Django - save multiple input parameters to database - django

Question

I'm using the below custom form in my Django app:
forms.py
class UpdateURLForm(forms.ModelForm):
VideoURL = forms.URLField()
MainDescription = forms.CharField(max_length=100)
class Meta:
model = Listing
fields = ('VideoURL', 'MainDescription',)
Then, in views.py I import the form and then I render the fields into my HTML template:
def edit_info(request):
if request.method == 'POST':
form = UpdateURLForm(request.POST)
if form.is_valid():
VideoURL = form.cleaned_data['VideoURL']
MainDescription = form.cleaned_data['MainDescription']
else:
form = UpdateURLForm()
return render(request, 'myapp/updateinfo.html', {'form': form})
HTML:
<form action="#" method='post' class="card shadow-soft border p-4 mb-4">{% csrf_token %}
<div class="form-group">
<label for="video">Video URL:</label>
{{form.VideoURL|add_class:"form-control shadow-soft"}}
</div>
<div class="form-group">
<label for="video">Video URL:</label>
{{form.MainDescription|add_class:"form-control shadow-soft"}}
</div>
<div class="row">
<div class="col">
<button class="btn btn-primary btn-dark mt-2 animate-up-2 text-right"
type="submit">Update</button>
</div>
</div>
</form>
Now, my question is: how can I render the field MainDescription in the template in order to save both information into the database? The way I rendered the second field (MainDescription) doesn't work. Thanks!
Edit
So, I have two fields in my custom form which (VideoURL and MainDescription) which I would like to use to update some info in the DB. When I try to render in the HTML template both are getting the same ID whereas I was expecting that each field of the form to be rendered:
<input type="text" name="VideoURL" value="https://videourl.com" maxlength="100" class="form-control shadow-soft" required="" id="id_VideoURL">
I do not figure out what I am missing.

Answer 1

Every ModelForm has a save() method. This method creates and saves a database object from the data bound to the form. A subclass of ModelForm can accept an existing model instance as the keyword argument instance; if this is supplied, save() will update that instance. If it’s not supplied, save() will create a new instance of the specified model:
EXAMPLE 1 with forms.ModelForm
forms.py
class UpdateURLForm(forms.ModelForm):
class Meta:
model = Listing
fields = ['video_url', 'main_description']
So you can ease save your form.
views.py
def edit_info(request):
if request.method == 'POST':
form = UpdateURLForm(request.POST)
if form.is_valid():
instance = form.save()
else:
form = UpdateURLForm()
return render(request, 'myapp/updateinfo.html', {'form': form})
EXAMPLE 2 with forms.Form
forms.py
class UpdateURLForm(forms.Form):
video_url = forms.URLField(label="Video Url")
main_description = forms.CharField(label="Description", max_length=100)
You can also import your model and create an object.
views.py
from models import Listing
def edit_info(request):
if request.method == 'POST':
form = UpdateURLForm(request.POST)
if form.is_valid():
listing = Listing(video_url=form.cleaned_data.get('video_url'), main_description=form.cleaned_data.get('main_description'))
listing.save()
else:
form = UpdateURLForm()
return render(request, 'myapp/updateinfo.html', {'form': form})