Swapping elements in 2d array - c++

Question

So, I'm trying to swap the matrix elements with respect to the main diagonal. I have tried using temp method (switching values while using temp variable), also tried std::swap(a,b). Somehow it only swaps upper right side of the matrix and leaves another half not changed.
How do I make everything swap?
My code:
#include <iostream>
using namespace std;
int main()
{
const int n = 7;
srand (time(NULL));
int matrix[n][n];
cout << "Original Matrix :" << endl;
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
(i == j) ? matrix[i][j] = 0 : matrix[i][j] = rand() % 100+1;
cout << matrix[i][j] << "\t";
}
cout << endl;
}
cout << "\nRemade Matrix:" << endl;
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
int temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
// swap(matrix[i][j], matrix[j][i]); //another method
cout << matrix[i][j] << "\t";
}
cout << endl;
}
return 0;
}

Answer 1

You are basically swapping them twice, replace your swapping loops with this. Notice the condition of the second loop, it's j < i. Then, you can print it with another set of loops.
for (int i = 0; i < n; i++)
for (int j = 0; j < i ; j++)
swap(matrix[i][j], matrix[j][i]);

Answer 2

Your logic is almost ok. Just the inner loop counter will start from "i+1" else after the swapping the value is again getting overlapped. Try the following code and make sure you understand it. Happy coding!
for (int i = 0; i < n; i++)
{
for (int j = i + 1; j < n; j++)
{
int temp = matrix[i][j];
matrix[i][j] = matrix[j][i];
matrix[j][i] = temp;
}
}
for (int i = 0; i < n; i++)
{
for (int j = 0; j < n; j++)
{
cout << matrix[i][j] << "\t";
}
cout << endl;
}