How can I store input after a comma as an integer? - c++

Question

I've been working on a program to display user input in a table and a histogram, I've got those down, but I can't figure out how to take the user input and separate it by a comma and save the first part as a string and the second as an integer. I used streams but it separates it by spaces and the string might need to have spaces in it, so that's not reliable. I also tried substrings but I need the second half to be an int. Any tips are appreciated. Thank you.
#include <iostream>
#include <string>
#include <vector>
#include <sstream>
#include <iomanip>
#include <ctype.h>
using namespace std;
int main() {
string title, col1, col2, userInput, one, two;
istringstream inSS;
string lineString;
string author;
int books;
vector<string> vecAuthors;
vector<int> vecBooks;
bool inputDone;
cout<<"Enter a title for the data:"<<endl;
getline(cin, title);
cout<<"You entered: "<<title<<endl;
cout<<"Enter the column 1 header:"<<endl;
getline(cin, col1);
cout<<"You entered: "<<col1<<endl;
cout<<"Enter the column 2 header:"<<endl;
getline(cin, col2);
cout<<"You entered: "<<col2<<endl;
while (!inputDone) {
cout<<"Enter a data point (-1 to stop input):"<<endl;
getline(cin, lineString);
while (lineString.find(',') == string::npos) {
if (lineString == "-1") {
break;
}
cout << "Error: No comma in string.\n" << endl;
cout << "Enter a data point (-1 to stop input):" << endl;
getline(cin, lineString);
}
string::size_type position = lineString.find (',');
if (position != string::npos)
{
while (lineString.find (',', position+1) != string::npos) {
if (lineString == "-1") {
break;
}
cout << "Error: Too many commas in input." << endl;
cout << "Enter a data point (-1 to stop input):" << endl;
getline(cin, lineString);
}
}
one = lineString.substr(0, lineString.find(','));
two = lineString.substr(lineString.find(',') + 1, lineString.size() - 1);
inSS.clear();
inSS.str(lineString);
inSS >> author;
inSS >> books;
if (inSS.fail()) {
if (lineString == "-1") {
break;
}
cerr << "Error: Comma not followed by an integer." << endl << endl;
cout << "Enter a data point (-1 to stop input):" << endl;
getline(cin, lineString);
}
inSS.clear();
inSS.str(lineString);
inSS >> author;
if (author == "-1") {
cout<<"Finished."<<endl;
inputDone = true;
}
else {
inSS >> books;
author.pop_back();
vecAuthors.push_back(author);
vecBooks.push_back(books);
cout << "Data string: " << author << endl;
cout << "Data integer: " << books << endl;
}
}
cout<<setw(33)<<right<<title<<endl;
cout<<setw(20)<<left<<col1<<"|";
cout<<setw(23)<<right<<col2<<endl;
cout<<setfill('-')<<setw(43)<<""<<endl;
cout<<setfill(' ');
for(int i=0; i<vecAuthors.size(); ++i){
cout<<setw(20)<<left<<vecAuthors[i]<<"|"<<setw(23)<<right<<vecBooks[i]<<endl;
}
cout<<endl;
for(int i=0; i<vecAuthors.size(); ++i){
cout<<setw(20)<<right<<vecAuthors[i];
for(int k = 0; k<vecBooks[i]; ++k) {
cout<<left<<"*";
}
cout<<endl;
}
return 0;
}

Answer 1

Code to get the first part to a string and second part to an int:
#include <iostream>
#include <string>
int main()
{
std::string input{};
std::cin >> input;
int commaSlot{};
for (int i = 0; i < input.length(); i++) {
if (input[i] == ',') {
commaSlot = i;
break;
}
}
std::string firstPart = input.substr(0,commaSlot);
int secondPart = std::stoi(input.substr(commaSlot+1));
std::cout << firstPart << " " << secondPart;
}

Answer 2

because what you need is quite custom (you need comma as a separator and not space ) you can get a line and parse it as you want with the getline function of std afterwards you can separate the string on the comma (the simplest way I can think off is a simple for loop but you can use std's algorithm's also) and then you can use the stoi function to convert a string to an int ,all of them together:
std::string row{};
unsigned positionofcomma{};
std::getline(std::cin,row);
for (unsigned i=0;i<row.length();i++)
if (row[i]==','){
positionofcomma=i;
break;
}
std::string numberstring=row.substr(positionofcomma+1, row.length());
int number=std::stoi(numberstring);