I have a log file that logs connection drops of computers in a LAN. I want to extract name of each computer from every line of the log file and for that I am doing this: (?<=Name:)\w+|(-PC)
The target text:
`[C417] ComputerName:KCUTSHALL-PC UserID:GO kcutshall Station 9900 (locked) LanId: | (11/23 10:54:09 - 11/23 10:54:44) | Average limit (300) exceeded while pinging www.google.com [74.125.224.147] 8x
[C445] ComputerName:FRONTOFFICE UserID:YB Yenae Ball Station 7C LanId: | (11/23 17:02:00) | Client is connected to agent.`
The problem is that some computer names have -PC in them and in some isn't. The expression I have created matches computer without -PC in their names but it if a computer has -PC in the name, it treats that as a separate match and I don't want that. In short, it gives me 3 matches, but I want only 2. That's why I need help here, I am beginner in regex.
You may use
(?<=Name:)\w+(?:-PC)?
Details
(?<=Name:) - a place immediately preceded with Name:
\w+ - 1+ word chars
(?:-PC)? - an optional non-capturing group that matches 1 or 0 occurrences of -PC substring.
Consider using word boundaries if you need to match PC as a whole word,
(?<=Name:)\w+(?:-PC\b)?
See the regex demo.
Related
Hi guys im trying to get the the substring as well as the corresponding number from this string
text = "Milk for human consumption may be taken only from cattle from 80 hours after the last treatment."
I want to select the word milk and the corresponding number 80 from this sentence. This is part of a larger file and i want a generic solution to get the word milk in a line and then the first number that occurs after this word anywhere in that line.
(Milk+)\d
This is what i came up with thinking that i can make a group milk and then check for digits but im stumped how to start a search for numbers anywhere on line and not just immediately after the word milk. Also is there any way to make the search case insensitive?
Edit: im looking to get both the word and the number if possible eg: "milk" "80" and using python
/(?<!\p{L})([Mm]ilk)(?!p{L})\D*(\d+)/
This matches the following strings, with the match and the contents of the two capture groups noted.
"The Milk99" # "Milk99" 1:"Milk" 2:"99"
"The milk99 is white" # "milk99" 1:"milk" 2:"99"
"The 8 milk is 99" # "milk is 99" 1:"milk" 2:"99"
"The 8milk is 45 or 73" # "milk is 45" 1:"milk" 2:"45"
The following strings are not matched.
"The Milk is white"
"The OJ is 99"
"The milkman is 37"
"Buttermilk is 99"
"MILK is 99"
This regular expression could be made self-documenting by writing it in free-spacing mode:
/
(?<!\p{L}) # the following match is not preceded by a Unicode letter
([Mm]ilk) # match 'M' or 'm' followed by 'ilk' in capture group 2
(?!p{L}) # the preceding match is not followed by a Unicode letter
\D* # match zero or more characters other than digits
(\d+) # match one or more digits in capture group 2
/x # free-spacing regex definition mode
\D* could be replaced with .*?, ? making the match non-greedy. If the greedy variant were used (.*), the second capture group for "The 8milk is 45 or 73" would contain "3".
To match "MILK is 99", change ([Mm]ilk) to (?i)(milk).
This seems to work in java (I overlooked that the questioner wanted python or the question was later edited) like you want to:
String example =
"Test 40\n" +
"Test Test milk for human consumption may be taken only from cattle from hours after the last treatment." +
"\nTest Milk for human consumption may be taken only from cattle from 80 hours after the last treatment." +
"\nTest miLk for human consumption may be taken only from cattle from 80 hours after the last treatment.";
Matcher m = Pattern.compile("((?i)(milk).*?(\\d+).*\n?)+").matcher(example);
m.find();
System.out.print(m.group(2) + m.group(3));
Look at how it tests whether the word "milk" appears in a case insensitive manner anywhere before a number in the exact same line and only prints these both. It also prints only the first found occurence (making it find all occurencies is also possible pretty easily just by a little modifications of the given code).
I hope the way it extracts these both things from a matching pattern is in the sense of your task.
You should try this one
(Milk).*?(\d+)
Based on your language, you can also specify a case-insensitive search. Example in JS: /(Milk).*?(\d+)/i, the final i makes the search case insensitive.
Note the *?, the most important part ! This is a lazy iteration. In other words, it reads any char, but as soon as it can stop and process the next instruction successfully then it does. Here, as soon as you can read a digit, you read it. A simple * would have returned the last number from this line after Milk instead
This is data present in my .txt file
+919000009998 SMS +919888888888
+919000009998 MMS +91988 88888 88
+919000009998 MMS abcd google
+919000009998 MMS amazon
I want to convert my .txt like this
919000009998 SMS 919888888888
919000009998 MMS 919888888888
919000009998 MMS abcd google
919000009998 MMS amazon
removing the + symbol, and also the spaces if present in third column only if it is a number, if it is string no operation to be performed
is there any regex to do this which can I write in search and replace in notepad++?
Ctrl+H
Find what: \+|(?<=\d)\h+(?=\d)
Replace with: LEAVE EMPTY
check Wrap around
check Regular expression
Replace all
Explanation:
\+ # + sign
| # OR
(?<=\d) # positive lookbehind, make sure we have a digit before
\h+ # 1 or more horizontal spaces
(?=\d) # positive lookahead, make sure we have a digit after
Screen capture:
All previous answer will perfectly work.
However, I'm just adding this just in case you need it:
If for some reason you had non-phone numbers on the third column separated by spaces (a street comes to mind for me +919000009998 MMS street foo nº 123 4º-B) you may use this regex instead (It will join number as long as the third column starts by +):
Search: ^[+](\S+\s+\S+\s++)(?:([^+][^\n]*)|[+])|\G\s*(\d+)
Replace by: \1\2\3
That will avoid joining the 3 and 4 on my previous example.
You have a demo here.
I have this regex
(\b(\S+\s+){1,10})\1.*MY
and I want to group 1 to capture "The name" from
The name is is The name MY
I get "is" for now.
The name can be any random words of any length.
It need not be at the beginning.
It need on be only 2 or 3 words. It can be less than 10 words.
Only thing sure is that it will be the last set of repeating words.
Examples:
The name is Anthony is is The name is Anthony - "The name is Anthony".
India is my country All Indians are India is my country - "India is my country "
Times of India Alphabet Google is the company Alphabet Google canteen - "Alphabet Google"
You could try:
(\b\w+[\w\s]+\b)(?:.*?\b\1)
As demonstrated here
Explanation -
(\b\w+[\w\s]+\b) is the capture group 1 - which is the text that is repeated - separated by word boundaries.
(?:.*?\b\1) is a non-capturing group which tells the regex system to match the text in group 1, only if it is followed by zero-or-more characters, a word-boundary, and the repeated text.
Regex generally captures thelongest le|tmost match. There are no examples in your question where this would not actualny be the string you want, but that could just mean you have not found good examples to show us.
With that out of the way,
((\S+\s)+)(\S+\s){0,9}\1
would appear to match your requirements as currently stated. The "longest leftmost" behavior could still get in the way if there are e.g. straddling repetitions, like
this that more words this that more words
where in the general case regex alone cannot easily be made to always prefer the last possible match and tolerate arbitrary amounts of text after it.
I want to delete everything except IPs.
For example
1 138.68.161.60:1080 SOCKS5 HIA United States (New York NY) 138.68.161.60 (DigitalOcean, LLC) 0.143 75% (3) - 12-jan-2018 14:37 (10 minutes ago)
2 174.64.234.29:17501 SOCKS5 HIA United States wsip-174-64-234-29.sd.sd.cox.net (Cox Communications Inc.) 0.956
100% (5) - 12-jan-2018 14:36 (10 minutes ago)
3 45.79.219.154:63189 SOCKS5 HIA United States (Atlanta GA) li1318-154.members.linode.com (Linode, LLC) 6.973
90% (103) - 12-jan-2018 14:36 (11 minutes ago)
to
138.68.161.60:1080
174.64.234.29:17501
45.79.219.154:63189
I need a regex to this convert.
In Notepad++, it requires some finesse to delete text not containing matched strings, but you can choose Find, Mark, then check the Regular expression box and use the regex:
([0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}\.[0-9]{1,3}+) and Mark Allto bookmark all rows containing IP adresses.
Then select Find, Replace, enter ^[0-9]\W in Find what:, and Replace All with nothing.
Then select Find, Replace, enter \w+S.+ in Find what:, and Replace All with nothing.
Then, go to Search, Bookmark, Remove Unmarked Lines.
Et Voilà!
You could use this regex in notepad++ and replace the captured values with group 1 \1
(?s)(\d \d+\.\d+\.\d+\.\d+:\d+).*?\(\d+ minutes ago\)
You select all the text for each of the 3 blocks from your example and use a capturing group for the text that you want to keep. Then in the replace you use only the captured group which holds your data.
Explanation
Inline modifier to make the dot match a line break (?s)
Group 1 with the pattern that you want to capture (\d \d+\.\d+\.\d+\.\d+:\d+)
Match any character zero or more times non greedy .*?
The pattern that is at the end of every part \(\d+ minutes ago\)
Using Regex, I'm attempting to get back the following (stars denote what I'd like to extract) from each string using a single Regex command:
FO4H56FD-BTU (Follow Home 56): PLTD8
\***********
FO4H56FD-SYH-BI (Follow Home 56 SYH): PLTD8
\***********
FO4H52FD-SZH-AG4R-BI (Follow Home 52 SAH): QQTD8
\****************
FO4H58FD-SGH: (Follow Home 58 TGT): PLTS8
\***********
For some reason I'm having a lot of difficulties. I've been using various methods and currently have =REGEXEXTRACT(A43,"(FO.+)\-BI") which isn't working. Mine also isn't looking for the : currently. I was using a | for multiple rules which didn't seem to work out.
You may use
=REGEXEXTRACT(A43,"^(.*?)(?:-BI)?(?:[ :]|$)")
Details:
^ - start of string
(.*?) - capturing group #1 matching any 0+ chars as few as possible
(?:-BI)? - an optional non-capturing group matching 1 or 0 occurrences of -BI substring
(?:[ :]|$) - either a space, : or end of string