I'm currently working on a project that has several classes, and at times, I have to call functions from other classes to make things work. I want to know if the way I'm doing it is efficient, or if there is another way I should be doing this. Here's an example
class FirstClass{ // FirstClass.cpp
public:
void aFunction(){
std::cout << "Hello!";
}
private:
}
Let's say I wanted to call aFunction in another class, I'd do this:
#include "FirstClass.cpp"
class SecondClass{ //SecondClass.cpp
public:
FirstClass getFirstClass;
// I would then use getFirstClass.aFunction();
// whenever I want to call.
private:
}
I don't feel like this is very productive. Is there a better way of doing this?
First of all why including source file FirstClass.cpp?
The proper way is to create a header file FirstClass.h and a source file FirstClass.cpp and include the header inside the source and in main.cpp.
Second: A member function is a member function it is a member of an object so you need an instance of that class to call its member. If you don't want to instantiate the class then declare the member function as a static function then you can either call it using an object or directly using class name followed by scope operator: FirstClass::aFunction().
// FirstClass.h
class FirstClass{ // FirstClass.cpp
public:
void aFunction();
}
// FirstClass.cpp
#include "FirstClass.h"
void FirstClass::aFunction(){
std::cout << "Hello!";
}
// SecondClass.h
#include "FirstClass.h"
class SecondClass{
public:
void foo();
private:
FirstClass getFirstClass;
};
// SecondClass.cpp
void SecondClass::foo()
{
getFirstClass.aFunction();
}
To make it a static:
struct A
{
static void do_it(){std::cout << "A::do_it()\n";}
};
struct B
{
void call_it(){ A::do_it();}
};
There's nothing with "productivity" to whether have a static or non-static data/function member.
The semi-colon is not redundant at the end of class body so you need t add them: class FirstClass{ }; class SecondClass{};.
Related
So consider I have a class with a private member variable and a private function which I do not want to define in the header file, because I want to "hide" it from the user.
How can I make this? I can not access the private variable without the declaration of the function in the header.
So what works is something like this:
// header file
class Testclass {
public:
// ...
private:
const int m_i;
void func() const;
}
// cpp file
#include "TestClass.h"
Testclass::func() const {
int j = m_i; //access to a private member variable
}
// ...
But I want something like this:
// header file
class Testclass{
public:
//...
private:
const int m_i;
}
// cpp file
#include "TestClass.h"
Testclass::func() const {
int j = m_i; //access to a private member variable
}
// ...
Which possibilities do I have? I read something about the PIMPL Idiom, but I am not sure if this is what I want, since it looks a bit cumbersome coding-wise.
You can have non-member helper functions in the cpp file, that the class members can use. However, they would have to pass the private variable as a parameter.
// header file
class Testclass{
public:
//...
private:
const int m_i;
}
// cpp file
#include "TestClass.h"
void func(int m_i) {
int j = m_i; //private member variable supplied by caller
}
// ...
Normally one achieves this through the PIMPL (Pointer to IMPLementation) idiom. In your header file you have:
class MainClass
{
public:
void public_function();
private:
class Impl;
Impl* impl;
};
Note that the header file does not contain the definition of the Impl class, only its declaration.
You then define that class in your cpp file and forward the calls from your public interface to the functions of the impl class:
class MainClass::Impl
{
void actualfunc()
{
//do useful stuff here
}
};
void MainClass::public_function()
{
return impl->actualfunc();
}
Apart from your indended hiding of unwanted members from your class users, the PIMPL idiom provides the additional benefit that if no changes are made to the interface of the class, the users of the class need not be recompiled.
Alright, I just thought give C++ a try (I currently do C#), now my first problem is class instantiating or calling a method in another class.
Here is my code:
My main Program entry:
#include <iostream>
#include "myClass.h"
using namespace std;
int main()
{
myClass* mc = new myClass();
}
The Class I'm trying to access:
#include "myClass.h"
myClass::myClass()
{
void DoSomething();
{
}
}
myClass::~myClass()
{
}
The Class Header:
#pragma once
class myClass
{
public:
myClass();
~myClass();
};
Now as you can see i have instantiated the class, but i cant access DoSomething() method.
This code simply declares a local function, and has an empty scope for fun:
myClass::myClass()
{
void DoSomething(); // local function declaration
{
// empty scope
}
}
If you want doSomething() to be a member of myclass, you have to declare it in the class definition:
class myClass
{
public:
myClass();
~myClass();
void doSomething();
};
then implement it
void myclass::doSomething() { .... }
Also note that you don't have to use new everywhere in C++. You can instantiate an object like this:
int main()
{
myClass mc;
}
Also note that using namespace std; isn't such a great idea anyway, at least not in real code.
this is a function declaration in a constructor (+an ampty scope within { }).
myClass::myClass()
{
void DoSomething();
{
}
}
You want a function declaration in class body (not in constructor) and definition of this function (this can be done immediately together with declaration or later as i.e. here):
class myClass
{
public:
myClass();
~myClass();
void doSomething();
};
implementation of constructor:
myClass::myClass() { .... }
implementation of your function, similarly:
void myClass::doSomething() { .... }
The method you are trying to use in main must be part of the class definition. You can write an inline function or can have a separate definition of that function. Also, you need to make that function public in order to access it from main.
Im trying to do a C++ class function that can return other classes values. The code works if class A is defined first but i have more code that i dont want to mangle around. I figured i need somekind of forward declaration for class A.
What kind of forward declaration do i need to get this work? All my code is in one file. Does this problem dissapear if i properly split my classes to multiple files and include them to project or does it make any difference to VC++ compiler?
Semi pseudo code below.
// forward declaration
class A;
// class deifinitions
class B {
private:
int testvalue;
public:
void settestvalue(A &Aobj);
}
void B::settestvalue(A &Aobj) {
testvalue = Aobj.settestvalue();
}
class A {
private:
int test = 10;
public:
int testvalue();
};
int A::testvalue() {
return test;
}
// mainloop
A Aobj;
B Bobj;
Bobj.settestvalue (Aobj);
just put the defination of B's member-function after A's class definition.
Very new to c++ having trouble calling a function from another class.
Class B inherits from Class A, and I want class A to be able to call a function created in class B.
using namespace std;
class B;
class A
{
public:
void CallFunction ()
{
B b;
b.bFunction();
}
};
class B: public A
{
public:
virtual void bFunction()
{
//stuff done here
}
};
It all looks fine on screen (no obvious errors) but when I try to compile it i get an error C2079 'b' uses undefined class B.
I've tried making them pointers/ friends but I'm getting the same error.
void CallFunction ()
{ // <----- At this point the compiler knows
// nothing about the members of B.
B b;
b.bFunction();
}
This happens for the same reason that functions in C cannot call each other without at least one of them being declared as a function prototype.
To fix this issue we need to make sure both classes are declared before they are used. We separate the declaration from the definition. This MSDN article explains in more detail about the declarations and definitions.
class A
{
public:
void CallFunction ();
};
class B: public A
{
public:
virtual void bFunction()
{ ... }
};
void A::CallFunction ()
{
B b;
b.bFunction();
}
What you should do, is put CallFunction into *.cpp file, where you include B.h.
After edit, files will look like:
B.h:
#pragma once //or other specific to compiler...
using namespace std;
class A
{
public:
void CallFunction ();
};
class B: public A
{
public:
virtual void bFunction()
{
//stuff done here
}
};
B.cpp
#include "B.h"
void A::CallFunction(){
//use B object here...
}
Referencing to your explanation, that you have tried to change B b; into pointer- it would be okay, if you wouldn't use it in that same place. You can use pointer of undefined class(but declared), because ALL pointers have fixed byte size(4), so compiler doesn't have problems with that. But it knows nothing about the object they are pointing to(simply: knows the size/boundary, not the content).
So as long as you are using the knowledge, that all pointers are same size, you can use them anywhere. But if you want to use the object, they are pointing to, the class of this object must be already defined and known by compiler.
And last clarification: objects may differ in size, unlike pointers. Pointer is a number/index, which indicates the place in RAM, where something is stored(for example index: 0xf6a7b1).
class B is only declared but not defined at the beginning, which is what the compiler complains about. The root cause is that in class A's Call Function, you are referencing instance b of type B, which is incomplete and undefined. You can modify source like this without introducing new file(just for sake of simplicity, not recommended in practice):
using namespace std;
class A
{
public:
void CallFunction ();
};
class B: public A
{
public:
virtual void bFunction()
{
//stuff done here
}
};
// postpone definition of CallFunction here
void A::CallFunction ()
{
B b;
b.bFunction();
}
in A you have used a definition of B which is not given until then , that's why the compiler is giving error .
Forward declare class B and swap order of A and B definitions: 1st B and 2nd A. You can not call methods of forward declared B class.
Here's my solution to the issue. Tried to keep it straight and simple.
#include <iostream>
using namespace std;
class Game{
public:
void init(){
cout << "Hi" << endl;
}
}g;
class b : Game{ //class b uses/imports class Game
public:
void h(){
init(); //Use function from class Game
}
}A;
int main()
{
A.h();
return 0;
}
You can also have a look at the curiously recurring template pattern and solve your problem similar to this:
template<typename B_TYPE>
struct A
{
int callFctn()
{
B_TYPE b;
return b.bFctn();
}
};
struct B : A<B>
{
int bFctn()
{
return 5;
}
};
int main()
{
A<B> a;
return a.callFctn();
}
A C++ n00b question. Is it possible to call a private constructor from a static method defined in the cpp? I'd like to keep methods out of the header file if possible -- I figure there should be a way to do this. I'm getting an error when attempting this:
"cannot access private member declared in class SomeClass"
/////////////////
// SomeClass.h //
/////////////////
class SomeClass {
public:
static SomeClass SomeMethod();
private:
SomeClass(int i);
}
///////////////////
// SomeClass.cpp //
///////////////////
static SomeClass OSImplementation() {
return SomeClass(0);
};
// calls implementation
SomeClass SomeClass::SomeMethod() {
return OSImplementation();
}
You can make OSImplementation a friend method.
Or you can make OSImplementation a static method within the class (but that has to be declared in the header).
Or, probably the most common way to do this, is to have an internal implementation class, like this:
class SomeClass {
public:
//...
private:
struct Impl;
Impl* intern;
};
In your cpp file, you declare struct SomeClass::Impl.
In your constructor, create the SomeClass::Impl instance. Delete it in the destructor. And implement the copy-constructor and the assignment operator!
This is called the PIMPL (pointer to implementation) idiom (Wikipedia, c2.com). It's used a lot in big projects like Qt.
Yes, it is possible, by making the OSImplementation() friend of SomeClass. Next example compiles without warnings and errors using g++ 4.6.1 :
#include <iostream>
// declare in hpp
class SomeClass {
friend SomeClass OSImplementation();
public:
static SomeClass SomeMethod();
void foo();
private:
SomeClass(int);
};
int main()
{
auto obj = SomeClass::SomeMethod();
obj.foo();
}
// define in cpp
SomeClass SomeClass::SomeMethod(){
return SomeClass( 5 );
}
SomeClass::SomeClass(int){
}
void SomeClass::foo(){
std::cout<<"foo"<<std::endl;
}
SomeClass OSImplementation()
{
return SomeClass::SomeMethod();
}