This question already has answers here:
Regex to replace string not in quotes in IntelliJ
(2 answers)
Closed 3 years ago.
Given the following array:
R991,U847,L239,U883,L224,D359,L907,D944,L79,U265,L107
I'd like to add quotation around each individual instance of a letter followed by a number of characters using the 'search and replace' function.
Now in the search function I can target all the instances using the Regex option, and using [A-Z]\d*.
Now for the replace value, how can I use a certain wildcard character to keep the same Regex value intact?
Example:
The end result should be:
"R991","U847","L239","U883","L224","D359","L907","D944","L79","U265","L107"
Note: As a quick fix I searched for each , and replaced that with "," which almost fixed it entirely. But I'm wondering for more complex cases you could use a wildcard.
Search for: ([A-Z]\d+)
Replace by: "$1"
https://www.jetbrains.com/help/webstorm/tutorial-finding-and-replacing-text-using-regular-expressions.html#capture_groups_and_backreference
Related
This question already has answers here:
Regular expression to get a string between two strings in Javascript
(13 answers)
Closed 3 years ago.
Link Regex101
I am using (FD.*?)FD however I am missing every second expression - see regex. Any ideas?
The trailing "FD" in your regex matches the "FD" in the input that starts the next "item" in the input text, so the entire next "item" is skipped, until it finds another "FD".
In a case like this, instead of specify .* followed by the pattern that starts the next item, you typically want to specify anything not including a pattern of FD.
This question already has an answer here:
How to insert the whole matched text in the replacement in Perl?
(1 answer)
Closed 3 years ago.
I am trying to put every last element of each column of a csv into quotation marks by using regex in Visual Studio Code.
I am matching the string using [^,;]+$ and trying to replace it by using "$1".
After replacing, the strings are not in order anymore and some vanish.
Can anybody help me out here?
My csv is shaped like this:
SOME_ID,SOME_ID2,SOME_ID3,NUM,CODE
1234,100,1723,1,403
1235,101,1723,2,486
1236,101,1723,3,5822
To refer to capture you require to put the expression in a capture group (...)
Your regex is correct and simply needs to be put in the capturing group, ([^,]+)$ , should fix your search and replace.
As Wiktor suggested in the comments $& will refer to the whole match and that can also be used.
This question already has answers here:
Regex: match everything but a specific pattern
(6 answers)
Closed 4 years ago.
I am trying to find all strings not ending with the sequence -6X.
What i'm trying to do is compare the value of an xml tag with a sequence.
If it matches then do some stuff.
However I am unable to do so. I want to achieve this without any lookaheads or lookbehinds.
I've tried using .*[^-6X]
However this does not work for strings ending in - or -5 .
I want to ignore strings ending in -6X only and every other pattern should work.
Thanks in advance for your help
This matches Strings NOT ending with -6X:
.*?([^-]..|.[^6].|..[^X])$
https://regex101.com/r/omwkQ3/2
This question already has answers here:
Is it possible to check if two groups are equal?
(2 answers)
Closed 5 years ago.
I'm trying to match iff two capture groups are the same. I could manually check after the match, but I'm wondering if there is a way I can do this in the expression itself.
My expression is (\d+)\/(\d+), so I only want to accept strings where the two numbers are equal. Is there a nice way to check this in the regular expression, or do I have to manually check groups after?
EDIT: This was marked a duplicate but the supposed duplicate question is not related and does not in any way answer my question...
You can use this one in python : \b(\d+)\/+\1\b
Demo
This is the same usecase as checking for doubled words
When editing text, doubled words such as "the the" easily creep in. Using the regex \b(\w+)\s+\1\b in your text editor, you can easily find them. To delete the second word, simply type in \1 as the replacement text and click the Replace button.
Source
I assume you don't have any other capture groups, based on that:
\b(\d+)\/(\1)\b
Regex Demo
This question already has answers here:
Zero-Length regexes and infinite matches?
(2 answers)
Closed 6 years ago.
If you try on http://regexr.com/ the regex \t you get all the single tabs. But if you try \t* you get only on the beginning of the first line. Why?
If you use \t* only, then you trying to match nothing, one or more tabs. Nothing in regexp will match anything, so it won't work.
If you need to find one or more tabs, use \t+ instead.
To make your regexp work on all lines, use global setting. There is an example: http://regexr.com/3db4i