This question already has answers here:
RegEx validation of decimal numbers with comma or dot
(6 answers)
How to extract decimal number from string in C#
(7 answers)
Closed 2 years ago.
I've custom regex where I match float numbers.
Regex:
/[0-9]*\,?[0-9]*\.?[0-9]*/m
When I tried with string 1,5$+absd1.5a get 10 matches on result where 1 match == 1,5 and 8 match = 1.5. Other matches is empty. How I can match without empty results?
Demo
https://regex101.com/r/jnhsly/1
Related
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Comma Separated Numbers Regex
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Regular Expression to match dot separated list with no dot on the end and allow asterisk at the end
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c++ regexp allowing digits separated by dot
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Closed 4 months ago.
/^[0-9][0-9-.]*[0-9]+$/u
I am trying to match with these like codes:
1.11122.5454.545
55
555.55
65656.75454
Not 111..444 and not 44545...444
How can I stop more than 1 dots between numbers
This question already has answers here:
Understanding the negated character class
(3 answers)
Negative lookahead in regex to exclude percentage (%) in R
(3 answers)
Closed 2 years ago.
I have the string '05/'. If I write the pattern \d+[^\/]{1}, why does it still match the '05' part of the string? Shouldn't it be fully rejected since there is no match on the 3rd char requirement?
This question already has answers here:
Match exact string
(3 answers)
Closed 4 years ago.
Hi this is my example 0xc1e5017fbc68aa3e56aa580708de9aa123d62d18
This is my reg ex ^0x[a-fA-F0-9]{1,40}. What I'm doing is 0x which is compulsory after that we can enter upto 40 alpha numeric digits. But not special characters. What should I do here so it will match correctly?
Your issue is that you need to assert where the string ends, or else you will match up until a special character is found, and get undesired matches.
So with your current regex and test string 0xc1!, 0xc1 would be matched, even though it is an invalid match.
How about using: ^0x[a-fA-F0-9]{1,40}$
This question already has answers here:
PHP: RegEx for string with 3-9 letters and 5-50 numbers
(2 answers)
Closed 5 years ago.
I want to match a string that has the following requirements:
The string contains 5 to 10 digits. [0-9]
Contains 2 to 3 letters. [a-z]
for example
123a2bc12
s123d456
This is my regular expression. /^\d*[a-z]\d*[a-z]\d*[a-z]?\d*$/. But this can only limit the number of letters.
It isn't pretty but this should be what you're looking for:
^(?=(?:[^a-zA-Z]*[a-zA-Z]){2,3}[0-9]*$)(?=(?:[^0-9]*[0-9]){5,10}[A-Za-z]*$).*$
I think you want to this
s=re.search(r'(\w+)','123a2bc12').group(1)
print s #The output is '123a2bc12'
This question already has answers here:
Regular expression to get last 3 characters of a string
(2 answers)
Closed 5 years ago.
how to get last 3 or 5 digits from this given one using regex
4c113866bc43e2be48bbf85be829d7bc
Use $ anchor to mark the end of the string:
.{3,5}$
3 above is the min number of characters to match; 5 is max.