How to get file name for uploading image into s3 bucket? - django

Question

Hello I am facing an issue while adding a file in to s3 bucket....
I am sharing my model
class UserProfile(SoftDeletionModel, BaseModel):
user = models.ForeignKey(User, on_delete=models.CASCADE)
first_name = models.CharField(max_length=100, blank=True)
contact_number = models.CharField(max_length=20, blank=True)
profile_pic=models.TextField(blank=True, null=True)
Here is my serializer class
class UserprofileSerializer(ModelSerializer):
class Meta:
model = UserProfile
exclude = ['deleted_at','created_date','modified_date']
extra_kwargs = {'user': {'required': False}}
Here is my view
class UserProfileUpdateView(UpdateAPIView):
def get_queryset(self, *args, **kwargs):
queryset_list = UserProfile.objects.filter(
user=self.request.user)
return queryset_list
serializer_class = UserprofileSerializer
The issue I am facing is..... THe profile pic uploaded as a image.... But in my model it created as a textfield , for saving the s3 bucket proxy url.....
I need to get the file name for creating a path in s3 bucket ......
So how can I do that ?

Answer 1

You can use request.FILES['profile_pic'] here 'profile_pic' is the input field name where you are uploading.
image = request.FILES['profile_pic']
then you can use image object as Body parameter of S3.
Suppose you have written a function upload_to_s3 which uploads image to S3 using boto3.
Exclude profile_pic from serializer.
Change your code as following:
def upload_to_s3(image_object):
// upload to s3 and get url using boto3
return url
class UserProfileUpdateView(UpdateAPIView):
serializer_class = UserprofileSerializer
def perform_update(self, serializer):
image = request.FILES['profile_pic']
serializer.validated_data['profile_pic'] = upload_to_s3(image)
serializer.save()
Convert profile_pic field type to URLField()