This question already has an answer here:
Reference - What does this regex mean?
(1 answer)
Closed 3 years ago.
I am trying to find an expression that can be used extract a string after a specific number of characters.
E.g
FR_EN_BR_Student_Exact
FR_EN_NB_Student_Exact
I would want a pattern that can take all characters past the second underscore ( not including the underscore.
Would appreciate any ideas!
I understand basic regex but am having trouble with this specific query.
try:
=ARRAYFORMULA(IFNA(REGEXEXTRACT(A1:A, ".+_.+_(.+_.+_.+)")))
Related
This question already has answers here:
Regex to mask characters except first two and last two characters in Java
(4 answers)
Closed 5 months ago.
I use Postgresql and need to replace numbers to asterisk at database layer. Howerver I'm new to learn regex and seems to be hard to do this with my current knowledge.
I will have in my database 16 numbers varchar and I need to replace middle numbers with asterisk.
Example.
123467812345678 -> 12**********5678
Could someone tell me how regex for this should look like in postgresql ?
Thanks in advance
Thanks to #Wiktor Stribiżew:
SELECT regexp_replace('123467812345678', '(?<=..).(?=....)', '*','g');
This question already has answers here:
Remove part of string after "."
(6 answers)
Closed 2 years ago.
As the image shows, I need to remove everything after the word "Please" irrespective of the position of word "Please".
I tried regex to remove everything after ".", I need different approach for this
Any help will be appreciated.
Please try this regexp (\bPlease\b)(?!.*\1)
https://regex101.com/r/9wWAlG/1
This question already has answers here:
What special characters must be escaped in regular expressions?
(13 answers)
Closed 4 years ago.
I'd like to setup auto download of some Anime using an RSS feed, but only 720p versions. The format never changes and it always looks like below.
[Blahblah] Blahepisode - 12 [720p].mkv
Here is the regex I have come up with but cannot get to work properly.
/.\+[720p]+/g
Any help would be appreciated!
Assuming you have lines that look like your example, it will be mached with the following Regex:
.+(?:\[720p\].mkv)
It maches one or more chacacters at start, followed by '[720p].mkv'.
Note that the Square brackets are escaped to '\[' and '\]', otherwise they have special meaning.
if you only need '[720p]' then you can use:
\[720p\]
This question already has an answer here:
Learning Regular Expressions [closed]
(1 answer)
Closed 4 years ago.
SO i got regex to make first letter capital but i need now a regex to make the last letter caps, ive tried google searches and came up with nothing
Example of what im talking about
razor123
james333
firefire32923932
laser
Need them to turn into
razoR123
jameS333
firefirE32923932
laseR
Try this:
Find: ^([a-z]+)([a-z][^a-z]*)$
Replace with: \1\U\2
This question already has answers here:
How do I match an entire string with a regex?
(8 answers)
Closed 5 years ago.
I believe my validation is correct however it is not working.
My regular expression pattern is
ValidationExpression= "(I|II|III|IV)[DEF]?"
Basically, the user should put any of the first options then with optional D, E or F
Valid text Example: IIIC
Thank you
I don't know much about regex, but I did a quick bit of googling and came up with this:
https://regex101.com/r/KYpVbk/1
It explains how it works at the side :)