Encapsulating arguments of variadic function in a class instance - c++

Here some code with holes:
template<typename... Args>
class A
{
typedef function_type = void(*)(Args...);
public:
void set_args(Args&& ... args)
{
// something magic manages to encapsulate
// args in instance of A
}
void apply_args(function_type function)
{
// something magic manages to "retrieve"
// the encapsulated args
function(std::forward<Args>(args)...);
}
};
Would that be somehow possible ?

You can store your template arguments in class data member of std::tuple type and the use std::apply in order to apply stored arguments to provided function.
So, let's say you have an Action class like this:
template <typename... Args>
class Action {
std::tuple<Args...> args_;
public:
Action() = default;
Action(Args&&... args)
: args_(std::forward<Args>(args)...)
{}
void args(Args&&... args) {
args_ = std::make_tuple<Args...>(std::forward<Args>(args)...);
}
template <typename F>
void apply(F&& fun) {
std::apply(std::forward<F&&>(fun), args_);
}
};
where you set arguments through constructor Action action(1, 2, 3); or through separate function action.set(3, 2, 1);.
Then your main function can look like this:
int main() {
Action action(1, 2);
action.apply([](int a, int b) {
std::cout << "a + b = " << (a + b) << std::endl;
});
return 0;
}
Check live example

You can make use of std::tuple and std::apply
#include <iostream>
#include <tuple>
#include <functional>
#include <string>
template <typename... Ts>
class A
{
private:
std::function<void (Ts...)> f;
std::tuple<Ts...> args;
public:
template <typename F>
A(F&& func, Ts&&... args)
: f(std::forward<F>(func)),
args(std::make_tuple(std::forward<Ts>(args)...))
{}
void Invoke()
{
std::apply(f, args);
}
};
template <typename F, typename... Args>
A<Args...> Create(F&& f, Args&&... args)
{
return A<Args...>(std::forward<F>(f), std::forward<Args>(args)...);
}
int main()
{
auto helloWorld = Create([] (std::string a, std::string b) { std::cout << a << ", " << b; }, std::string("Hello"), std::string("World!"));
helloWorld.Invoke();
}

Related

Save and pass to function list of template arguments in C++

I want to save and pass list of template arguments to function.
Like std::thread passes arguments to a thread. Types of arguments are templated and arguments count is not static.
Example, how it will work:
class CallbackList {
public:
Callback(/* Type of list of template args */ args) {
this->saved_args = args;
}
void Call() {
this->callback(saved_args);
}
private:
/* Type of list of template args */ saved_args;
CallbackType callback;
}
Or how can I implement that:
template<typename ...Args>
class CallbackList {
public:
using CallbackPrototype = /* some prototype */;
void RegisterCallback(CallbackPrototype callback, Args... args) {
CallbackInfo callback_info;
callback_info.callback = callback;
callback_info.args = { args... };
this->callbacks.push_back(callback_info);
}
void Call() {
for (CallbackInfo& callback_info : this->callbacks)
callback_info.callback(callback_info.args);
}
private:
struct CallbackInfo {
CallbackPrototype callback;
/* what type should be here? tuple? args count are not static */ args;
};
std::vector<CallbackInfo> callbacks;
}
It is possible?
How can I implement it?
If you do not want your callback to depend on the types of the arguments you have to use some kind of type erasure. You can, for example, use std::function from <functional>:
#include <functional>
#include <iostream>
class Lazy_Callback
{
public:
template <typename F, typename ...Args>
Lazy_Callback(F && f, Args && ...args)
: _fun([=]() { return f(args...); })
{ }
void call() const
{
_fun();
}
protected:
private:
std::function<void()> _fun;
};
void print_int(int x)
{
std::cout << "x = " << x << "\n";
}
int main()
{
Lazy_Callback lc(print_int, 5);
lc.call();
}
If the callback can be templated then you can use std::tuple to store your arguments:
#include <tuple>
#include <iostream>
template <typename F, typename ...Args>
class Lazy_Callback
{
public:
template <typename ...Ts>
Lazy_Callback(F f, Ts && ...ts)
: _f(f), _args(ts...)
{ }
void call() const
{
return std::apply(_f, _args);
}
protected:
private:
F _f;
std::tuple<Args...> _args;
};
template <typename F, typename ...Ts>
Lazy_Callback<F, std::decay_t<Ts>...> make_callback(F && f, Ts && ...ts)
{
return { std::forward<F>(f), std::forward<Ts>(ts)... };
}
void print_int(int x)
{
std::cout << "x = " << x << "\n";
}
int main()
{
auto lc = make_callback(print_int, 5);
lc.call();
}
Are you looking for something like std::bind? Here is a simple example that you could probably expand on:
#include <iostream>
#include <functional>
template <typename T1, typename T2>
void printSum(const T1& a, const T2& b)
{
std::cout << a + b << std::endl;
}
int main()
{
const auto callback = std::bind(&printSum<int, int>, 1, 2);
// ...
callback();
}

Store and call member function with unknown arguments

I'm trying to store a member function of an unknown class with unkown arguments to be called later.
I found this code snippet to get the lambda:
template <auto Fn, typename T, typename R = void, typename... Args>
auto get_cb_inner(T* obj, R (T::*)(Args...) const) {
return [obj](Args... args) -> R {
return (obj->*Fn)(std::forward<Args>(args)...);
};
}
template <auto Fn, typename T>
auto get_cb(T* obj) {
return get_cb_inner<Fn, T>(obj, Fn);
}
But I can't figure out how I would store it and then be able to call it during runtime with the correct parameters.
I have a struct like this:
struct Job {
void execute(Data& data, const OtherData& otherData) const {
// do job
}
};
auto exe_fn = get_cb<&Job::execute>(new Job());
What I want to do is to store this "execute" function in a lambda and then store it in a vector-like container (with other functions that may have different arguments) that can be iterated and called on.
EDIT:
Using #KamilCuk code I created this wrapper-struct with no mem leaks/seg faults.
template <typename... Args>
using exec_fn = std::function<void(Args...)>;
template <typename Job>
using job_ptr = std::unique_ptr<Job>;
template <typename J, typename R = void, typename... Args>
struct JobExecuteCaller {
exec_fn<Args...> exec_fn;
job_ptr<J> job_ptr;
JobExecuteCaller (J* job, R (S::*f)(Args...) const)
: job_ptr{job_ptr<J>(job)} {
exec_fn = [this, f](Args... args) -> R {
(job_ptr.get()->*f)(std::forward<Args>(args)...);
};
}
void operator()(Args... args) { exec_fn(args...); }
};
auto process = JobExecuteCaller(new Job(), &Job::execute);
JobExecuteCaller(/*args ... */)
Now I just have to figure out a way to store different kinds of JobExecuteCallers.
You mean you want std::bind?
#include <utility>
#include <new>
#include <iostream>
#include <functional>
struct Job {
void execute(int a, int b) {
std::cout << a << " " << b << std::endl;
}
};
int main() {
auto exe_fn = std::bind(&Job::execute, new Job(),
std::placeholders::_1, std::placeholders::_2);
exe_fn(1, 2);
}
I have fixed your code. You need to pass not only the type of the function member pointer, but also the address of the function member pointer to the function. That way you can call it.
#include <utility>
#include <new>
#include <iostream>
#include <functional>
template <typename T, typename R = void, typename... Args>
auto get_cb(T* obj, R (T::*f)(Args...)) {
return [obj, f](Args... args) -> R {
return (obj->*f)(std::forward<Args>(args)...);
};
}
struct Job {
void execute(int a, int b) {
std::cout << a << " " << b << std::endl;
}
};
int main() {
auto exe_fn = get_cb(new Job(), &Job::execute);
exe_fn(1, 2);
}
Note that both examples leak memory from new Job().

Is there a way to partially match a variadic template parameter pack?

I currently have a system to "connect" signals to functions. This signal is a variadic template that has as template parameters the arguments of the functions it can connect to.
In the current implementation, I obviously cannot connect to functions whose arguments aren't exactly the same (or those that can be converted to) as the signal's parameters. Now, as I'm trying to mimic Qt's signal/slot/connect, I'd also like to connect a signal of N parameters to a slot of M<N parameters, which is perfectly well-defined (i.e. ignore the >M parameters of the signal and just pass the first M to the connected function). For an example of the code I have in its most simplistic form, see Coliru.
So the question is two-fold:
How do I make the connect call work for a function void g(int);?
How do I make the emit call work for a function void g(int);?
I'm guessing I'll have to make some "magic" parameter pack reducer for both the slot and its call function, but I can't see how it all should fit together so it's quite hard to actually start trying to code a solution. I'm OK with a C++17-only solution, if at least Clang/GCC and Visual Studio 2015 can compile it.
The code linked above for completeness:
#include <memory>
#include <vector>
template<typename... ArgTypes>
struct slot
{
virtual ~slot() = default;
virtual void call(ArgTypes...) const = 0;
};
template<typename Callable, typename... ArgTypes>
struct callable_slot : slot<ArgTypes...>
{
callable_slot(Callable callable) : callable(callable) {}
void call(ArgTypes... args) const override { callable(args...); }
Callable callable;
};
template<typename... ArgTypes>
struct signal
{
template<typename Callable>
void connect(Callable callable)
{
slots.emplace_back(std::make_unique<callable_slot<Callable, ArgTypes...>>(callable));
}
void emit(ArgTypes... args)
{
for(const auto& slot : slots)
{
slot->call(args...);
}
}
std::vector<std::unique_ptr<slot<ArgTypes...>>> slots;
};
void f(int, char) {}
int main()
{
signal<int, char> s;
s.connect(&f);
s.emit(42, 'c');
}
template<class...> struct voider { using type = void; };
template<class... Ts> using voidify = typename voider<Ts...>::type;
template<class C, class...Args>
using const_lvalue_call_t = decltype(std::declval<const C&>()(std::declval<Args>()...));
template<class T, std::size_t...Is>
auto pick_from_tuple_impl(T &&, std::index_sequence<Is...>)
-> std::tuple<std::tuple_element_t<Is, T>...>;
template<class Tuple, class = std::enable_if_t<(std::tuple_size<Tuple>::value > 0)>>
using drop_last = decltype(pick_from_tuple_impl(std::declval<Tuple>(),
std::make_index_sequence<std::tuple_size<Tuple>::value - 1>()));
template<class C, class ArgsTuple, class = void>
struct try_call
: try_call<C, drop_last<ArgsTuple>> {};
template<class C, class...Args>
struct try_call<C, std::tuple<Args...>, voidify<const_lvalue_call_t<C, Args...>>> {
template<class... Ts>
static void call(const C& c, Args&&... args, Ts&&... /* ignored */) {
c(std::forward<Args>(args)...);
}
};
Then in callable_slot:
void call(ArgTypes... args) const override {
using caller = try_call<Callable, std::tuple<ArgTypes...>>;
caller::call(callable, std::forward<ArgTypes>(args)...);
}
For member pointer support (this requires SFINAE-friendly std::result_of), change const_lvalue_call_t to
template<class C, class...Args>
using const_lvalue_call_t = std::result_of_t<const C&(Args&&...)>;
then change the actual call in try_call::call to
std::ref(c)(std::forward<Args>(args)...);
This is poor man's std::invoke for lvalue callables. If you have C++17, just use std::invoke directly (and use std::void_t instead of voidify, though I like the sound of the latter).
Not sure to understand what do you exactly want but... with std::tuple and std::make_index_sequence ...
First of all you need a type traits that give you the number of arguments of a function (or std::function)
template <typename>
struct numArgs;
template <typename R, typename ... Args>
struct numArgs<R(*)(Args...)>
: std::integral_constant<std::size_t, sizeof...(Args)>
{ };
template <typename R, typename ... Args>
struct numArgs<std::function<R(Args...)>>
: std::integral_constant<std::size_t, sizeof...(Args)>
{ };
Next you have to add a constexpr value in callable_slot to memorize the number of arguments in the Callable function
static constexpr std::size_t numA { numArgs<Callable>::value };
Then you have to modify the call() method to pack the arguments in a std::tuple<ArgTypes...> and call another method passing the tuple and an index sequence from 0 to numA
void call(ArgTypes... args) const override
{ callI(std::make_tuple(args...), std::make_index_sequence<numA>{}); }
Last you have to call, in CallI(), the callable() function with only the first numA elements of the tuple of arguments
template <std::size_t ... Is>
void callI (std::tuple<ArgTypes...> const & t,
std::index_sequence<Is...> const &) const
{ callable(std::get<Is>(t)...); }
The following is a full working example
#include <memory>
#include <vector>
#include <iostream>
#include <functional>
template <typename>
struct numArgs;
template <typename R, typename ... Args>
struct numArgs<R(*)(Args...)>
: std::integral_constant<std::size_t, sizeof...(Args)>
{ };
template <typename R, typename ... Args>
struct numArgs<std::function<R(Args...)>>
: std::integral_constant<std::size_t, sizeof...(Args)>
{ };
template <typename ... ArgTypes>
struct slot
{
virtual ~slot() = default;
virtual void call(ArgTypes...) const = 0;
};
template <typename Callable, typename ... ArgTypes>
struct callable_slot : slot<ArgTypes...>
{
static constexpr std::size_t numA { numArgs<Callable>::value };
callable_slot(Callable callable) : callable(callable)
{ }
template <std::size_t ... Is>
void callI (std::tuple<ArgTypes...> const & t,
std::index_sequence<Is...> const &) const
{ callable(std::get<Is>(t)...); }
void call(ArgTypes... args) const override
{ callI(std::make_tuple(args...), std::make_index_sequence<numA>{}); }
Callable callable;
};
template <typename ... ArgTypes>
struct signal
{
template <typename Callable>
void connect(Callable callable)
{
slots.emplace_back(
std::make_unique<callable_slot<Callable, ArgTypes...>>(callable));
}
void emit(ArgTypes... args)
{ for(const auto& slot : slots) slot->call(args...); }
std::vector<std::unique_ptr<slot<ArgTypes...>>> slots;
};
void f (int i, char c)
{ std::cout << "--- f(" << i << ", " << c << ")" << std::endl; }
void g (int i)
{ std::cout << "--- g(" << i << ")" << std::endl; }
struct foo
{
static void j (int i, char c)
{ std::cout << "--- j(" << i << ", " << c << ")" << std::endl; }
void k (int i)
{ std::cout << "--- k(" << i << ")" << std::endl; }
};
int main ()
{
std::function<void(int, char)> h { [](int i, char c)
{ std::cout << "--- h(" << i << ", " << c << ")" << std::endl; }
};
std::function<void(int)> i { [](int i)
{ std::cout << "--- i(" << i << ")" << std::endl; }
};
using std::placeholders::_1;
foo foo_obj{};
std::function<void(int)> k { std::bind(&foo::k, foo_obj, _1) };
signal<int, char> s;
s.connect(f);
s.connect(g);
s.connect(h);
s.connect(i);
s.connect(foo::j);
s.connect(k);
s.emit(42, 'c');
}
This example need C++14 because use std::make_index_sequence and std::index_sequence.
Substitute both of they and prepare a C++11 compliant solution isn't really difficult.

Subclassing std::thread: problems with variadic template functions in constuctor

I'm trying to subclass std::thread such that a member function of the subclass is executed on the new thread before the caller's passed-in function. Something like the following invalid code:
#include <thread>
#include <utility>
class MyThread : public std::thread {
template<class Func, class... Args>
void start(Func&& func, Args&&... args) {
... // Useful, thread-specific action
func(args...);
}
public:
template<class Func, class... Args>
MyThread(Func&& func, Args&&... args)
: std::thread{[=]{start(std::forward<Func>(func),
std::forward<Args>(args)...);}} {
}
};
g++ -std=c++11 has the following issue with the above code:
MyThread.h: In lambda function:
MyThread.h:ii:jj: error: parameter packs not expanded with '...':
std::forward<Args>(args)...);}}
^
I've tried a dozen different variations in the initializer-list to no avail.
How can I do what I want?
The biggest difficulty I had when I did this before was getting all the behavior of std::thread. It's constructor can take not only a pointer to a free function, but also a class method pointer and then a object of the class as the first argument. There are a number of variations on that: class methods, class function object data members, an object of the class type vs a pointer to an object, etc.
This is for C++14:
class MyThread : public std::thread {
void prolog() const { std::cout << "prolog\n"; }
public:
template <typename... ArgTypes>
MyThread(ArgTypes&&... args) :
std::thread(
[this, bfunc = std::bind(std::forward<ArgTypes>(args)...)]
() mutable {
prolog();
bfunc();
})
{ }
};
If you put the prolog code inside the lambda and it doesn't call class methods, then the capture of this is not needed.
For C++11, a small change is needed because of the lack of capture initializers, so the bind must be passed as an argument to std::thread:
std::thread(
[this]
(decltype(std::bind(std::forward<ArgTypes>(args)...))&& bfunc) mutable {
prolog();
bfunc();
}, std::bind(std::forward<ArgTypes>(args)...))
Here's a test program that also exercises the class member form of std::thread:
int main()
{
auto x = MyThread([](){ std::cout << "lambda\n"; });
x.join();
struct mystruct {
void func() { std::cout << "mystruct::func\n"; }
} obj;
auto y = MyThread(&mystruct::func, &obj);
y.join();
return 0;
}
I haven't checked, but I'm a bit worried that the capture of this, also seen in other solutions, is not safe in some cases. Consider when the object is an rvalue that is moved, as in std::thread t = MyThread(args). I think the MyThread object will go away before the thread it has created is necessarily finished using it. The "thread" will be moved into a new object and still be running, but the captured this pointer will point to a now stale object.
I think you need to insure your constructor does not return until your new thread is finished using all references or pointers to the class or class members. Capture by value, when possible, would help. Or perhaps prolog() could be a static class method.
This should do it (c++11 and c++14 solutions provided):
C++14
#include <thread>
#include <utility>
#include <tuple>
class MyThread : public std::thread {
template<class Func, class ArgTuple, std::size_t...Is>
void start(Func&& func, ArgTuple&& args, std::index_sequence<Is...>) {
// Useful, thread-specific action
func(std::get<Is>(std::forward<ArgTuple>(args))...);
}
public:
template<class Func, class... Args>
MyThread(Func&& func, Args&&... args)
: std::thread
{
[this,
func = std::forward<Func>(func),
args = std::make_tuple(std::forward<Args>(args)...)] () mutable
{
using tuple_type = std::decay_t<decltype(args)>;
constexpr auto size = std::tuple_size<tuple_type>::value;
this->start(func, std::move(args), std::make_index_sequence<size>());
}
}
{
}
};
int main()
{
auto x = MyThread([]{});
}
In C++17 it's trivial:
#include <thread>
#include <utility>
#include <tuple>
#include <iostream>
class MyThread : public std::thread {
public:
template<class Func, class... Args>
MyThread(Func&& func, Args&&... args)
: std::thread
{
[this,
func = std::forward<Func>(func),
args = std::make_tuple(std::forward<Args>(args)...)] () mutable
{
std::cout << "execute prolog here" << std::endl;
std::apply(func, std::move(args));
std::cout << "execute epilogue here" << std::endl;
}
}
{
}
};
int main()
{
auto x = MyThread([](int i){
std::cout << i << std::endl;
}, 6);
x.join();
}
C++11 (we have to facilitate moving objects into the mutable lambda, and provide the missing std::index_sequence):
#include <thread>
#include <utility>
#include <tuple>
namespace notstd
{
using namespace std;
template<class T, T... Ints> struct integer_sequence
{};
template<class S> struct next_integer_sequence;
template<class T, T... Ints> struct next_integer_sequence<integer_sequence<T, Ints...>>
{
using type = integer_sequence<T, Ints..., sizeof...(Ints)>;
};
template<class T, T I, T N> struct make_int_seq_impl;
template<class T, T N>
using make_integer_sequence = typename make_int_seq_impl<T, 0, N>::type;
template<class T, T I, T N> struct make_int_seq_impl
{
using type = typename next_integer_sequence<
typename make_int_seq_impl<T, I+1, N>::type>::type;
};
template<class T, T N> struct make_int_seq_impl<T, N, N>
{
using type = integer_sequence<T>;
};
template<std::size_t... Ints>
using index_sequence = integer_sequence<std::size_t, Ints...>;
template<std::size_t N>
using make_index_sequence = make_integer_sequence<std::size_t, N>;
}
template<class T>
struct mover
{
mover(T const& value) : value_(value) {}
mover(T&& value) : value_(std::move(value)) {}
mover(const mover& other) : value_(std::move(other.value_)) {}
T& get () & { return value_; }
T&& get () && { return std::move(value_); }
mutable T value_;
};
class MyThread : public std::thread {
template<class Func, class ArgTuple, std::size_t...Is>
void start(Func&& func, ArgTuple&& args, notstd::index_sequence<Is...>) {
// Useful, thread-specific action
func(std::get<Is>(std::forward<ArgTuple>(args))...);
}
public:
template<class Func, class... Args>
MyThread(Func&& func, Args&&... args)
: std::thread()
{
using func_type = typename std::decay<decltype(func)>::type;
auto mfunc = mover<func_type>(std::forward<Func>(func));
using arg_type = decltype(std::make_tuple(std::forward<Args>(args)...));
auto margs = mover<arg_type>(std::make_tuple(std::forward<Args>(args)...));
static_cast<std::thread&>(*this) = std::thread([this, mfunc, margs]() mutable
{
using tuple_type = typename std::remove_reference<decltype(margs.get())>::type;
constexpr auto size = std::tuple_size<tuple_type>::value;
this->start(mfunc.get(), std::move(margs).get(), notstd::make_index_sequence<size>());
});
}
};
int main()
{
auto x = MyThread([](int i){}, 6);
x.join();
}

Call functions with multiple args

Can I store in a container a list of member functions and then call them later, if they have different number of args.
I feel I'm just missing something small but this is how far I've got.
template<typename T>
class RPCServer
{
public:
RPCServer(const std::string host, const int port) {}
// Store the method pointers
template<typename F>
void register_method(const T discriminant, F func) {
m_callbacks.emplace_back(discriminant,func);
}
template<typename... Args>
void run(T subject, Args... args) {
auto func = std::find(std::begin(m_callbacks), std::end(m_callbacks), subject);
if (func != std::end(m_callbacks)) {
auto res = std::get<1>(*func)(args...); // This doesn't compile
}
}
~RPCServer() = default;
private:
// Store
std::vector<std::tuple<T, boost::any>> m_callbacks;
};
class Impl
{
public:
// RPC methods
void send_data(std::string data) {}
int get_details(int input) { return 0; }
};
Set up here
using namespace std::placeholders;
Impl impl;
RPCServer<std::string> server("localhost",1234);
server.register_method("foo", std::bind(&Impl::send_data, impl, _1));
server.register_method("bar", std::bind(&Impl::get_details, impl, _1));
server.run("foo", "blah"s); // This should call send_data with 'blah' as a arg
auto result = server.run("bar", 1); // Call get_details passing in 1
How do I store/retrieve a set of member functions type safely.
What about creating an adaptor template?
A proof-of-concept code:
#include <iostream>
#include <functional>
template<typename T0, typename... TS> struct FunCaller {
template<class F> FunCaller(F &&f): f(f) {}
template<typename... More> T0 operator()(TS &&... as, More &&...) {
return f(as...);
}
private:
std::function<T0(TS...)> f;
};
template<typename T0, typename... TS> inline FunCaller<T0, TS...> funCaller(T0(&&f)(TS...)) { return FunCaller<T0, TS...>(f); }
std::ostream &printSome(std::string const &s1, std::string const &s2) { return std::cout << s1 << ", " << s2 << std::endl; }
int main() {
auto omg = funCaller(printSome);
omg("Hello", "world!", "This", "is", "cocaine", "speaking");
}