RegEx match with lookaheads - regex

Question

I am been playing with regex and it seems to me. If i can achieve that with regex.
So my test string goes something like this ->
1. \"name\":\"asdsaD\"
2. target(name=adsada, name = asdasd , name=asds dfd ad,cccc=dsaasdas)
My desired result is to achieve that matches \"name\":\"asdsaD\" , name=adsada, name = asdasd and name=asds dfd ad
My solution that i tried -> \\*"{0,1}(?:name)\\*"{0,1}\s{0,}[:=]\s{0,}\\*"{0,1}(.*?)([),]|\\*"{0,1})
https://regex101.com/r/6e58Cb/1
It doesnot match it the way i want it to, tried changing the .*? -> .*
It matches the whole of second line -> name=adsada, name = asdasd , name=asds dfd ad,cccc=dsaasdas)

Answer 1

You could try something like this, a little simpler, and works at least on your given example:
name[\\"\:\s=]+([a-zA-Z0-9\-\_]+)
Basically just finds "name" with an equals, colon, slashes, etc., in front of it, and matches the following word

Answer 2

You could make use of a capturing group with a backreference \1 to what is captured to get consistent maches for the backslash and the double quotes on both sides:
((?:\\")?)name\1\h*[:=]\h*\1[^:=,]+\1
((?:\\")?) Capture group 1, optionally match \"
name\1\ Match name followed by a backrefernce to group 1
h*[:=]\h* Match either : or = between 0+ horizontal whitespace chars
\1[^:=,]+\1 Match 1+ times any char except : = and , between 2 backreferences
Regex demo | Java demo
For example
String regex = "((?:\\\\\")?)name\\1\\h*[:=]\\h*\\1[^:=,]+\\1";
String string = "1. \\\"name\\\":\\\"asdsaD\\\"\n"
+ "2. target(name=adsada, name = asdasd , name=asds dfd ad,cccc=dsaasdas)";
Pattern pattern = Pattern.compile(regex);
Matcher matcher = pattern.matcher(string);
while (matcher.find()) {
System.out.println(matcher.group(0));
}
Output
\"name\":\"asdsaD\"
name=adsada
name = asdasd
name=asds dfd ad