How to use Conditions in switch case in c++? - c++

Question

Is there any way I can use a switch-case statement based on the answer of condition?
For example: if a percentage is greater than 90 then by using the switch statement, it should print grade A?

Answer 1

You can do something like,
#include<iostream>
#include<string>
int main()
{
int n;
std::cout<<"Enter Mark:";
std::cin>>n;
n=n>90;
switch(n)
{
case 1:
std::cout<<"Grade A";
break;
case 0:
std::cout<<"Grade B";
break;
}
return 0;
}
or if you have more than two
#include<iostream>
#include<string>
// <50 is c , 50 - 90 is b, >90 is a
int main()
{
int n;
std::cout<<"Enter Mark:";
std::cin>>n;
n=(n>50?(n>90?1:2):3);
switch(n)
{
case 1:
std::cout<<"Grade A";
break;
case 2:
std::cout<<"Grade B";
break;
case 3:
std::cout<<"Grade C";
break;
}
return 0;
}

Answer 2

#include <iostream>
using namespace std;
int main()
{
double physics,chemistry,biology,computer,math,totalMarks,obtainMarks,percentage;
char grade;
cout<<"Enter Total Marks=";
cin>>totalMarks;
cout<<"Enter Marks of Physics=";
cin>>physics;
cout<<"Enter Marks of chemistry=";
cin>>chemistry;
cout<<"Enter Marks of biology=";
cin>>biology;
cout<<"Enter Marks of computer=";
cin>>computer;
cout<<"Enter Marks of Mathematics=";
cin>>math;
obtainMarks=physics+chemistry+biology+computer+math;
percentage=(obtainMarks/totalMarks)*100;
grade=percentage>=90?'A':(percentage>=80?'B':(percentage>=70?'C':(percentage>=60?'D':(percentage>=40?'E':'F'))));
switch(grade)
{
case 'A' : cout<<"you have got A grade";
break;
case 'B': cout<<"you have got B grade";
break;
case 'C': cout<<"you have got C grade";
break;
case 'D': cout<<"you have got D grade";
break;
case 'E': cout<<"you have got E grade";
break;
case 'F': cout<<"you have got F grade";
break;
}
return 0;
}
done!