Related
I'm using the scite text editor (I cannot make use of any IDE or compiler since I'm required to also utilize Makefiles which is only possible if I use some sort of text editor) for all of my coding in c++. However, I'm consistently facing the same challenge; the text editor (I've attempted this on multiple ones including codepad and sublime text) isn't reading any input from the keyboard. Here is the source code:
#include <iostream>
#include <iomanip>
using namespace std;
const int SIZE_OF_ARRAY = 5;
int main(){
int x, y;
int counter = 0;
int elements[SIZE_OF_ARRAY];
cout << "Please enter a number ";
cin >> x;
cin.ignore();
cout << "Please enter a choice ";
cin >> y;
if(y == 1){
for(int i = 0; i < SIZE_OF_ARRAY; i++)
elements[i] = -1*SIZE_OF_ARRAY + x;
for(int j = 0; j < SIZE_OF_ARRAY; j++)
cout << elements[j] << " ";
}
else if(y == 2){
for(int i = 0; i < SIZE_OF_ARRAY; i++){
if(i == 0)
elements[i] = -1*x;
else{
elements[i] = elements[i-1] + 1;
}
}
for(int j = 0; j < SIZE_OF_ARRAY; j++)
cout << elements[j] << " ";
}
else if(y == 3){
for(int i = 0; i < SIZE_OF_ARRAY; i++){
counter++;
elements[i] = 7*x*counter;
}
for(int j = 0; j < SIZE_OF_ARRAY; j++)
cout << elements[j] << " ";
}
}
The program is supposed to take as an input any number from the user and, depending on a numeric choice (between one and three) entered by the user, manipulate the value first entered somehow.
Choice one (User picks first choice)
The program negates the size of the array and adds the number which the user first entered and fills the array with the resulting value.
Choice Two (User picks second choice)
The program negates the number entered by the user, places this in the first array location then each successive element is added one unit more than the previous one.
Choice Three (User picks third choice)
Fills the array with the first five multiples of seven. Then shifts each number by a factor equivalent to the number the user had first entered.
I've ran it on an IDE (Codeblocks) and it works perfectly well. However, on any text editor, the 'cout' statements are printed with the variables x and y taken to each be equal to zero rather than being set to the value entered from the keyboard. It doesn't even allow any keyboard input. Any answer regarding how I can fix this would be immensely appreciated.
Hoosain, continuing from the comments above, when you use an IDE, you must configure the path to your compiler as well as all compiler options you wish to use, and the location for the resulting executable and object files, etc. When you used CodeBlocks on windows, you essentially got lucky that CodeBlocks will automatically detect whether MinGW is installed and set its compiler configuration to allow you to build and run your code without you having to configure the compiler details. Geany is another editor that does a good job auto-detecting and using MinGW.
For the remaining IDE's it is up to you to configure them to find and use the compiler you have installed (MinGW), as well as configuring all desired compiler options (at minimum enable compiler warning with -Wall -Wextra).
That is where new programmers who have only used an IDE configured for them run into problems... Before you can tell an IDE where your compiler is located and which compiler options you want to use, you have to know where you compiler is located and understand what minimum set of compiler options you should use.
The way you learn to use a compiler is with the good old command line. (yep, that's cmd.exe on windows, often labeled as the "DOS Prompt" in earlier versions) An IDE is just a front-end to your compiler that executes the same commands you can simply enter on the command line to compile your program.
Learning how to use your compiler will save you an incredible amount of time when learning to code. You can simply open a command prompt and compile any file you wish, without setting up a project, etc.. When learning to code, trying to shoehorn small examples into an IDE is much more time consuming and often more trouble than it is worth. Rather than worry how to use an IDE, focus on "how to use your compiler" first.
Since you have MinGW installed on windows, all you have to do to be able to compile from the command prompt is add the path to the MinGW bin directory to your User Environment. You do that by adding the PATH as an Environment Variable here:
Start Menu-> (rt-click on Computer)-> Properties->
Advanced System Settings-> (Advanced tab)-> Environment Variables
In the Top window (your user variables), click to add (or edit) the PATH "Variable name". Generally, if you installed MinGW in the default location, you simply add the path as the "Variable value":
c:\MinGW\bin;c:\MinGW\mingw32\bin
(verify the path on your computer)
(note: windows separates path components by the semi-colon, so if there is already a PATH variable set, just add a semi-colon between what is there and what you add. Also if you already have a command prompt open, you must close it and open it again for the new path to take effect) Just open Start Menu-> Accessories-> Command Prompt (you can rt-click on the icon (top-left) and choose Properties to set the font (recommend Lucida Console 12) and height/width)
Now you have configured your command prompt to allow you to compile any file at any location within your filesystem. For example, I tested with the code you posted (I modified it to add prompts for the information). Compiling it is a piece of cake. I keep my executables in a bin directory to keep sources and binaries separate.
I named your file array_get.cpp.
Compile
Then just enter the normal g++ compiler command, and at minimum use -Wall -Wextra options to enable compiler warnings (you can add -pedantic and whatever additional warnings you want, I would recommend at least adding -Wshadow so your compiler will warn on any variables you declare in multiple scopes that could conflict). The -o option allows you to specify the location of the executable (I just use a separate bin directory as explained above). So to compile and link your code into bin\array_get.exe all I have to enter is:
C:\Users\david\Documents>g++ -Wall -Wextra -o bin\array_get array_get.cpp
(do not accept code until it compiles without warning -- read any warning (it gives line of problem), understand what it is telling you, and go fix it)
Example Use/Output
C:\Users\david\Documents>bin\array_get.exe
Please enter a number: 21
Please enter a choice (1-3): 3
147 294 441 588 735
That's it. Since MinGW uses gcc, the compiler commands you use on windows are the exact same you would use in Linux, so learning to compile from the command line pays double-benefit.
Now you have the luxury of using any text-editor to edit your code while you have the command prompt simply and easily re-compile as you wish until your code is correct. No project dialogs, no mess of a different folder for every file, just the freedom to compile any file you wish -- right from the command line. (I actually separate my sources in directory by type, e.g. c, cpp), you find what works best for your. I also use a simple bat file that takes the exename and source.cpp names as arguments and then compiles with the options I set -- it just cuts down on typing :)
Further, since you now where your compiler is located, and which options to use, you can open the Settings window on any IDE and set the appropriate compiler command and compiler options to allow the IDE compile your code for you. Give it a try, and let me know if you have further questions.
This is a probably an embarasing question as no doubt the answer is blindingly obvious.
I've used Visual Studio for years, but this is the first time I've done any 'Console Application' development.
When I run my application the console window pops up, the program output appears and then the window closes as the application exits.
Is there a way to either keep it open until I have checked the output, or view the results after the window has closed?
If you run without debugging (Ctrl+F5) then by default it prompts your to press return to close the window. If you want to use the debugger, you should put a breakpoint on the last line.
Right click on your project
Properties > Configuration Properties > Linker > System
Select Console (/SUBSYSTEM:CONSOLE) in SubSystem option or you can just type Console in the text field!
Now try it...it should work
Starting from Visual Studio 2017 (15.9.4) there is an option:
Tools->Options->Debugging->Automatically close the console
The corresponding fragment from the Visual Studio documentation:
Automatically close the console when debugging stops:
Tells Visual Studio to close the console at the end of a debugging session.
Here is a way for C/C++:
#include <stdlib.h>
#ifdef _WIN32
#define WINPAUSE system("pause")
#endif
Put this at the top of your program, and IF it is on a Windows system (#ifdef _WIN32), then it will create a macro called WINPAUSE. Whenever you want your program to pause, call WINPAUSE; and it will pause the program, using the DOS command. For other systems like Unix/Linux, the console should not quit on program exit anyway.
Goto Debug Menu->Press StartWithoutDebugging
If you're using .NET, put Console.ReadLine() before the end of the program.
It will wait for <ENTER>.
try to call getchar() right before main() returns.
(/SUBSYSTEM:CONSOLE) did not worked for my vs2013 (I already had it).
"run without debugging" is not an options, since I do not want to switch between debugging and seeing output.
I ended with
int main() {
...
#if _DEBUG
LOG_INFO("end, press key to close");
getchar();
#endif // _DEBUG
return 0;
}
Solution used in qtcreator pre 2.6. Now while qt is growing, vs is going other way. As I remember, in vs2008 we did not need such tricks.
just put as your last line of code:
system("pause");
Here's a solution that (1) doesn't require any code changes or breakpoints, and (2) pauses after program termination so that you can see everything that was printed. It will pause after either F5 or Ctrl+F5. The major downside is that on VS2013 Express (as tested), it doesn't load symbols, so debugging is very restricted.
Create a batch file. I called mine runthenpause.bat, with the following contents:
%1 %2 %3 %4 %5 %6 %7 %8 %9
pause
The first line will run whatever command you provide and up to eight arguments. The second line will... pause.
Open the project properties | Configuration properties | Debugging.
Change "Command Arguments" to $(TargetPath) (or whatever is in "Command").
Change "Command" to the full path to runthenpause.bat.
Hit OK.
Now, when you run, runthenpause.bat will launch your application, and after your application has terminated, will pause for you to see the console output.
I will post an update if I figure out how to get the symbols loaded. I tried /Z7 per this but without success.
add “| pause” in command arguments box under debugging section at project properties.
You could run your executable from a command prompt. This way you could see all the output. Or, you could do something like this:
int a = 0;
scanf("%d",&a);
return YOUR_MAIN_CODE;
and this way the window would not close until you enter data for the a variable.
Just press CNTRL + F5 to open it in an external command line window (Visual Studio does not have control over it).
If this doesn't work then add the following to the end of your code:
Console.WriteLine("Press any key to exit...");
Console.ReadKey();
This wait for you to press a key to close the terminal window once the code has reached the end.
If you want to do this in multiple places, put the above code in a method (e.g. private void Pause()) and call Pause() whenever a program reaches a possible end.
A somewhat better solution:
atexit([] { system("PAUSE"); });
at the beginning of your program.
Pros:
can use std::exit()
can have multiple returns from main
you can run your program under the debugger
IDE independent (+ OS independent if you use the cin.sync(); cin.ignore(); trick instead of system("pause");)
Cons:
have to modify code
won't pause on std::terminate()
will still happen in your program outside of the IDE/debugger session; you can prevent this under Windows using:
extern "C" int __stdcall IsDebuggerPresent(void);
int main(int argc, char** argv) {
if (IsDebuggerPresent())
atexit([] {system("PAUSE"); });
...
}
Either use:
cin.get();
or
system("pause");
Make sure to make either of them at the end of main() function and before the return statement.
You can also use this option
#include <conio.h>
/* run this program using the console pauser or add your own getch, system("pause") or input loop */
int main() {
.
.
.
getch();
return 0;
}
In my case, i experienced this when i created an Empty C++ project on VS 2017 community edition. You will need to set the Subsystem to "Console (/SUBSYSTEM:CONSOLE)" under Configuration Properties.
Go to "View" then select "Property Manager"
Right click on the project/solution and select "Property". This opens a Test property page
Navigate to the linker then select "System"
Click on "SubSystem" and a drop down appears
Choose "Console (/SUBSYSTEM:CONSOLE)"
Apply and save
The next time you run your code with "CTRL +F5", you should see the output.
Sometimes a simple hack that doesnt alter your setup or code can be:
Set a breakpoint with F9, then execute Debug with F5.
Since running it from VS attaches the VS debugger, you can check for an attached debugger:
if (Debugger.IsAttached)
{
Console.WriteLine("Debugger is attached. Press any key to exit.");
Console.ReadKey();
}
I guess the only caveat is that it'll still pause if you attach any other debugger, but that may even be a wanted behavior.
Use Console.ReadLine() at the end of the program. This will keep the window open until you press the Enter key. See https://learn.microsoft.com/en-us/dotnet/api/system.console.readline for details.
Visual Studio 2015, with imports. Because I hate
when code examples don't give the needed imports.
#include <iostream>;
int main()
{
getchar();
return 0;
}
Currently there is no way to do this with apps running in WSL2. However there are two work-arounds:
The debug window retains the contents of the WSL shell window that closed.
The window remains open if your application returns a non-zero return code, so you could return non-zero in debug builds for example.
It should be added that things have changed since then. On Windows 11 (probably 10, I can't check any more) the new Terminal app that now houses the various console, PowerShell and other sessions has its own settings regarding closing. Look for it in Settings > Defaults > Advanced > Profile termination behavior.
If it's set to close when a program exits with zero, then it will close, even if VS is told otherwise.
Go to Setting>Debug>Un-check close on end.
Lately, I've been trying to learn C++ from this website. Unfortunately whenever I try to run one of the code samples, I see that program open for about a half second and then immediately close. Is there a way to stop the program from closing immediately so that I can see the fruits of my effort?
If you are using Visual Studio and you are starting the console application out of the IDE:
pressing CTRL-F5 (start without debugging) will start the application and keep the console window open until you press any key.
Edit: As Charles Bailey rightly points out in a comment below, this won't work if there are characters buffered in stdin, and there's really no good way to work around that. If you're running with a debugger attached, John Dibling's suggested solution is probably the cleanest solution to your problem.
That said, I'll leave this here and maybe someone else will find it useful. I've used it a lot as a quick hack of sorts when writing tests during development.
At the end of your main function, you can call std::getchar();
This will get a single character from stdin, thus giving you the "press any key to continue" sort of behavior (if you actually want a "press any key" message, you'll have to print one yourself).
You need to #include <cstdio> for getchar.
The solution by James works for all Platforms.
Alternatively on Windows you can also add the following just before you return from main function:
system("pause");
This will run the pause command which waits till you press a key and also displays a nice message Press any key to continue . . .
If you are using Microsoft's Visual C++ 2010 Express and run into the issue with CTRL+F5 not working for keeping the console open after the program has terminated, take a look at this MSDN thread.
Likely your IDE is set to close the console after a CTRL+F5 run; in fact, an "Empty Project" in Visual C++ 2010 closes the console by default. To change this, do as the Microsoft Moderator suggested:
Please right click your project name and go to Properties page, please expand Configuration Properties -> Linker -> System, please select Console (/SUBSYSTEM:CONSOLE) in SubSystem dropdown. Because, by default, the Empty project does not specify it.
I usually just put a breakpoint on main()'s closing curly brace. When the end of the program is reached by whatever means the breakpoint will hit and you can ALT-Tab to the console window to view the output.
Why not just run the program from a console ie run the program from cmd.exe if you're using Windows. That way the window stays open after the program finishes.
[EDIT]: When I use KDevelop4 there is a fully fledged instance of Bash (a Linux CLI) running in a tab at the bottom of the IDE. Which is what I use in these sort of circumstances.
Before the end of your code, insert this line:
system("pause");
This will keep the console until you hit a key.
#include <iostream>
#include <string>
using namespace std;
int main()
{
string s;
cout << "Please enter your first name followed by a newline\n";
cin >> s;
cout << "Hello, " << s << '\n';
system("pause"); // <----------------------------------
return 0; // This return statement isn't necessary
}
Call cin.get(); 2 times:
//...
cin.get();
cin.get();
return 0
}
If you run your code from a competent IDE, such as Code::Blocks, the IDE will manage the console it uses to run the code, keeping it open when the application closes. You don't want to add special code to keep the console open, because this will prevent it functioning correctly when you use it for real, outside of the IDE.
I just do this:
//clear buffer, wait for input to close program
std::cin.clear(); std::cin.ignore(INT_MAX, '\n');
std::cin.get();
return 0;
Note: clearing the cin buffer and such is only necessary if you've used cin at some point earlier in your program. Also using std::numeric_limits::max() is probably better then INT_MAX, but it's a bit wordy and usually unnecessary.
Okay I'm guessing you are on Windows using Visual Studio... why? Well because if you are on some sort of Linux OS then you'd probably be running it from the console.
Anyways, you can add crap to the end of your program like others are suggesting, or you can just hit CTRL + F5 (start without debugging) and Visual Studio will leave the console up once complete.
Another option if you want to run the Debug version and not add crap to your code is to open the console window (Start -> Run -> cmd) and navigate to your Debug output directory. Then, just enter the name of your executable and it will run your debug program in the console. You can then use Visual Studio's attach to process or something if you really want to.
Just add the following at the end of your program. It will try to capture some form of user input thus it stops the console from closing automatically.
cin.get();
If you are actually debugging your application in Visual C++, press F5 or the green triangle on the toolbar. If you aren't really debugging it (you have no breakpoints set), press Ctrl+F5 or choose Start Without Debugging on the menus (it's usually on the Debug menu, which I agree is confusing.) It will be a little faster, and more importantly to you, will pause at the end without you having to change your code.
Alternatively, open a command prompt, navigate to the folder where your exe is, and run it by typing its name. That way when it's finished running the command prompt doesn't close and you can see the output. I prefer both of these methods to adding code that stops the app just as its finished.
Add the following lines before any exit() function or before any returns in main():
std::cout << "Paused, press ENTER to continue." << std::endl;
cin.ignore(100000, "\n");
For Visual Studio (and only Visual Studio) the following code snippet gives you a 'wait for keypress to continue' prompt that truly waits for the user to press a new key explicitly, by first flushing the input buffer:
#include <cstdio>
#include <tchar.h>
#include <conio.h>
_tprintf(_T("Press a key to continue "));
while( _kbhit() /* defined in conio.h */ ) _gettch();
_gettch();
Note that this uses the tchar.h macro's to be compatible with multiple 'character sets' (as VC++ calls them).
Use #include "stdafx.h" & system("pause"); just like the code down below.
#include "stdafx.h"
#include <iostream>
using namespace std;
int main()
{
std::cout << "hello programmer!\n\nEnter 2 numbers: ";
int x, y;
std::cin >> x >> y;
int w = x*y;
std::cout <<"\nyour answer is: "<< w << endl;
system("pause");
}
simply
#include <cstdio>
int main(){
// code...
std::getchar();
std::getchar();
return 0;
}
for some reason there is usually 1 character possible to read with getchar already in stdin when you run a program. so the first getchar reads this character, and the second getchar waits for user (your) input before exiting the program. And after a program exits most of terminals, especially on Windows close terminal immediately.
so what we aim to is a simple way of preventing a program from finishing after it outputs everything.
Of course there are more complex and clean ways to solve this, but this is the simplest.
Similar idea to yeh answer, just minimalist alternative.
Create a batch file with the following content:
helloworld.exe
pause
Then use the batch file.
See if your IDE has a checkbox in project setting to keep the window open after the program terminates. If not, use std::cin.get(); to read a character at the end of main function. However, be sure to use only line-based input (std::getline) or to deal with leftover unread characters otherwise (std::ignore until newline) because otherwise the .get() at the end will only read the garbage you left unread earlier.
This seems to work well:
cin.clear();
cin.ignore(2);
If you clear the buffer first it won't be a problem when you read the next one.
For some reason cin.ignore(1) does not work, it has to be 2.
You could always just create a batch file. For example, if your program is called helloworld.exe, some code would be:
#echo off
:1
cls
call helloworld.exe
pause >nul
goto :1
If you are running Windows, then you can do system("pause >nul"); or system("pause");. It executes a console command to pause the program until you press a key. >nul prevents it from saying Press any key to continue....
I'm putting a breakpoint at the last return 0 of the program. It works fine.
I used cin.get() and that is worked but one day I needed to use another cin.get([Array Variable]) before that to grab a ling string with blank character in middle of. so the cin.get() didn't avoid command prompt window from closing. Finally I found Another way:
Press CTRL+F5 to open in an external window and Visual Studio does not have control over it anymore. Just will ask you about closing after final commands run.
I tried putting a getchar() function at the end. But it didn't work. So what I did was add two getchar() functions one after another. I think the first getchar() absorbs the Enter key you press after the last data input. So try adding two getchar() functions instead of one
Instead of pressing the run button, press CTRL and F5 at the same time, it will give you the press any key to continue message. Or type "(warning use this only for testing not actual programs as an antiviruses don't like it!!!!)" at the end of your main function but: (warning use this only for testing not actual programs as an antiviruses don't like it!!!!)
just use cin.ignore() right before return 0; twice
main()
{
//your codes
cin.ignore();
cin.ignore();
return 0;
}
thats all
you can try also doing this
sleep (50000);
cout << "any text" << endl;
This will hold your code for 50000m, then prints message and closes. But please keep in mind that it will not pause forever.
Here's a problem, not so obvious. Somehow I had added a debug breakpoint at the very last line of my program. } Not sure how I did that, perhaps with an erroneous mouse click while jumping between different screens. I'm working in VS Code.
And when I go to debug, the system jumps immediately to that breakpoint. No error message, no interim output, nothing. I'm like, how did the program rush thru all my set breakpoints? This took too long to figure out.
Apparently the system sees that last line breakpoint as a "first" stop. The simple fix? Delete that breakpoint, doh! (insert forehead slap here.)
All you have to do set a variable for x then just type this in before the return 0;
cout<<"\nPress any key and hit enter to end...";
cin>>x;
Shouldn't this work? I mean, the code is merely a test and is meant so that the dialogue goes this way : What is your name? name here, Hello name here, and yet it does not show the last line of Hello after I type in my name and click enter it just dissapears. Here is the code.
#include <iostream>
#include <string>
int main (void)
{
using std::cin;
using std::cout;
using std::string;
string name = "";
cout << "What is your name, pls?\n";
cin >> name;
cout << "\nHello " << name.c_str() << "\n";
return 0;
}
My guess is that you are running from the debugger, or double clicking the executable. In either of those cases, when the program ends, the console will close. So, the program produced output, but you just could not see it before the console closed.
Run the program from a pre-existing console so that the console remains after your program ends. Or, just whilst debugging, arrange that your program does not terminate immediately after emitting its final output. A simple way to do that is to place a break point at the end of the program.
It probably showed it right before it disappeared. If you're going to write console programs, and if you're going to send output to a console, you should run them from a console so the output has some place to go.
After you are done with your program, press Ctrl + F5 ( Run without debugging). This will prompt before closing the window and this is what you want.
Make sure you put a breakpoint before main goes out of scope. I guess your console disappears under VS?
Also, you don't need to extract the char* in the last cout statement:
cout << "\nHello " << name << endl;
Open a terminal (or a command prompt window).
Navigate to the folder that contains the executable.
Run it.
It's not disappearing. It is just running really fast.
Every IDE has a keyboard shortcut that allows you to run code and pause after the execution has finished.
This keyboard shortcut is Ctrl-F5 in Visual Studio.
I have no idea what IDE you're running, but that is your basic problem.
The other thing you can do is to test your code in ideone : ideone.com/hb4Cel (it's the same code. There is no point pasting it here)
A dirty workaround is to add something like this
cin >> name;
at the end, just before return 0;. It forces the window to wait for input (i.e. hitting return) before returning (which closes the program).
This isn't necessarily good design, but if all you want to do is run some tests then it'll do the trick.
Basically when you enter your name it displays your last line and exits after return 0.
Here are the following things to avoid that
1- use command line to run the application
Start->accessories->command prompt
Go to folder in which your application is using cd command
c:>cd c:\path\foldername
Now run the application by typing the program name e.g
c:\path\foldername>my_application.exe
It will display your last line.
2- Now if your are using microsoft visual c++ press ctrl+F5 to run your program
3- This is not recommended but you an use it as long as your are debugging then remove it from the code afterwards. Include conio.h header file and add getch(); line before return statement. It would hold the screen for you till you press a key.
I'm trying my hand at c++ and am using fedora eclipse (3.4.2) as my IDE.
At the moment I'm trying to enter a string of numbers into the console, get the program to sort them and spit them back out. The program is straight out of a book and works with xcode and through a normal terminal - so I know it's correct.
Basically I run the program and enter a few numbers into the eclipse console, the numbers are coloured green so I know its accepting the input correctly.
When I hit enter, the console jumps to a new line and nothing happens. When I press control+shift+D, nothing happens. When I press control+d, nothing happens.
I use eclipse for python too, and the console works properly. Just hitting enter inputs data to the program.
Am I missing something here? I've spent the last half hour or so trying to figure this out. Can anyone help me? Thanks.
What version of ecplise and what complier are you using? The following worked for me on Eclipse Ganymede with GCC version 3.4.5:
#include <iostream>
using namespace std;
int main() {
int x = 0;
cout << "Type your input here:";
cin >> x ;
cout << "You entered " << x << endl;
return 0;
}
How does your program know that input has ended? It sounds like it accepts multiple lines of input in the console window. Isn't there some magic case that pops you out of that loop so you can process the input that's been collected?
As other said, without the code there's no answer.