I am attempting to pick apart data from the following string utlizing a regex expression:
Ethane, C2 11.7310 3.1530 13.9982 HV, Dry # Base P,T 1432.00
The ultimate goal is to be able to pull out the middle three data points as individual values 11.7310, 3.153, 13.9982
The code expression I am working with at the moment is as follows:
(?<=C2 )(\d*\.?\d+)
This yields a full match of 11.7310 and a Group 1 match of 11.7310, but I can't figure out how to match the other two data points.
I am using PCRE (PHP) to create my expression.
You may use
(?:\G(?!^)|\bC2)\s+\K\d*\.?\d+
See the regex demo.
Details
(?:\G(?!^)|\bC2) - either the end of the previous successful match or C2 whole word
\s+ - 1+ whitespaces
\K - match reset operator discarding all the text matched so far in the match memory buffer
\d* - 0+ digits
\.? - an optional dot
\d+ - 1+ digits.
Related
I have some manually entered data (it's an email subject), and I am trying to extract the correct ID to perform a series of actions with RPA on.
RE:'HC=312-822-281' abc2-1234567 7354612
I have a regex query:
(?<!\d)\d{7}(?!\d)
I want to extract 7354612 but not 1234567.
I want to avoid matching any 7-digit number that is preceded with a hyphen, or a hyphen and a space.
My initial query works 80% of the time, but this hyphen issue is interfering with the other 20%.
You can modify the existing (?<!\d) lookbehind to also exclude the position after a hyphen, i.e. (?<![\d-]), and add another lookbehind to exclude the hyphen + space context ((?<!- ) or (?<!-\s)):
(?<![\d-])(?<!- )\d{7}(?!\d)
(?<![\d-])(?<!-\s)\d{7}(?!\d)
Note \s matches any whitespace. See the regex demo.
Details
(?<![\d-]) - a negative lookbehind that fails the match if there is a digit or a hyphen immediately to the left of the current location
(?<!-\s) - a negative lookbehind that fails the match if there is a - and a space after it immediately to the left of the current location
\d{7} - any seven digits
(?!\d) - a negative lookahead that fails the match if there is a digit immediately to the right of the current location.
Variations
With PCRE regex, you may also use
-\s*\d{7}(?!\d)(*SKIP)(*F)|(?<!\d)\d{7}(?!\d)
See the regex demo, where -\s*\d{7}(?!\d)(*SKIP)(*F)| matches -, 0+ spaces, seven digits after which there are no more digits and skips that match, only returning matches for the (?<!\d)\d{7}(?!\d) pattern.
In .NET, modern JavaScript and PyPi regex in Python, you may use
(?<!\d|-\s*)\d{7}(?!\d)
See this regex demo. Here, (?<!\d|-\s*) negative lookbehind fails the match if there is a digit or - + 0 or more whitespace chars immediately to the left of the current position.
Im currenty having issues with a regex that Im creating. The regex has to extract all the groups that says number #### between Hello and Regards. At this moment my regex only extracts one group and I need all the groups inside, at this case I have 2, but there may be more inside.
Regex Image
I'm using the web page https://regex101.com/
Flavor: PCRE (PHP)
Regex: Hello\s.*(number\s*[\d]*)\s.*Regards
Text:
This is my test text number 25120
Hello my name is testing
I'm 20 years old
Please help me with the regex number 1542
I have been trying to create the regex many times this is my number 5152
Regards
I'm still trying my attempt number 5150
Result:
My Result is only the group number 5152 but inside is another group number 1542.
You may use
(?si)(?:\G(?!\A)|\bHello\b)(?:(?!\bHello\b).)*?\K\bnumber\s*\d+(?=.*?\bRegards\b)
See the regex demo.
Details
(?si) - s - DOTALL modifier making . match any chars, and i makes the pattern case insensitive
(?:\G(?!\A)|\bHello\b) - either the end of the previous match (\G(?!\A)) or (|) a whole word Hello (\bHello\b)
(?:(?!\bHello\b).)*? - any char, 0 or more times but as few as possible, that does not start a whole word Hello char sequence
\K - match reset operator that discards all text matched so far
\bnumber - a whole word number
\s* - 0+ whitespaces
\d+ - 1+ digits
(?=.*?\bRegards\b) - there must be a whole word Regards somewhere after any 0+ chars (as few as possible).
I have a numbers operation like this:
-2-28*95+874-1545*-5+36
I need to extract operands, not implied in a multiplication operation with a regex:
-2
+874
+36
I tried things like that without success:
[\+,-]\d+(?=\+|-|$)
This regex matches -5, too, and
(?(?=\d+)[\+,-]|^)\d+(?=\+|-|$)
matches nothing.
How do I solve this problem?
You may use
(?<!\*)[-+]\d*\.?\d+(?![*\d])
See the regex demo
Details
(?<!\*) - (a negative lookbehind making sure the current position is) not immediately preced with a * char
[-+] - - or +
\d* - 0 or more digits
\.? - an optional . char
\d+ - 1+ digits
(?![*\d]) - not immediately followed with a * or digit char.
See the regex graph:
This RegEx might help you to capture your undesired pattern in one group (), then it would leave your desired output:
(((-|\+|)\d+\*(-|\+|)\d+))
You can also use other language specific functions such as (*SKIP)(*FAIL) or (*SKIP)(*F) and get the desired output:
((((-|\+|)\d+\*(-|\+|)\d+))(*SKIP)(*FAIL)|([s\S]))
You can also DRY your expression, if you wish, and remove unnecessary groups that you may not need.
Another option could be to match what you don't want and capture in a group what you want to keep. Your values are then in the first capturing group:
[+-]?\d+(?:\*[+-]?\d+)+|([+-]?\d+)
Explanation
[+-]?\d+ Optional + or - followed by 1+ digits
(?:\*[+-]?\d+)+ Repeat the previous pattern 1+ times with an * prepended
| Or
([+-]?\d+) Capture in group 1 matching an optional + or - and 1+ digits
Regex demo
I have implemented the following Regex pattern
^[\d,|+\d,]+$
It validates the following pattern
14,+96,4,++67
I need to invalidate ++67 from my pattern and I need to keep values with only a single leading + sign.
How should I change my Regex pattern?
You may use
^\+?\d+(?:,\+?\d+)*$
See the regex demo.
Details
^ - start of string
\+? - an optional + char
\d+ - 1+ digits
(?:,\+?\d+)* - zero or more repetitions of a sequence of patterns:
, - a comma
\+? - an optional plus
\d+ - 1+ digits
$ - end of string
Perhaps you meant to do this?
^(\d,|\+\d,)+$
Square brackets use every character or character class within, which does not appear to be what you really want. For disjunction you need round brackets.
You can try this one
^(\d+\,?|\+\d+,?)+$
In the following string I have to find only 1) and 2):
"Dsfgdsf ghdsgtaq sadf 5hs a sdgewrg1) AF AFDS (1,1-3). sdfwurf sgwefasöpopwe qdasda (2,3-29). jkgwgvsd sdfawefas2)"
With \d\) I find all closing brackets.
With \((.*?)\) I find (1,1-3) and (2,3-29).
How do I manage to combine both patterns?
It seems you need to match 1 or more digits with a ) after them only if preceded with a letter.
You may use
(?<=\p{L})\d+\)
See the regex demo.
Details
(?<=\p{L}) - a positvie lookbehind requiring a letter to be present immediately to the left of the current position
\d+ - 1+ digits
\) - a literal ).