My program will repeat output: "You are currently on the 2 floor out of 5
The sum of the codes is: 7 and the product of the codes is: 12
Try again before he catches onto you!"
Based on how many wrong characters are added how can I fix this? I have inserted the cin.clear and cin.ignore but it will repeat the part above.
i.e. if I type wasds it will repeat 5x. Any other notes are also appreciated.
#include <iostream>
#include <ctime>
using namespace std;
int PlayerLevel = 0;
int MaxLevel = 5;
bool GamePlay ()
{
srand(time(NULL));
int PlayerGuessA, PlayerGuessB, PlayerGuessC;
int CodeA = rand() % PlayerLevel + PlayerLevel;
int CodeB = rand() % PlayerLevel + PlayerLevel;
int CodeC = rand() % PlayerLevel + PlayerLevel;
int SumofCodes = CodeA + CodeB + CodeC;
int ProductofCodes = CodeA * CodeB * CodeC;
cout << "You are currently on the " << PlayerLevel << " floor out of 5" << endl;
cout << "The sum of the codes is: " << SumofCodes << " and the product of the codes is: " << ProductofCodes << endl;
cin >> PlayerGuessA >> PlayerGuessB >> PlayerGuessC;
int PlayerProduct = PlayerGuessA * PlayerGuessB * PlayerGuessC;
int PlayerSum = PlayerGuessA + PlayerGuessB + PlayerGuessC;
if (PlayerProduct == ProductofCodes && SumofCodes == PlayerSum) {
cout << "Great Job you got this!!!\n" << endl;
++PlayerLevel;
return true;
}
else
{
cout << "Try again before he catches onto you!\n" << endl;
return false;
}
}
int GameStart()
{
string Introduction = "Welcome to your worst nightmare. You are trapped in a murderer's house. You are on the 5th floor and need to get to the first floor to escape.\n";
string Instructions = "He has each door locked behind a security system that requires a 3 number code to disarm it.\nEnter the codes and move foward. Each level will the code will be harder to figure out.\n";
string PlayerStart;
cout << Introduction << endl;
cout << Instructions << endl;
cout << "Would you like to escape? Yes or No" << endl;
cin >> PlayerStart;
if (!(PlayerStart != "Yes" && PlayerStart != "yes")) {
++PlayerLevel;
}
return 0;
}
int main ()
{
if (PlayerLevel == 0) {
GameStart();
}
while (PlayerLevel <= MaxLevel)
{
bool bLevelComplete = GamePlay();
cin.clear ();
cin.ignore();
}
cout << "You Made it out! Now run before he finds out!" << endl;
return 0;
}
When the type of the input doesn't match the type of the variable that it is being extracted to, cin sets the fail bit. Once this happens, all subsequent reads fail until the stream is reset. The offending characters are still left in the buffer, so that needs to be cleared out as well.
Your usage of cin.clear() and cin.ignore() meant that the fail bit was getting reset, but only one offending character was being removed (cin.ignore() ignores one character by default). This is why you saw the output repeating x times for x erroneous characters.
You could do something like this:
while (PlayerLevel <= MaxLevel)
{
bool bLevelComplete = GamePlay();
if (cin.fail())
{
//Input extraction failed, need to reset stream and clear buffer until newline
cin.clear();
cin.ignore(numeric_limits<streamsize>::max(),'\n');
}
}
Related
int main() {
power=1;
while (1 == 1){
tapcost=power*3;
cout << "type upgrade/buy/a" << endl;
cin >> way;
if (way == "upgrade"){
cout << "1. A Power " << "(Costs: " << tapcost << ")" << endl;
cin >> upgr;
if (upgr == 1){
if (0<=money-power*3){
power=power+1;
money=money-power*3;
}
else
cout << "You can't afford that!!!" << endl;
}
}
if (way == "a"){
money=money+power;
}
}
return 0;
}
When I type upgrade and then type anything else other than the variable "1", the code will repeat infinitely.
This is a never-ending problem.
See this question: Infinite loop with cin when typing string while a number is expected
I think your code have some mistakes.
int upgr;
cin >> upgr; // you can type any number you want (-2 147 483 648 / 2 147 483 647)
I suggest you to use getline, cin.getline or fgets instead of cin >> when reading a line.
And just use while(1) or while(true)
You have created an infinite loop by never changing the value of your ‘1’ variable. In some way you need to change that value when iterating through your conditions or else you’ll never get out of your loop.
You could also try out something like that.
char i;
while((std::cin >> i) && i != '1') {
....
}
In your code, while (1 == 1) creates an infinite loop. Since I assume you want this code to keep asking players for their input until they decide to stop, you can add an option exit which breaks out of the loop when the player wants to.
#include <iostream>
int main() {
int power = 1;
int money = 1000;
while (1 == 1) {
int tapcost = power * 3;
std::string way;
std::cout << "type upgrade/buy/a/exit" << std::endl;
std::cin >> way;
if (way == "upgrade") {
std::cout << "1. A Power " << "(Costs: " << tapcost << ")" << std::endl;
int upgr;
std::cin >> upgr;
if (upgr == 1) {
if (0 <= money - power * 3) {
power = power + 1;
money = money - power * 3;
}
else {
std::cout << "You can't afford that!!!" << std::endl;
}
}
}
if (way == "a") {
money = money + power;
}
if (way == "exit") {
break;
}
}
return 0;
}
This question already has answers here:
Why is cout printing twice when I use getline?
(2 answers)
Closed 5 years ago.
When I run this and after I select my number as a player, Computer returns me two outputs (instead of one...). I have no idea why, could you please help me explain why that happens?
#include <iostream>
#include <string>
#include <stdlib.h>
#include <time.h>
using namespace std;
int random(int a, int b)
{
int num = a + rand() % (b + 1 - a);
return num;
}
int main()
{
srand(time(NULL));
int myNum;
cout << "Choose your number, human: ";
cin >> myNum;
int min = 1;
int max = 100;
int comp;
string player;
while(1) {
comp = random(min, max);
cout << "Computer: " << comp << endl; // why does this get called twice??
getline(cin, player);
if (player == "too high") {
max = comp - 1;
cout << "min: " << min << " max: " << max << endl;
} else if (player == "too low") {
min = comp + 1;
cout << "min: " << min << " max: " << max << endl;
} else if (player == "correct") {
cout << "Computer found the number..." << endl;
break;
}
}
}
It's because you are mixing input using >> and getline. getline reads to the next newline, >> does not. After you have entered your number, there is still a newline left behind, you have typed it, but hasn't yet been read. The first time you call getline that left behind newline gets read, and the program doesn't pause. Only on the second time that you call getline does your program pause and wait for you to type something.
Simple way to fix the problem is
int myNum;
cout << "Choose your number, human: ";
cin >> myNum;
// flush pending newline
string dummy;
getline(cin, dummy);
I have a small problem. I have attempted to make the game 'Word Jumble' with a scoring system. But sometimes, when the computer guesses a word, then it'll say: The word is: blank here. There should be a jumbled word there. When I try any word, it just subtracts 1.#INF points.
Code:
#include<iostream>
#include<string>
#include<stdlib.h>
#include<time.h>
using namespace std;
const int size=10;
string Words[size] = {
"consecutive",
"alternative",
"consequently",
"jumbled",
"computer",
"charger",
"food",//I'm hungry
"library",
"strawberry",
"carrier"
};
string Hints[size] = {
"Following continuously.",
"Something available as another opportunity.",
"As a result.",
"This word is rather jumbled, isn't it ;)",
"The enitiy you are reading this off of",
"My phone battery is running low",
"I'm hungry, I need some _",
"Where can I go get a book?",
"It's red, and not a berry."
"Either carries stuff, or is what your data company is called."
};
void main()
{
string word,hint;
double points=0;
bool correct=false,playAgain=true;
cout << "Welcome to Word Jumble!\n";
cout << "The objective of this game is to guess the jumbled word, correctly.\n";
cout << "Say 'quit' to quit, or 'hint' for a hint.\n";
while (playAgain==true)
{
correct = false;
int guesses = 0;
srand(static_cast<unsigned int>(time(0)));
int num = rand() % size + 1;
word = Words[num];
hint = Hints[num];
string jumble = word;
int length = jumble.size();
for (int i = 0; i < length*2; ++i)
{
int index1 = (rand() % length);
int index2 = (rand() % length);
char temp = jumble[index1];
jumble[index1] = jumble[index2];
jumble[index2] = temp;
}
cout << "The word is: " << jumble << endl;
double tempPoints=0;
while (correct==false)
{
string theGuess;
cout << "Guess the word: ";
cin >> theGuess;
guesses++;
while (!cin)
{
cin.sync();
cin.clear();
cout << "Ivalid entry, try again: ";
cin >> theGuess;
}
if (theGuess == word)
{
cout << "Correct! You guessed the word in only " << guesses << " tries!\n";
tempPoints += jumble.size()*1.5;
tempPoints -= (guesses - 1) / 4.0;
points += tempPoints;
cout << "You have been awarded " << tempPoints << " points this round for a total of " << points << "!\n";
correct = true;
cout << "Would you like to play again? (y or n): ";
char tempYN;
cin >> tempYN;
while (!cin || tempYN != 'y' && tempYN != 'n')
{
cin.sync();
cin.clear();
cout << "Invalid entry.\nWould you like to play again? (y or n): ";
cin >> tempYN;
}
if (tempYN == 'y')
{
playAgain = true;
}
else
{
playAgain = false;
}
}
else if (theGuess == "hint")
{
tempPoints -= (1.0 / (jumble.size())) * 40;
cout << "Hint: " << hint << endl;
correct = false;
playAgain = true;
}
else if (theGuess == "quit")
{
correct = true;
playAgain = false;
}
else
{
double sub = (1.0 / (jumble.size())) * 20;
cout << "Incorrect word, deducting "<<sub<<" points\n";
tempPoints -= sub;
playAgain = true;
correct = false;
}
};
};
cout << "Goodbye\n";
}
In the line:
int num = rand() % size + 1;
You are saying to select a random number between 0 and 9 then add 1.
If the random number is 9 the + 1 will make it 10. This means that you are trying to access a value in the array Words and Hints at index 10. Since arrays are 0 indexed and it's size is 10 that means you only have elements at 0 - 9.
You also will never get the first string in the arrays.
I am a newby at this and am working on my fist if/else program. I am having trouble getting the first if statement to recognize my input of "r". I tried playing with just one statement at a time I was able to input all the examples of input the teacher gave us with the desired output for residential and business. However when I run the program altogether I have a problem. I select R for residential, 0 for additional connections, 0 for premium channels and instead of output of $18.50 I get the business fee of $75.00. I am sure it is a simple mistake but I can't figure out what I am doing wrong. Can someone who knows how to work an if/else give me some insight on this!
#include "stdafx.h"
#include <conio.h>
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
const float BASIC_RESIDENTIAL = 18.50;
const float BASIC_BUSINESS = 75.00;
const float CONNECT_RESIDENTIAL = 6.50;
const float CONNECT_BUSINESS = 5.00;
const float PREMIUM_RESIDENTIAL = 7.50;
const float PREMIUM_BUSINESS = 50.00;
char customerType;
int numOfConnections;
int numOfPremiumChannels;
float amountCableBill;
cout << fixed << setprecision(2);
cout << "Residential or Business [R or B]? ";
cin >> customerType;
cout << endl << endl;
cout << "How many Additional Connections? ";
cin >> numOfConnections;
cout << endl << endl;
cout << "Total number of Premium Channels: ";
cin >> numOfPremiumChannels;
cout << endl << endl;
if (customerType == 'R' || customerType == 'r')
{
amountCableBill = BASIC_RESIDENTIAL + CONNECT_RESIDENTIAL * numOfConnections + PREMIUM_RESIDENTIAL * numOfPremiumChannels;
}
//else customerType == 'B' || customerType == 'b'; // unnecessary
{
if (numOfConnections <= 9)
amountCableBill = BASIC_BUSINESS + PREMIUM_BUSINESS * numOfPremiumChannels;
else
amountCableBill = BASIC_BUSINESS + (numOfConnections - 9) * CONNECT_BUSINESS + PREMIUM_BUSINESS *numOfPremiumChannels;
}
cout << "Total amount of Cable Bill: " << amountCableBill << endl << endl;
cout << "Press <ENTER> to end..." << endl;
_getch();
return 0;
}
While the condition else if (customerType == 'B' ...) may be redundant, you still have to put an else before the opening brace of the branch.
It's
if (condition) { code } else { code }
You need else in the condition (unless you want "some other code" to be executed every time)
if (customerType == 'R' || customerType == 'r')
{
//Some Code
}
else //<--Notice else
{
//Some other code.
}
I wrote a program for my computer science class that validates and solves sudoku puzzles from .txt files, but I wanted to take it one step further and write a program that made it easy to input and sudoku game. I'm sure you can figure out the format of the files based on this code. My only problem is that the last cin gets skipped, and that option is important to me. Any insight will be appreciated!!
#include <iostream>
#include <fstream>
#include <string>
using namespace std;
struct s {
s();
~s() {/*zzzz*/}
void show_grid();
void set (int &r, int &c, int &v) {g[r][c] = v;}
private:
int g[9][9];
};
//************************************************************************
void s::show_grid() {
//print game out to check it
cout << " | ------------------------------- |" << endl;
for (int k=0; k<81; k++) {
if (k%3 == 0)
cout << " |";
cout << " " << g[k/9][k%9];
if (k%9 == 8) {
cout << " |" << endl;
if ((k/9)%3 == 2)
cout << " | ------------------------------- |" << endl;
}
}
cout << endl;
}
//************************************************************************
s::s() {
//initialize all elements to zero
for (int i=0; i<9; i++) {
for (int j=0; j<9; j++) {
g[i][j] = 0;
}
}
}
//************************************************************************
void create_name (string &name) {
//append .txt extension LIKE IT OR NOT
string ext = name;
ext.erase(ext.begin(), ext.end() - 4);
if (ext.compare(".txt")!=0)
name.append(".txt");
}
//************************************************************************
int main () {
s g;
string name;
string yon("");
int count = 0;
int row, col, val, rcv;
ofstream os;
cout << "Enter game file name: ";
cin >> name;
create_name(name);
//open and do typical checks
os.open(name.c_str());
if (os.fail()) {
cerr << "Could not create " << name << ". Waaaah waaaaaaaaaah...\n\n";
return 0;
}
//useful output (hopefully)
cout << "Enter grid coordinates and value as a 3-digit number,\n"
<< "from left to right, row by row.\n"
<< "(e.g. 2 in first box would be 112)\n";
//take input as one int, to be user friendly
while (cin >> rcv && count < 81) {
row = (rcv / 100) - 1;
col = ((rcv / 10) % 10) - 1;
val = rcv % 10;
os << row << " " << col << " " << val << endl;
g.set (row, col, val);
count++;
}
os.close();
//From here down is broken, but it still compiles, runs, and works
cout << "Show grid input(y/n)?\n";
cin >> yon;
if (yon.compare("y")==0)
g.show_grid();
else if (yon.compare("n")==0)
cout << "Peace!\n";
return 0;
}
The problem is here:
while (cin >> rcv && count < 81)
Consider what happens when count==81: First, rcv will be input from cin, and only then the condition count < 81 will be evaluated to false. The loop will stop, and the value of rcv will be ignored. So effectively you read one input too many.
You should change the order of evaluation, so that count is checked first:
while (count < 81 && cin >> rcv)
Edit:
According to your comment above you are actually expecting to read less than 81 values. In that case, I recommend having the user input a special value (for example, 0) to terminate the loop. You'd just need to add if (rcv==0) break;. If you just input an invalid value as you are apparently doing, the cin stream will be put in a failed state and further input will not succeed.
Try something like:
//useful output (hopefully)
cout << "Enter grid coordinates and value as a 3-digit number,\n"
<< "from left to right, row by row.\n"
<< "(e.g. 2 in first box would be 112)\n"
<< "or Z to end the loop\n"; // 1
//take input as one int, to be user friendly
while (count < 81 && cin >> rcv ) { // 2
row = (rcv / 100) - 1;
col = ((rcv / 10) % 10) - 1;
val = rcv % 10;
os << row << " " << col << " " << val << endl;
g.set (row, col, val);
count++;
}
if(!std::cin) { // 3
std::cin.clear();
std::cin.ignore(std::numeric_limits<std::streamsize>::max(), '\n');
}
1) Let the user know that he can enter in invalid char. It doesn't have to be Z, actually any non-numeric char will work.
2) Fix off-by-one error in the order of the &&.
3) If std::cin is in error state, clear the error and ignore the Z.
cin >> yon
still actually reads in a variable, it just reads in the variable that the while loop found to be false. When the while loop condition returns false rcv is ignored, so the number remains in the input stream waiting for the next cin statement. When yon is called that number meant for rcv is read into yon, giving you some strange errors.
it would be better to use interjay's method:
while (count < 81 && cin >> rcv)