Minimalistic reimplementation of std::cout [closed] - c++

Question

Closed. This question needs to be more focused. It is not currently accepting answers.
Want to improve this question? Update the question so it focuses on one problem only by editing this post.
Closed 3 years ago.
Improve this question
Can you please help me reimplement the most basic functionality of std::cout?
Requirements:
1) C standard headers can be included, but no C++ libraries can be used. For example stdio.h can be used for printf function.
2) It is okay if it only works with one type, let's go with "char*". The objective is to find the briefest implementation.
3) The following line should be working without any modification (namespace should be used):
std::cout << "Hello World!\n";
4) Everything should be within one file including the main() method
Edit:
Here is the code which I have, that results in a compilation error:
#include <stdio.h>
namespace std {
class cout {
public:
void operator << (char* s) {
printf("%s", s);
}
};
}
int main() {
std::cout << "Hello World!\n"; // Compilation error: expected an identifier
}
Thanks

Answer 1

Here is the solution, you were not refering with an operator to the object, but to the class type. You need to create an object of that type to use the << with it.
#include <stdio.h>
//don't ever use std namespace
namespace test {
class base_cout {
public:
void operator << (const char const* s) {
printf("%s",s);
}
};
// This should be extern if you want to use it outside a single file.
base_cout cout;
}
int main() {
test::cout << "Hello World\n";
}
This is what cout in iostream header is:
namespace std { extern ostream __declspec(dllexport) cout; }