Exit from switch C++ - c++

Question

#include <iostream>
#include <string>
#include <vector>
#include "Player.h"
using namespace std;
void PlayerMenu();
int main() {
int z;
cout << "Please press 0 to see the PLayers Menu. " << endl;
cin >> z;
while (z == 0) {
PlayerMenu();
}
cout << " Now You're Functional Lets get started. ";
};
void PlayerMenu()
{
char ch;
int num;
do {
system("cls");
cout << "\n\n\n\t Player Menu";
cout << "\n\n1 Wallet Balance ";
cout << "\n\n2 Player Invetory";
cout << "\n\n3 To Exit";
cin >> ch;
system("cls");
switch (ch)
{
case '1':
cout << "Your Balance at the moment is ..."<<endl;
cout << "\n";
Bank();
break;
//Show Wallet Balance
case '2':
cout << "Here is your Inventory"<<endl;
cout << "\n";
break;
//Show Inventory
case '3':
cout << " Bye.\n";
break;
//exit i'VE TRIED bREKA BUT it will not go back to the main source code or main method
}
cin.ignore();
cin.get();
} while (ch != '3');//If not 1 or 2 or 3 will ignore it
}
I tried break statements, but the break method will not exit to the main method and run the last following statement. I would like to also run methods inside of the case to case so when a player is selecting 1 it will show the balance of the player. Also when the player inputs a value of 2 it will show a vector of weapons bought.

Answer 1

Use return instead of break to exit from the current function. You then don't need the while (ch != '3'). Instead, you can just use an infinite loop:
while (true) {
// ...
case '3':
cout << " Bye.\n";
return;
}
cin.ignore();
cin.get();
}
You can also use for (;;) instead of while (true), but that's just a stylistic choice.
Also, don't call PlayerMenu() in a loop in main. Just do:
int main()
{
int z;
cout << "Please press 0 to see the PLayers Menu. " << endl;
cin >> z;
if (z == 0) {
PlayerMenu();
}
cout << " Now You're Functional Lets get started. ";
}

Answer 2

break in this context exits the switch. If you wish to exit the function, you will need to return instead.

Answer 3

Your PlayerMenu() function is exiting just fine. The problem is in main():
while (z == 0) {
PlayerMenu();
}
There is nothing in the loop that modifies z, so it never exits. It just keeps going back to the menu forever.
I don't know if you intended to loop there or just test it with an if.