Regex to extract static text and number using only regular expression - regex

Question

I am completely new to this regular expression.
But I tried to write the regular expression to get some static text and phone number for the below text
"password":"password123:cityaddress:mailaddress:9233321110:gender:45"
I written like below to extract this : "password":9233321110
(([\"]password[\"][\s]*:{1}[\s]*))(\d{10})?
regex link for demo:
https://regex101.com/r/2vNpMU/2
the correct regexp gives full match as "password":9233321110 in regex tool
I am not using any programming language here, this is for network packet capture at F5 level.
Please help me with the regexp;

Answer 1

I would use /^([^:]+)(?::[^:]+){3}:([^:]+)/ for this.
Explained (more detailed explanation at regex101):
^ matches from the start of the string
(…) is the first capture group. This will collect that initial "password"
[^:]+ matches one or more non-colon characters
(?:…) is a non-capturing group (it collects nothing for later)
:[^:]+ matches a colon and then 1+ non-colons
{3} instructs us to match the previous item (the non-capturing group) 3 times
: matches a literal colon
([^:]+) captures a match of 1+ non-colons, which will get us 9233321110 in this example
The first capture group is typically stored as $1 or the first item of the returned array. (In Javascript, the zeroth item is the full match and item index 1 is the first capture group.) The second capture group is $2, etc.
To always match the "password" key, hard-code it: /^("password")(?::[^:]+){3}:([^:]+)/
Here's a live snippet demonstrating it:
x = `"password":"password123:cityaddress:mailaddress:9233321110:gender:45"`;
match = x.match(/^([^:]+)(?::[^:]+){3}:([^:]+)/);
if (match) console.log(match[1] + ":" + match[2]);
else console.log("no match");