of the language reference, we have a section on operators, which includes #, which makes it also an operator:
The following tokens are operators:
+ - * ** / // % #
<< >> & | ^ ~
< > <= >= == !=
and in the next page, the Data Model, we have the section Emulating Numeric Types,
object.__add__(self, other)
object.__sub__(self, other)
object.__mul__(self, other)
object.__matmul__(self, other)
object.__truediv__(self, other)
object.__floordiv__(self, other)
[...]
These methods are called to implement the binary arithmetic operations (+, -, *, #, /, //, [...]
And we see that __matmul__ corresponds to #. If we search the documentation for "matmul" we get a link to What's new in Python 3.5 with "matmul" under a heading "PEP 465 - A dedicated infix operator for matrix multiplication".
it can be implemented by defining __matmul__(), __rmatmul__(), and
__imatmul__() for regular, reflected, and in-place matrix multiplication.
(So now we learn that #= is the in-place version). It further explains:
Matrix multiplication is a notably common operation in many fields of
mathematics, science, engineering, and the addition of # allows
writing cleaner code:
S = (H # beta - r).T # inv(H # V # H.T) # (H # beta - r)
instead of:
S = dot((dot(H, beta) - r).T,
dot(inv(dot(dot(H, V), H.T)), dot(H, beta) - r))
While this operator can be overloaded to do almost anything, in numpy, for example, we would use this syntax to calculate the inner and outer product of arrays and matrices:
>>> from numpy import array, matrix
>>> array([[1,2,3]]).T # array([[1,2,3]])
array([[1, 2, 3],
[2, 4, 6],
[3, 6, 9]])
>>> array([[1,2,3]]) # array([[1,2,3]]).T
array([[14]])
>>> matrix([1,2,3]).T # matrix([1,2,3])
matrix([[1, 2, 3],
[2, 4, 6],
[3, 6, 9]])
>>> matrix([1,2,3]) # matrix([1,2,3]).T
matrix([[14]])
Inplace matrix multiplication: #=
While researching the prior usage, we learn that there is also the inplace matrix multiplication. If we attempt to use it, we may find it is not yet implemented for numpy:
>>> m = matrix([1,2,3])
>>> m #= m.T
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: In-place matrix multiplication is not (yet) supported. Use 'a = a # b' instead of 'a #= b'.
When it is implemented, I would expect the result to look like this:
>>> m = matrix([1,2,3])
>>> m #= m.T
>>> m
matrix([[14]])
What does the “at” (#) symbol do in Python?
# symbol is a syntactic sugar python provides to utilize decorator,
to paraphrase the question, It's exactly about what does decorator do in Python?
Put it simple decorator allow you to modify a given function's definition without touch its innermost (it's closure).
It's the most case when you import wonderful package from third party. You can visualize it, you can use it, but you cannot touch its innermost and its heart.
Here is a quick example,
suppose I define a read_a_book function on Ipython
In [9]: def read_a_book():
...: return "I am reading the book: "
...:
In [10]: read_a_book()
Out[10]: 'I am reading the book: '
You see, I forgot to add a name to it.
How to solve such a problem? Of course, I could re-define the function as:
def read_a_book():
return "I am reading the book: 'Python Cookbook'"
Nevertheless, what if I'm not allowed to manipulate the original function, or if there are thousands of such function to be handled.
Solve the problem by thinking different and define a new_function
def add_a_book(func):
def wrapper():
return func() + "Python Cookbook"
return wrapper
Then employ it.
In [14]: read_a_book = add_a_book(read_a_book)
In [15]: read_a_book()
Out[15]: 'I am reading the book: Python Cookbook'
Tada, you see, I amended read_a_book without touching it inner closure. Nothing stops me equipped with decorator.
What's about #
#add_a_book
def read_a_book():
return "I am reading the book: "
In [17]: read_a_book()
Out[17]: 'I am reading the book: Python Cookbook'
#add_a_book is a fancy and handy way to say read_a_book = add_a_book(read_a_book), it's a syntactic sugar, there's nothing more fancier about it.
If you are referring to some code in a python notebook which is using Numpy library, then # operator means Matrix Multiplication. For example:
import numpy as np
def forward(xi, W1, b1, W2, b2):
z1 = W1 # xi + b1
a1 = sigma(z1)
z2 = W2 # a1 + b2
return z2, a1
Decorators were added in Python to make function and method wrapping (a function that receives a function and returns an enhanced one) easier to read and understand. The original use case was to be able to define the methods as class methods or static methods on the head of their definition. Without the decorator syntax, it would require a rather sparse and repetitive definition:
class WithoutDecorators:
def some_static_method():
print("this is static method")
some_static_method = staticmethod(some_static_method)
def some_class_method(cls):
print("this is class method")
some_class_method = classmethod(some_class_method)
If the decorator syntax is used for the same purpose, the code is shorter and easier to understand:
class WithDecorators:
#staticmethod
def some_static_method():
print("this is static method")
#classmethod
def some_class_method(cls):
print("this is class method")
General syntax and possible implementations
The decorator is generally a named object ( lambda expressions are not allowed) that accepts a single argument when called (it will be the decorated function) and returns another callable object. "Callable" is used here instead of "function" with premeditation. While decorators are often discussed in the scope of methods and functions, they are not limited to them. In fact, anything that is callable (any object that implements the _call__ method is considered callable), can be used as a decorator and often objects returned by them are not simple functions but more instances of more complex classes implementing their own __call_ method.
The decorator syntax is simply only a syntactic sugar. Consider the following decorator usage:
#some_decorator
def decorated_function():
pass
This can always be replaced by an explicit decorator call and function reassignment:
def decorated_function():
pass
decorated_function = some_decorator(decorated_function)
However, the latter is less readable and also very hard to understand if multiple decorators are used on a single function.
Decorators can be used in multiple different ways as shown below:
As a function
There are many ways to write custom decorators, but the simplest way is to write a function that returns a subfunction that wraps the original function call.
The generic patterns is as follows:
def mydecorator(function):
def wrapped(*args, **kwargs):
# do some stuff before the original
# function gets called
result = function(*args, **kwargs)
# do some stuff after function call and
# return the result
return result
# return wrapper as a decorated function
return wrapped
As a class
While decorators almost always can be implemented using functions, there are some situations when using user-defined classes is a better option. This is often true when the decorator needs complex parametrization or it depends on a specific state.
The generic pattern for a nonparametrized decorator as a class is as follows:
class DecoratorAsClass:
def __init__(self, function):
self.function = function
def __call__(self, *args, **kwargs):
# do some stuff before the original
# function gets called
result = self.function(*args, **kwargs)
# do some stuff after function call and
# return the result
return result
Parametrizing decorators
In real code, there is often a need to use decorators that can be parametrized. When the function is used as a decorator, then the solution is simple—a second level of wrapping has to be used. Here is a simple example of the decorator that repeats the execution of a decorated function the specified number of times every time it is called:
def repeat(number=3):
"""Cause decorated function to be repeated a number of times.
Last value of original function call is returned as a result
:param number: number of repetitions, 3 if not specified
"""
def actual_decorator(function):
def wrapper(*args, **kwargs):
result = None
for _ in range(number):
result = function(*args, **kwargs)
return result
return wrapper
return actual_decorator
The decorator defined this way can accept parameters:
>>> #repeat(2)
... def foo():
... print("foo")
...
>>> foo()
foo
foo
Note that even if the parametrized decorator has default values for its arguments, the parentheses after its name is required. The correct way to use the preceding decorator with default arguments is as follows:
>>> #repeat()
... def bar():
... print("bar")
...
>>> bar()
bar
bar
bar
Finally lets see decorators with Properties.
Properties
The properties provide a built-in descriptor type that knows how to link an attribute to a set of methods. A property takes four optional arguments: fget , fset , fdel , and doc . The last one can be provided to define a docstring that is linked to the attribute as if it were a method. Here is an example of a Rectangle class that can be controlled either by direct access to attributes that store two corner points or by using the width , and height properties:
class Rectangle:
def __init__(self, x1, y1, x2, y2):
self.x1, self.y1 = x1, y1
self.x2, self.y2 = x2, y2
def _width_get(self):
return self.x2 - self.x1
def _width_set(self, value):
self.x2 = self.x1 + value
def _height_get(self):
return self.y2 - self.y1
def _height_set(self, value):
self.y2 = self.y1 + value
width = property(
_width_get, _width_set,
doc="rectangle width measured from left"
)
height = property(
_height_get, _height_set,
doc="rectangle height measured from top"
)
def __repr__(self):
return "{}({}, {}, {}, {})".format(
self.__class__.__name__,
self.x1, self.y1, self.x2, self.y2
)
The best syntax for creating properties is using property as a decorator. This will reduce the number of method signatures inside of the class
and make code more readable and maintainable. With decorators the above class becomes:
class Rectangle:
def __init__(self, x1, y1, x2, y2):
self.x1, self.y1 = x1, y1
self.x2, self.y2 = x2, y2
#property
def width(self):
"""rectangle height measured from top"""
return self.x2 - self.x1
#width.setter
def width(self, value):
self.x2 = self.x1 + value
#property
def height(self):
"""rectangle height measured from top"""
return self.y2 - self.y1
#height.setter
def height(self, value):
self.y2 = self.y1 + value
Starting with Python 3.5, the '#' is used as a dedicated infix symbol for MATRIX MULTIPLICATION (PEP 0465 -- see https://www.python.org/dev/peps/pep-0465/)
# can be a math operator or a DECORATOR but what you mean is a decorator.
This code:
def func(f):
return f
func(lambda :"HelloWorld")()
using decorators can be written like:
def func(f):
return f
#func
def name():
return "Hello World"
name()
Decorators can have arguments.
You can see this GeeksforGeeks post: https://www.geeksforgeeks.org/decorators-in-python/
It indicates that you are using a decorator. Here is Bruce Eckel's example from 2008.
Python decorator is like a wrapper of a function or a class. It’s still too conceptual.
def function_decorator(func):
def wrapped_func():
# Do something before the function is executed
func()
# Do something after the function has been executed
return wrapped_func
The above code is a definition of a decorator that decorates a function.
function_decorator is the name of the decorator.
wrapped_func is the name of the inner function, which is actually only used in this decorator definition. func is the function that is being decorated.
In the inner function wrapped_func, we can do whatever before and after the func is called. After the decorator is defined, we simply use it as follows.
#function_decorator
def func():
pass
Then, whenever we call the function func, the behaviours we’ve defined in the decorator will also be executed.
EXAMPLE :
from functools import wraps
def mydecorator(f):
#wraps(f)
def wrapped(*args, **kwargs):
print "Before decorated function"
r = f(*args, **kwargs)
print "After decorated function"
return r
return wrapped
#mydecorator
def myfunc(myarg):
print "my function", myarg
return "return value"
r = myfunc('asdf')
print r
Output :
Before decorated function
my function asdf
After decorated function
return value
To say what others have in a different way: yes, it is a decorator.
In Python, it's like:
Creating a function (follows under the # call)
Calling another function to operate on your created function. This returns a new function. The function that you call is the argument of the #.
Replacing the function defined with the new function returned.
This can be used for all kinds of useful things, made possible because functions are objects and just necessary just instructions.
# symbol is also used to access variables inside a plydata / pandas dataframe query, pandas.DataFrame.query.
Example:
df = pandas.DataFrame({'foo': [1,2,15,17]})
y = 10
df >> query('foo > #y') # plydata
df.query('foo > #y') # pandas

How to return a lazy translation object with placeholders?

In my Django v1.6.5 project running on Python v2.7.x, I have a Model that returns its configuration as a string. I need the returned string to be a gettext_lazy object, so I can evaluate it in any language required later.
from __future__ import unicode_literals
from django.utils.translation import ugettext_lazy as _, string_concat
...
class MyModel(models.Model):
key = models.CharField(...)
value = models.CharField(...)
#property
def config_str(self):
return _('some configuration')
This seems to work fine in these scenarios:
Static string: (see above) - works!
String concatenation: return string_concat(self.key, _(' equals '), self.value) - works!
What is not working, is using gettext_lazy with placeholders, a la:
return _('“%(key)s” equals “%(value)s”' % {key: self.key, value: self.value})
or using the .format() mechanism:
return _('“{key}” equals “{value}”').format(key=self.key, value=self.value)
When I do this, my .po file does contain:
#, python-format
msgid "“%(key)s” equals “%(value)s”" or
msgid "«{key}» equals «{value}»"
but even when I populate this Eg.:
msgstr "«%(key)s» est égal à «%(value)s»" or
msgstr "«{key}» est égal à «{value}»"
and I run compilemessages, the translation seems to be ignored. When I translate the promise returned by the model instance, I always get an EN string with the placeholders filled E.g., '“foo” equals “bar”'. Note, I get an EN string even when the first calling context is FR (for example). This tells me that the translations just aren't even occurring. It is my theory that by the time I eval the lazy object, gettext is looking for the literal string "“foo” equals “bar”" (for example) in the translation catalog rather than something with placeholders and named values.
With this in mind, I've also tried wrapping the whole format() in the lazy object like this:
return _('“{key}” equals “{value}”'.format(key=self.key, value=self.value))
But it seems to have made zero difference. =/
I can get by with string_concat() for now, but sometimes, the placeholders will need to be moved around in some translations, so I'd like to figure this out.
I'm beginning to think that one simply cannot use placeholders with gettext_lazy.
NOTE: I have reviewed django: Translation with variables inside, but a) that has no accepted answer and b) he's using gettext, not gettext_lazy.
OK, the solution here is to provide an extra layer of laziness (Thanks, Django core dev: Florian Apolloner AKA “apollo13”).
Here's my modified function that WORKS:
from django.utils import six
from django.utils.functional import lazy
class MyModel(models.Model):
key = models.CharField(...)
value = models.CharField(...)
#property
def configuration_string(self):
def wrapper():
return _('“{key}” equals “{value}”').format(
key=self.key,
value=self.value
)
return lazy(
wrapper,
six.text_type
)
The only thing is, where I use this, I must remember to eval the wrapper function as follows:
from django.utils.encoding import force_text
config = my_model_instance.configuration_string
# NOTE: Evaluate the lazy function wrapper inside the force_text()
config_str = force_text(config())
Now, in my case, I need to support cases where 3rd party devs write the function configuration_string returning either the lazy function wrapper, a lazily evaluated translation string or just a regular string, so I use:
import types
from django.utils.encoding import force_text
from django.functional import Promise
config = my_model_instance.configuration_string
if isinstance(config, types.FunctionType):
config_str = force_text(config())
elif isinstance(config, Promise):
config_str = force_text(config)
else:
config_str = config
Thanks again to Apollo13 for guidance!
I had a very similar problem and found that using gettext_noop instead of gettext_lazy worked for me available since Django 1.11.

How to convert string to function reference in python

I have a class that transforms some values via a user-specified function. The reference to the function is passed in the constructor and saved as an attribute. I want to be able to pickle or make copies of the class. In the __getstate__() method, I convert the dictionary entry to a string to make it safe for pickling or copying. However, in the __setstate__() method I'd like to convert back from string to function reference, so the new class can transform values.
class transformer(object):
def __init__(self, values=[1], transform_fn=np.sum):
self.values = deepcopy(values)
self.transform_fn = transform_fn
def transform(self):
return self.transform_fn(self.values)
def __getstate__(self):
obj_dict = self.__dict__.copy()
# convert function reference to string
obj_dict['transform_fn'] = str(self.transform_fn)
return obj_dict
def __setstate__(self, obj_dict):
self.__dict__.update(obj_dict)
# how to convert back from string to function reference?
The function reference that is passed can be any function, so solutions involving a dictionary with a fixed set of function references is not practical/flexible enough. I would use it like the following.
from copy import deepcopy
import numpy as np
my_transformer = transformer(values=[0,1], transform_fn=np.exp)
my_transformer.transform()
This outputs: array([ 1. , 2.71828183])
new_transformer = deepcopy(my_transformer)
new_transformer.transform()
This gives me: TypeError: 'str' object is not callable, as expected.
You could use dir to access names in a given scope, and then getattr to retrieve them.
For example, if you know the function is in numpy:
import numpy
attrs = [x for x in dir(numpy) if '__' not in x] # I like to ignore private vars
if obj_dict['transform_fn'] in attrs:
fn = getattr(numpy, obj_dict['transform_fn'])
else:
print 'uhoh'
This could be extended to look in other modules / scopes.
If you want to search in the current scope, you can do the following (extended from here):
import sys
this = sys.modules[__name__]
attrs = dir(this)
if obj_dict['transform_fn'] in attrs:
fn = getattr(this, obj_dict['transform_fn'])
else:
print 'Damn, well that sucks.'
To search submodules / imported modules you could iterate over attrs based on type (potentially recursively, though note that this is an attr of this).
I think if you are asking the same question, I came here for.
The answer is simply use eval() to evaluate the name.
>>> ref = eval('name')
This is going to return what 'name' references in the scope where the eval is
executed, then you can determine if that references is a function.