Search numbers between quotation marks and remove it (VS Code) - regex

Question

I've a really big .json file with this structure:
[
"9": {
"id": 9,
"chapter": 4
},
"4": {
"id": 82,
"chapter": 32
},
]
I want to remove every quotation marks before the brackets. The file should looking like this:
[
{
"id": 9,
"chapter": 4
},
{
"id": 82,
"chapter": 32
},
]
I found a similar question here, but the result isn't that what I want.

Answer 1

this step will remove keys; what are looking for( assuming no nested objects ) :
"\d+":\s*{ replace with '{'
this will remove latest ,if exist and turn last } to ]
},?\s*}$ replace with '}]'
optional step: this will remove latest ,if exist
},?\s*]$ replace with '}]'
check code snippet below for working example from your input to a valid json:
copy the pattern between // and paste it to vs-code find bar; (e.g. /},?\s*]$/ will be },?\s*]$) to be used in VSCode and the likewise for the replace
const input = `[
"9": {
"id": 9,
"chapter": 4
},
"4": {
"id": 82,
"chapter": 32
},
]`
const step1Find = /"\d+":\s*{/g;const step1Replace = '{'
//not needed anymore
//const step2Find = /^{/;const step2Replace = '['
//removing lastest comma if exists
const step3Find = /},?\s*]$/;const step3Replace = '}]'
let stringObject = input
.replace(step1Find,step1Replace)
.replace(step3Find,step3Replace)
console.log(JSON.parse(stringObject))