bash return string between 2 patterns - regex

Question

I have this file: 1.txt
===================================================================
File: .cvsignore Status: Up-to-date
Working revision: 1.1 Thu Jan 16 11:00:00 2020
Repository revision: 1.1 /usr/local/rancid/var/CVS/Routers/.cvsignore,v
Sticky Tag: (none)
Sticky Date: (none)
Sticky Options: (none)
===================================================================
File: router.db Status: Up-to-date
Working revision: 1.6 Fri Jan 17 11:57:39 2020
Repository revision: 1.6 /usr/local/rancid/var/CVS/Routers/router.db,v
Sticky Tag: (none)
Sticky Date: (none)
Sticky Options: (none)
===================================================================
File: .cvsignore Status: Up-to-date
Working revision: 1.1 Thu Jan 16 11:00:00 2020
Repository revision: 1.1 /usr/local/rancid/var/CVS/Routers/configs/.cvsignore,v
Sticky Tag: (none)
Sticky Date: (none)
Sticky Options: (none)
===================================================================
===================================================================
File: 1.1.1.1 Status: Up-to-date
Working revision: 1.2 Fri Jan 17 07:56:21 2020
Repository revision: 1.2 /usr/local/rancid/var/CVS/Routers/configs/1.1.1.1,v
Sticky Tag: (none)
Sticky Date: (none)
Sticky Options: -ko
I want to extract string between File: and Status: (.cvsignore, router.db, 1.1.1.1)
and between Repository revision: and /usr/local/rancid/ (1.1, 1.6, 1.1 )
so final output should be:
.cvsignore 1.1
router.db 1.6
.cvsignore 1.1
1.1.1.1 1.2
for filename i created following filter:
sed 's/^.*File: //; s/Status:.*$//' 1.txt
Output:
===================================================================
.cvsignore
Working revision: 1.1 Thu Jan 16 11:00:00 2020
Repository revision: 1.1 /usr/local/rancid/var/CVS/Routers/.cvsignore,v
Sticky Tag: (none)
Sticky Date: (none)
Sticky Options: (none)
===================================================================
router.db
Working revision: 1.6 Fri Jan 17 11:57:39 2020
Repository revision: 1.6 /usr/local/rancid/var/CVS/Routers/router.db,v
Sticky Tag: (none)
Sticky Date: (none)
Sticky Options: (none)
===================================================================
.cvsignore
Working revision: 1.1 Thu Jan 16 11:00:00 2020
Repository revision: 1.1 /usr/local/rancid/var/CVS/Routers/configs/.cvsignore,v
Sticky Tag: (none)
Sticky Date: (none)
Sticky Options: (none)
===================================================================
1.1.1.1
Working revision: 1.2 Fri Jan 17 07:56:21 2020
Repository revision: 1.2 /usr/local/rancid/var/CVS/Routers/configs/172.18.1.24,v
Sticky Tag: (none)
Sticky Date: (none)
Sticky Options: -ko
===================================================================
For Repository revision i'm trying
sed 's/^.'*Repository revision:' //; s#usr#local#rancid:.*$//' 1.txt
But getting
sed: -e expression #1, char 15: unterminated `s' command
I need one regex for filename and second for Repository revision

Answer 1

Your example isn't clear but is this what you're trying to do?
$ awk 'sub(/^[[:space:]]*(File|Repository revision):[[:space:]]*/,""){print $1}' file
.cvsignore
1.1
router.db
1.6
.cvsignore
1.1
1.1.1.1
1.2
or maybe this:
$ awk 'sub(/^[[:space:]]*(File|Repository revision):[[:space:]]*/,""){printf "%s%s", $1, ((++c)%2 ? OFS : ORS)}' file
.cvsignore 1.1
router.db 1.6
.cvsignore 1.1
1.1.1.1 1.2

Answer 2

$ awk '/^File:/ { printf "%s # filename ", $2}
/Repository revision:/{printf "%s # Repository version\n", $3}' input
.cvsignore # filename 1.1 # Repository version
router.db # filename 1.6 # Repository version
.cvsignore # filename 1.1 # Repository version
1.1.1.1 # filename 1.2 # Repository version

Answer 3

This might work for you (GNU sed):
sed -En '/^File:\s*(\S+).*/{s//\1/;h};/^\s*Repository revision:\s*(\S+).*/{s//\1/;H;g;s/\n/ /p}' file
Store the file name in the hold space and append the revision, then replace the introduced newline by a space and print the result.