The Idea is to invoke a single function to check the user input and return True || False.
User Input with 0123456789 must return
The Number Entered Correctly
User Input with 0123w456789 must return
Number is not allowed or Contains invalid input such as "w"
User Input with 0123wx456789 must return
Number is not allowed or Contains invalid input such as "wx"
My Code:
#include <iostream>
using namespace std;
int main ( )
{
string i_numvalidation;
cout << "Enter the number: " << '\n';
cin >> i_numvalidation;
bool isNumber = true;
for (int i = 0; i < i_numvalidation.length(); i++)
{
if (!(i_numvalidation[i] >= '0' && i_numvalidation [i] <= '9'))
{
isNumber = false;
}
}
if (isNumber)
cout << " Entered number " << i_numvalidation << " is correct" << '\n';
else
cout << " Entered number " << i_numvalidation << " is not allowed or Contains invalid input such as " << "'\n";
}
Question is Updated to understand it clearly.
You already have almost everything you need to get the desired output. You only need to remember the characters that make the input invalid (ie those for which you set isNumber = false;) in a second string and print that instead of the original input. Really the only ingredient that you are not already using in your code is adding a character to a string and that can be done like this:
std::string x;
char invalid_character = 'w';
char other_invalid_character = 'p';
x += invalid_charater;
x += other_invalid_character;
std::cout << x; // prints wp
The Functions I have Implemented is working for a single value but it is still not printing the complete invalid characters.
If the Input is 0123ab456789 so it will print the error message with "a" instead of "ab". It must print "ab" as input contains "ab".
The Code:
#include <iostream>
using namespace std;
int main ( )
{
string i_numvalidation;
cout << "Enter the Number: " << '\n';
cin >> i_numvalidation;
bool isNumber = true;
int bad_index = 0 ;
if (i_numvalidation [0] == '0')
isNumber = false;
for (int i = 0; i < i_numvalidation.length () && isNumber; i++ )
{
if (!(i_numvalidation [i] >= '0' && i_numvalidation [i] <= '9'))
{
isNumber = false;
bad_index = i ;
break;
}
}
if (isNumber)
{
cout << " The Entered " << i_numvalidation << " number is correct" << '\n';
}
else
cout << " The Entered " << i_numvalidation << " is not allowed or Contains invalid input such as '" << i_numvalidation [ bad_index ] << "'\n";
}
Like:
String err='1';
for(int i=0;i<i_numvalidation.length(); i++)
{
if(i_numvalidation[i]!= '0' || i_numvalidation[i]!= '1' || i_numvalidation[i]!= '2' and so on...)
{
err[err.length()]=i_numvalidation[i];
isNumber=false;
}
}
if(!isNumber)
cout<<"That's not a number bruh"<<err<<endl;
Sorry if I'm not helpful, I tried...
Hope you'll get the answer.
Related
I wanted to use only 1 and 0 for the binary. But instead the answer keep giving me the 2nd option with whatever number I typed. I had tried where did I programmed wrongly but unfortunately I still can't find it. So I hoped that I could get some help here.
#include<iostream>
#include<cmath>
using namespace std;
int DualzahlZuDezimal(long long n)
{
int dez = 0;
int i = 0, rem;
while (n != 0)
{
rem = n % 10;
n /= 10;
dez += rem * pow(2, i);
++i;
}
return dez;
}
string a;
int main()
{
long long n;
int dez;
cout << "Test Ein- und Ausgabe : \n";
cout << "----------------------- \n";
cout << "Eingabe einer Dualzahl : ";
cin >> n;
if ((n == '1') && (n == '0'))
{
cout << "Dual : " << n << endl;
cout << "Dezimal : " << DualzahlZuDezimal(n) << endl;
cout << "cin ok ? : ja-ok" << endl;
return 0;
}
else
{
cout << "Dual : 0" << endl;
cout << "Dezimal : 0" << endl;
cout << "cin ok ? : nein-nicht ok" << endl;
return 0;
}
}
If I understand this right, you want the user to enter a binary number, like 10001101001, and you will show the decimal equivalent (1129 in this case).
There are 2 general ways to do that yourself:
You can read the value as a number, as you do, and then apply your conversion
process, except that you check that rem is either 0 (in which case you do
nothing), or 1 (in which case you add the power of 2). If it's another value,
you report the error, and return 0.
You can read the value as a std::string instead. Then you can use
std::find_first_not_of()
to check for contents other than 0 or 1:
if (n.find_first_not_of("01") != string::npos) { /* complain */ }
but then you need to do the conversion based on characters.
But the best approach is not to reinvent the wheel and instead let the standard library handle it for you via stol():
#include <cstddef>
#include <iostream>
#include <string>
using namespace std;
int
main()
{
string text;
cout << "Enter a binary number: " << flush;
cin >> text;
size_t endpos = 0;
long decimal_number = stol(text, &endpos, 2); // base 2 == binary
if (endpos != text.size()) {
cerr << "'" << text << "' is not a valid binary number!" << endl;
return 1;
}
else {
cerr << "binary number: " << text << endl;
cerr << "decimal number: " << decimal_number << endl;
return 0;
}
}
Keep in mind that input from the console is text. If you need to check that the text matches a particular format (in this case, consists entirely of 1's and 0's), the simplest approach is to look at that text:
std::string input;
std::cin >> input;
bool input_is_valid = true;
for (int i = 0; input_is_valid && i < input.length(); ++i) {
if (input[i] != '0' && input[i] != '1')
input_is_valid = false;
}
then, if the input is valid, convert the text to a numeric value:
long long n = std::stoll(input);
This is a program that grade user inputs for the questions of Driver's License Exam.
I'm having trouble of validating the user input.
I'd like to accept the [ENTER] key as an invalid input and proceed to my validation rather than just go to an empty line and cannot process to the next question. Purpose is to send out error message and that no input is given and [ENTER] key is not valid input and only accept one more chance to enter valid input which are a/A, b/B, c/C, or d/D. So that is why I'm using if statement here instead of loop.
I tried if (testTakerAnswers[ans] == (or =) '\n') {} but still doesn't solve the problem of newline.
I include curses.h in here hope to use getch() statement from the other post but somehow I can't manage to work in my code with an array instead of regular input.
I'm looking for other methods as well rather than getch()
So should I adjust my bool function, or directly validate input in main() function.
#include <iostream>
#include <iomanip>
#include <string>
#include <cctype>
#include <curses.h>
using namespace std;
const unsigned SIZE = 20; // Number of qns in the test
char testTakerAnswers[SIZE]; //Array to hold test taker's answers
bool validateInput(char);
class TestGrader
{
private:
char answers[SIZE]; // Holds the correct answers // Answer is array
int getNumWrong (char[]);
void missedQuestions (char[]);
public:
void setKey(string); // Initialize object with standard keys
void grade(char[]); // Grades the answers from tester
};
void TestGrader::setKey(string key){
if (key.length()!=SIZE){
cout << "Error in key data.\n";
return;
}
for (unsigned pos = 0; pos < SIZE ; pos ++)
answers [pos] = key [pos];
}
void TestGrader::grade(char test[])
{
int numWrong = getNumWrong(test);
if (numWrong <= 5)
cout << "Congratulations. You passed the exam.\n";
else
cout << "You did not pass the exam. \n";
cout << "You got " << (SIZE-numWrong) << " questions correct. \n";
if (numWrong > 0){
cout << "You missed the following " << numWrong << " questions: \n";
missedQuestions(test);
}
}
int TestGrader::getNumWrong(char test[])
{
int counter = 0;
for (int i = 0; i < SIZE; i++){
if (answers[i] != toupper(testTakerAnswers[i])){
counter++;
}
}
return counter;
}
void TestGrader::missedQuestions(char test[])
{
// cout << testTakerAnswers[i]; This is to print taker's answers
int counter = 0;
for (int i = 0; i < SIZE; i++){
if (answers[i] != toupper(testTakerAnswers[i])){
cout << "\n" << i + 1 << ". Correct answers: " << answers[i];
counter++;
}
}
}
bool validateInput(char ans){ // Only A, B, C, D valid input
if (toupper(ans)!='A' && toupper(ans)!= 'B' && toupper(ans)!='C' && toupper(ans)!= 'D'){
cout << "\n********************WARNING*******************\n";
cout << "Invalid input! Enter only a/A, b/B, c/C, or d/D\n";
return false;
}
if (testTakerAnswers[ans] == '\n'){
return false;
}
return true;
}
int main()
{
const int NUM_QUESTIONS = 20;
string name; //Test taker's name
char doAnother; //Control variable for main processing loop
TestGrader DMVexam; //Create a TestGrader object
DMVexam.setKey("BDAACABACDBCDADCCBDA");
do {
cout << "Applicant Name: ";
getline(cin,name);
cout << "Enter answer for " << name << ".\n";
cout << "Use only letters a/A, b/B, c/C, and d/D. \n\n";
for (int i = 0; i < NUM_QUESTIONS; i++){
// Input and validate it
do{
cout << "Q" << i+1 << ": ";
cin >> testTakerAnswers[i];
if (!validateInput(testTakerAnswers[i])){
cout << "You get one more chance to correct.\nOtherwise, it count as wrong answer.";
cout << "\n*********************************************";
cout << "\nRe-enter: ";
cin >> testTakerAnswers[i];
cout << '\n';
break;
}
}while(!validateInput(testTakerAnswers[i]));
}
//Call class function to grade the exam
cout << "Results for " << name << '\n';
DMVexam.grade(testTakerAnswers);
cout << "\nGrade another exam (Y/N)? ";
cin >> doAnother;
while (doAnother != 'Y' && doAnother != 'N' && doAnother != 'y' && doAnother != 'n'){
cout << doAnother << " is not a valid option. Try Again y/Y or n/N" << endl;
cin >> doAnother;}
cout << endl;
cin.ignore();
}while(doAnother != 'N' && doAnother != 'n');
return 0;
}
Your issue is cin >> testTakerAnswers[i]; cin is whitespace delimited, that means that any whitespace (including '\n') will be discarded. So testTakerAnswers[i] can never be '\n'.
I'm not sure exactly what you want to do, but possibly try
getline(cin,input_string);
then
input_string == "A" | input_string == "B" | ...
So if only the enter key is pressed, input_string will become "".
I have to make a simple letter guessing game. So far I've finished almost everything but I'm not sure about what to do when it comes to one task.
So before the game begins it asks the user to input two things:
Enter the amount of different characters: (if 4 is entered for example, the letters chosen would be from A to the 4th letter, A-D only)
and
Enter the pattern length:
The pattern length input is working fine, but I'm having a tough time figuring out how to modify the generate code function to add the amount of different characters.
Any tips?
#include <iostream>
#include <random>
#include <string>
using namespace std;
size_t len;
string str;
void generate_code()
{
str.string::reserve(len);
random_device rd;
mt19937 gen{rd()};
uniform_int_distribution<char> dis{'A', 'Z'};
for (size_t i = 0; i < len; i++)
{
str += dis(gen);
}
}
void guess_checker()
{
string guess{};
size_t trial_count = 0, match_count = 0;
do
{
cout << "Enter your guess: " << endl;
cin >> guess;
if (guess.size() != len)
{
cout << "error: invalid guess" << endl;
}
else
{
match_count = 0;
for (size_t i = 0; i < len; i++)
{
if (guess[i] == str[i])
++match_count;
}
cout << "You guessed " << match_count << " character"
<< (match_count == 1 ? "" : "s") << " correctly." << endl;
}
++trial_count;
}
while (match_count != len);
cout << "You guessed the pattern in " << trial_count << " guess"
<< (trial_count == 1 ? "" : "es") << "." << endl;
}
int main()
{
int amount;
cout << "Enter the amount of different characters: ";
cin >> amount;
cout << "Enter the pattern length: ";
cin >> len;
generate_code();
guess_checker();
return 0;
}
Simply change your generator line to:
uniform_int_distribution<char> dis{'A', 'A' + amount - 1};
I would also recommend adding some validation beforehand, such as:
if (amount < 1 || amount > 26) {
cout << "Bad amount" << endl;
// exit or something
}
I have one of those basic assignments where you need to count the numbers of specific types of characters in an input file. There are 3 files involved, the main program (which I will include below), the hopper.txt input text to be analyzed, and the sample output.txt which demonstrates what the output should look like in the command line.
I believe I have everything set but my final numbers arnt turning out correctly. Specifically, my other and total counters are about 200 over. Now I've done some counting with other programs and am pretty sure that the sample output is correct which is why I suspect that I must be counting the hidden characters (and they must be there because the output isn't just a block of text).
I've tried casting each character to an int in order to see what its ascii value is and go off of that range but my IDE (Xcode) says that "comparison of constant with expression of type 'bool' is always true", and the check doesn't seem to catch anything.
Here are the other two files:
hopper.txt
sample output.txt
/***************************************************************
CSCI 240 Program 4 Summer 2013
Programmer:
Date Due: 7/14/14
Purpose: This program reads in the characters from a text file.
While reading them it takes cultivates relivant data about
the frequency of different ascii characters and shares its
results.
***************************************************************/
#include <iostream>
#include <iomanip>
#include <fstream>
#include <unistd.h>
#define FILENAME "/Users/username/Documents/NIU/240/Assigntment\ 4/hopper.txt"
using namespace std;
bool isVowel(char ch);
bool isConsonant(char ch);
int main()
{
ifstream inFile;
inFile.open (FILENAME, ios::in);
char ch;
int t_total = 0;
int t_vowel = 0;
int t_consonant = 0;
int t_letter = 0;
int t_leftParen = 0;
int t_rightParen = 0;
int t_singleQuote = 0;
int t_doubleQuote = 0;
int t_digit = 0;
int t_other = 0;
//See if we successfully imported the file
if (inFile.fail())
{
cout<< "\nThe file entitled: " << FILENAME << " failed to open.\n";
return 0;
}
do
{
//get next letter and print it out
inFile.get (ch);
cout << ch;
//increment total
t_total++;
//check if the character is a letter and if so if it is a vowel or consonant
if(isalpha(ch)){
t_letter++;
//we have found a letter
if(isVowel(ch)) {
t_vowel++;
//we have found a vowel
}
else if(isConsonant(ch)) {
t_consonant++;
//we have found a consonant;
}
else {
cout << "\nYou shouldnt be here...";
}
}
//check if the character is a digit
else if (isdigit(ch)) {
t_digit++;
//we have found a digit
}
//filter out formating characters
else if (!( 32 <= ((int)ch) <= 255)) {
continue;
}
//covers all other cases of askii characters
else {
switch(ch) {
case '(':
t_leftParen++;
break;
case ')':
t_rightParen++;
break;
case '\'':
t_singleQuote++;
break;
case '\"':
t_doubleQuote++;
break;
default:
t_other++;
break;
}
}
} while (inFile);
//These are really just here for the convience of not changing each value while working on formatting
int width1 = 25;
int width2 = 6;
//print out the totals found in the document
cout << "\n\nSummary\n";
cout << fixed << setw(width1) << "\nTotal characters:" << setw(width2) << right << t_total;
cout << fixed << setw(width1) << "\nVowels:" << setw(width2) << right << t_vowel;
cout << fixed << setw(width1) << "\nConsonants:" << setw(width2) << right << t_consonant;
cout << fixed << setw(width1) << "\nLetters:" << setw(width2) << right << t_letter;
cout << fixed << setw(width1) << "\nDigits:" << setw(width2) << right << t_digit;
cout << fixed << setw(width1) << "\nLeft parentheses:" << setw(width2) << right << t_leftParen;
cout << fixed << setw(width1) << "\nRight parentheses:" << setw(width2) << right << t_rightParen;
cout << fixed << setw(width1) << "\nSingle quotes:" << setw(width2) << right << t_singleQuote;
cout << fixed << setw(width1) << "\nDouble quotes:" << setw(width2) << right << t_doubleQuote;
cout << fixed << setw(width1) << "\nOther:" << setw(width2) << right << t_other;
return 0;
}
/***************************************************************
Function: isVowel
Use: Checks if the inputed character is a vowel.
Arguements: 1. ch: A askii character
Returns: true if it is a vowel, false if it is not
***************************************************************/
bool isVowel(char ch) {
//double check we have a letter
if(isalpha(ch)) {
//reduce to lower case to reduce the number of cases that must be checked
ch = tolower(ch);
if(ch == 'a' || ch == 'e' || ch == 'i' || ch == 'o' || ch == 'u') {
return true;
}
else {
return false;
}
}
return false;
}
/***************************************************************
Function: isConsonant
Use: Checks if the inputed character is a consonant.
Arguements: 1. ch: A askii character
Returns: true if it is a consonant, false if it is not
***************************************************************/
bool isConsonant(char ch) {
//So long as it is a letter, anything that is not a vowel must be a consonant
if(isalpha(ch)) {
return !isVowel(ch);
}
return false;
}
You can use std::isspace to test if a character is one of :
space (0x20, ' ')
form feed (0x0c, '\f')
line feed (0x0a, '\n')
carriage return (0x0d, '\r')
horizontal tab (0x09, '\t')
vertical tab (0x0b, '\v')
And ignore those by adding a test in your reading loop :
else if (std::isspace(ch)) {
continue; // Do not update counters
}
This bit of code works. I can also copy paste from start to end several times inside my main and it will still work.
int main()
{
string str;
cout << "Input a palindrome: "; // Start
getline(cin, str);
if (testPalindrome(str) == 1)
cout << "Your input is a palindrome: True" << endl;
else
cout << "Your input is a palindrome: False" << endl;
cout << endl; // End
cout << "\nCreated by,\nNorman Ettedgui" << endl;
system("pause");
return 0;
}
However this bit of code will not work and the error I get is a strings out of bound within my function (oddly enough before the function call).
This is my testPalindrome function:
bool testPalindrome(string str)
{
string newStr;
for (int i = 1; i < str.length() - 1; i++)
newStr += str[i];
if (newStr.length() > 1)
testPalindrome(newStr);
if (str[0] == str[str.length() - 1])
return true;
}
This is what I'm trying to run:
int main()
{
string str;
int i = 0;
while (i != -1)
{
cout << "Input a palindrome: ";
getline(cin, str);
if (testPalindrome(str) == 1)
cout << "Your input is a palindrome: True" << endl;
else
cout << "Your input is a palindrome: False" << endl;
cout << "-1 to Exit or any other number to continue: ";
cin >> i;
cout << endl;
}
cout << "\nCreated by,\nNorman Ettedgui" << endl;
system("pause");
return 0;
}
Try the following function
bool testPalindrome( string s)
{
return ( s.size() < 2 ? true
: s.front() == s.back() && testPalindrome( s.substr( 1, s.size() -2 ) ) );
}
Also in main substitute this statement
if (testPalindrome(str) == 1)
for
if ( testPalindrome(str) )
If you use getline and operator >> simultaneously then you should use ignore to skip ENTER key
(DO not forget include <limits>)
#include <limits>
while (i != -1)
{
cout << "Input a palindrome: ";
cin.ignore( numeric_limits<streamsize>::max() );
getline(cin, str);
//...
cin >> i;
cout << endl;
}
I will explain you why you got the error. Without statement with the call of ignore function getline read an empty string. So str was empty. In function testPalindrome there is statement
for (int i = 1; i < str.length() - 1; i++)
As for an empty string its length is equal to 0 then expression
str.length() - 1
has the maximum value for the unsigned type because the type of this expression is some unsigned integral type and the internal representation of -1 corresponds to the maximim unsigned value.
So variable i will be always less than -1 and you get memory access violation.
Also I would use another loop without using additional variable i.
while ( true )
{
cout << "Input a palindrome: ";
string str;
getline(cin, str);
if ( str.empty() ) break;
//...
}
if (newStr.length()>1) only handles the condition when newStr.length() is >1. You need an else statement to handle when the condition: if (newStr.length()>1) is false.