How to access Many-to-Many field data? - django

Question

I have the following models:
class Work_Music(MPTTModel, Work):
name = models.CharField(max_length=10, null=True, blank=True)
key = models.CharField(max_length=10, null=True, blank=True)
tonality = models.CharField(max_length=20, null=True, blank=True)
class WorkCast(models.Model):
work = models.ForeignKey(Work_Music, verbose_name=_('work'), related_name='workcast', null=True, blank=True, on_delete=models.PROTECT)
cast = models.ManyToManyField(Cast, verbose_name=_('cast'), related_name='workcast', blank=True)
order = models.DecimalField(max_digits=100, decimal_places=2, null=True, blank=True)
class Cast(models.Model):
name = models.CharField(max_length=100, null=True, blank=True)
In view.py, I send the following in template context:
work_cast = WorkCast.objects.get(work=self.kwargs['pk'])
How do I display in the template,
Cast #1, Cast #2, Cast #3, Cast #4
How to I grab all of the cast members? Is it?
work.cast.cast.all()
doesn't yield any output.
How do I display it as a list with commas in between?

Answer 1

If I understand you correctly you are sending a context variable to your template called "work_cast" and this variable references one WorkCast instance.
In the django template language do not use the () so grabbing all the Cast members of that one WorkCast instance would be
work_cast.cast.all
You can interate through the instances as described in the docs:
{% for cast in work_cast.cast.all %}
{{ cast }}
{% if not forloop.last %}
,
{% endif %}
{% endfor %}
In the loops the django template language add some extra variable which you can use. In this case we use it to avoid putting a comma after the last entry of your list.