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I have a comma-separated string and wanted to check if the string has all words irrespective of order using REGEX pattern.
Example: Original String = "help, assist, aid";
Use Cases:
"help, assist, aid" -> return true
"aid, assist, help" -> return true
"aid, help,assist" -> return true
"aid, help" -> return false
"aid, help,support" -> return false
Can someone help me in writing the regex pattern for this use case?
You could use three positive lookahead assertions:
^(?=.*\bhelp\b)(?=.*\baid\b)(?=.*\bassist\b).*$
Each of the three lookaheads is actually zero width, and so would all be evaluated once at the very start of the pattern.
Demo
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hreset_error_status_t2_reg1
htrans_flag_t1_reg2
hsize_flag_error_reg
check_hwdata_reg
I had to write a Tcl script using regex I have to remove error_status, flag, flag_error, and check in the following strings. It has to search the following keywords in the file and have to remove the mentioned keywords in a string.
To remove all those patterns from a string, use regsub -all. If you don't need to use the power of regular expressions, then string map works well too.
set my_str "hreset_error_status_t2_reg1 htrans_flag_t1_reg2 hsize_flag_error_reg check_hwdata_reg"
set my_regex {error_status_|flag_(error_)?|check_}
regsub -all $my_regex $my_str ""
--> hreset_t2_reg1 htrans_t1_reg2 hsize_reg hwdata_reg
or
set my_map {
error_status_ ""
flag_error_ ""
flag_ ""
check_ ""
}
string map $my_map $my_str
--> hreset_t2_reg1 htrans_t1_reg2 hsize_reg hwdata_reg
Note that I put flag_error_ before flag_ in $my_map so that only the flag_ characters in flag_error weren't removed.
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I using Regex to extract a pattern which is of the form [a-zA-z][0-9]{8} Ex:K12345678
I need to extract this pattern from a string and this pattern should be matched properly
I tried the below but my testcase if failing for this scenario
This is my Regex /[a-zA-Z][0-9]{8}/g
phonne number:9978434276K12345678:My pattern
For this scenario it is failing.
My Sample Code
const expression = /[a-zA-Z][0-9]{8}/;
const content = "phone number:9978434276K12345678:My pattern"
let patternMatch = content.match(expression);
The expected output is K12345678.The Regex which I wrote does not handle this.
You can use String.match(Regex)
"9978434276K12345678".match(/[a-zA-Z][0-9]{8}/)
It returns an array of 4 elements: [String coincidence, index: Number, input: String, groups: undefined]
just stay with the element 0: coincidence and 1: index of the match.
and use this just to check that the string matches at least one
/Regex/.test(String)
/[a-zA-Z][0-9]{8}/.test("9978434276K12345678")
It will return true or false
USE expression without quotation marks
const expression = /[a-zA-Z][0-9]{8}/;
const content = "phone number:9978434276K12345678:My pattern"
let patternMatch = content.match(expression);
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e.g.
If i have a String like val input = "2+2#=4=test2" should return a List
2+2#=4
test2
order is not important.
You may try splitting using a lookbehind which asserts that what precedes the = sign is not a hash symbol:
val input = "2+2#=4=test2";
val arr = input.split("(?<!#)=".toRegex());
println(arr);
This prints:
[2+2#=4, test2]
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Sample code, see if a value matches any regex from a list:
private val regex: List<Regex> = ...
fun matches(value: String): Boolean {
regex.forEach { re ->
if (re.matches(value))
return true
}
return false
}
It works, but I'm wondering if there is a more elegant way to do this. Note that I don't want to evaluate all of them, but stop whenever there is a match.
fun matches(value: String) = regex.any { it.matches(value) }
any
There are also similar functions:
all,
none
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I have few lines
Eg:
word1-word2-word3-1
word1-word2-word3-23
word1-word2-word3-dr
word1-word2-word3-13-4
word1-word2-word3-drg
word1-word2-word3-word4-4
From the above lines i need the following lines by using Regex
word1-word2-word3-1
word1-word2-word3-23
word1-word2-word3-word4-4
ie. The string ending with a "-{int}"
You can use the pattern -\d+$
The pattern means that we are look for;
-\d+ - hyphen and one or more digits
$ Asserts that we are at the line end.
I don't know what language you are writing this in but assuming you are doing it in Javascript. This pattern can be proved using the code below.
"use strict";
var values = [
"word1-word2-word3-1",
"word1-word2-word3-23",
"word1-word2-word3-dr",
"word1-word2-word3-13-4",
"word1-word2-word3-drg",
"word1-word2-word3-word4-4"
];
values.forEach(value => {
if (/.*-(?!\d+-)\w+-\d+$/.exec(value)) {
console.log(value + " has - integer at the end!");
};
});