Stuck on a loop - c++

Question

I already posted this question, but none of the responses were correct once I implemented the suggestions I was given. Here is what I need to happen.
Would you like to process all the records in the file? (y/n) w
Error - Please enter either y or n.
Would you like to process all the records in the file? (y/n) n
Enter number of records to process: two
XXXXXXXXXX Error-non numeric or negative value, try again
Enter number of records to process: -10
XXXXXXXXXX Error-non numeric or negative value, try again
Enter number of records to process: 0
XXXXXXXXXX Error-non numeric or negative value, try again
Enter number of records to process: 10
Maximum requested record count of 10 reached
Here is what I have. I don't know what I am doing wrong.
#include <iostream>
#include <fstream>
using namespace std;
int main(){
char a = 0; //User chooses Y or N
int ProcessAmount = 0; //Amount of times to process if not all
cout << "Would you like to process all the records in the file? "
<< "(y/n) ";
cin >> a;
if (a == 'y')
{
cout << "Processed all records successfuly" << endl;
}
do
{
if (a == 'n')
{
cout << "Enter number of records to process: ";
cin >> ProcessAmount;
if (ProcessAmount <= 0 or cin.fail())
{
cout << "" << endl;
cout << "XXXXXXXXX Error-non numeric or negative value";
cout << "" << endl;
cin >> ProcessAmount;
}
else if (ProcessAmount >= 0 or (!(cin.fail())))
;
{
cout << "Maximum requested record count of " << ProcessAmount;
cout << " reached" << endl;
break;
}
}
else
(cin.fail());
{
cin.clear();
cin.ignore(40, '\n');
cout << "Please try again" << endl;
cout << "Would you like to process all the records in the file? "
<< "(y/n) ";
cin >> a;
}
} while (a == 'n');
}

Answer 1

First of all or is something I didn't know worked in C++, but in my gcc compiler it works fine, so thank you for that, I still replaced it with || in my answer, though.
Apart from that there are some issues with the sequence of events in your do - while cycle, try the code below.
Live sample here
do {
if (a == 'y') {
cout << "Processed all records successfuly" << endl;
break;
}
if (a == 'n') {
cout << "Enter number of records to process: ";
cin >> ProcessAmount;
if (ProcessAmount <= 0 || cin.fail()) {
cout << "XXXXXXXXX Error-non numeric or negative value";
cout << "" << endl;
}
else {
cout << "Maximum requested record count of " << ProcessAmount;
cout << " reached" << endl;
break;
}
cin.clear();
cin.ignore(40, '\n');
continue;
}
cout << "Please try again" << endl;
cout << "Would you like to process all the records in the file? "
<< "(y/n) ";
cin >> a;
} while (a != 'y');

Answer 2

First of all, the value of a must be validated, with something like:
cout << "Would you like to process all the records in the file? "
<< "(y/n) ";
cin >> a;
//validating a
while (a != 'n' && a != 'y'){
cout << "Error - Please enter either y or n." << endl;
cout << "Would you like to process all the records in the file? "
<< "(y/n) ";
cin >> a;
}
//...do things if a='n'
//...do thing if a='y'
then you should stop worrying about a, then you can do things if a = n or if a = y