how to find keyword in string in c++ - c++

Question

When you use a specific keyword, it is a matter of printing out all the words that contain that keyword. You shouldn't use arrays in solving problems.
I used the find() function to get the code that prints from the starting index of the keyword until ',' appears, but there is an error.
Here is the code:
#include <iostream>
#include <string>
#include <limits.h>
using namespace std;
int main() {
string data = "사랑,프로그래머,의자,사랑의바보,영통역,천년의사랑,냉장고,객체지향";
string keyword;
cout << "키워드 : ";
cin >> keyword;
int i = 0;
while (1) {
i = data.find(keyword, i);
if (i == INT_MAX) return 0;
while (data[i] != ',') {
cout << data[i] << " ";
i++;
}
}
}
Even if it compiles successfully, if the keyword is after the word, it cannot be printed.
In summary, my questions are:
Problems in the above code, assuming the keyword is in front of the word.
Idea to print the word even when the keyword is behind it.

Answer 1

std::string::find returns std::string::npos if it doesn't find anything.
The result is of type std::size_t and not int: std::size_t i = 0;
The inner while loop goes out of bounds after the last word: while (i < data.length() && data[i] != ',')
#include <iostream>
#include <string>
using namespace std;
int main() {
string data = "사랑,프로그래머,의자,사랑의바보,영통역,천년의사랑,냉장고,객체지향";
string keyword;
cout << "키워드 : ";
cin >> keyword;
std::size_t i = 0;
while (1) {
i = data.find(keyword, i);
if (i == std::string::npos) return 0;
while (i < data.length() && data[i] != ',') {
cout << data[i] << " ";
i++;
}
}
}