How to issue a c++ termination catch without a OOM killer - c++

Question

I am learning about exceptions from a book and try/catch and the OS should terminate the following program.
The book says, the message terminate called after throwing an instance of 'std::bad_alloc' should show up. But doesn't.
I am using Arch Linux and the program is not stopping. It runs, fills the RAM a bit linear until it doesn't (at about 90%), the processor is working a lot but no freezing and no terminating.
Is this a Windows only use case or how could I reproduce the error on a Linux/maybe Unix system?
#include <iostream>
#include <exception> //c++ exception
int main()
{
int *feld;
int loop = 1;
for(;;) //infinite loop
{
std::cout << "Loop number: " << loop << '\n';
try
{
feld = new int[10000];
loop++;
if (durchlauf == 100000) //since c++11
std::terminate();
}
catch(...)
{
std::cout << "Error, Program done.\n";
break;
}
}
return 0;
}
EDIT: I found out that my OOM killer is not working properly with swap enabled/at all. But c++ has its own termination process call
https://en.cppreference.com/w/cpp/error/terminate
It just doesn't issues an exception to print out the catch line.
Has anyone a hint to issue a catch termination?

Answer 1

I found the following code for you to program some terminations:
Hope that helps.
#include <iostream>
#include <stdexcept>
struct A {
int n;
A(int n = 0): n(n) { std::cout << "A(" << n << ") constructed successfully\n"; }
~A() { std::cout << "A(" << n << ") destroyed\n"; }
};
int foo()
{
throw std::runtime_error("error");
}
struct B {
A a1, a2, a3;
B() try : a1(1), a2(foo()), a3(3) {
std::cout << "B constructed successfully\n";
} catch(...) {
std::cout << "B::B() exiting with exception\n";
}
~B() { std::cout << "B destroyed\n"; }
};
struct C : A, B {
C() try {
std::cout << "C::C() completed successfully\n";
} catch(...) {
std::cout << "C::C() exiting with exception\n";
}
~C() { std::cout << "C destroyed\n"; }
};
int main () try
{
// creates the A base subobject
// creates the a1 member of B
// fails to create the a2 member of B
// unwinding destroys the a1 member of B
// unwinding destroys the A base subobject
C c;
} catch (const std::exception& e) {
std::cout << "main() failed to create C with: " << e.what();
}

Answer 2

Just for the sake of being helpful if someone steps into the same problem
a coded thrown exception after 100000 loops:
#include <iostream>
#include <exception> //c++ exception
int main()
{
int *feld;
int loop = 1;
for(;;) //infinite loop
{
std::cout << "Loop number: " << loop << '\n';
try
{
feld = new int[10000];
loop++;
if (loop == 1e5)
throw std::bad_alloc(); //has to be inside the try(){} scope
}
catch(...)
{
std::cout << "Error, Program done.\n";
break;
}
}
return 0;
}