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who knows how to calculate the sum using the do/while operator using the formula below?
I would be grateful for any help.
Your formula can be translated like this:
double i = 1;
double sum = 0;
do{
sum += (1/i + 18*i);
i--;
} while (i < 16);
I'm not really sure that using a do while is the best option, it would probably be better with a for loop like so:
double sum = 0;
for (double i = 1; i < 16; ++i){
sum += (1/i + 18*i);
}
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I have around 500 signals with the naming pattern
"Dem_AllEventsStatusByte._101"
"Dem_AllEventsStatusByte._102"
"Dem_AllEventsStatusByte._103"
...
"Dem_AllEventsStatusByte._490"
I want to loop over all of them.
I tried the following code but when i=10 then my signal name is like " Dem_AllEventsStatusByte._1010" which is false it should be 110 at the end.
for (i=1; i<=3;i++)
{
SPrint(signal, "Dem_AllEventsStatusByte._10%d", i);
How to loop over 490 signals of same name pattern? please help! Thank you
You probably want something this:
for (i = 1; i <= 490 - 100; i++)
{
SPrint(signal, "Dem_AllEventsStatusByte._%d", i + 100);
or maybe this:
for (i = 101; i <= 490; i++)
{
SPrint(signal, "Dem_AllEventsStatusByte._%d", i);
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How can i convert boost cpp_int (>1000 bits) to it's binary representation in string (e.g. "1011....11001") ?
I have tried convert it by std::bitset, but it does not work on higher numbers
Edit - solution:
This contains a solution for this question:
Instead of int -> cpp_int
std::string toBinary(boost::multiprecision::cpp_int n)
{
std::string r;
while(n != 0)
{
r = (n % 2 == 0 ? "0":"1") + r;
n /= 2;
}
return r;
}
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Equation Given :
x = (((x+8)/3)%5)*5;
solve the above equation using assignment operators (eg. +=, -=, *=).
Can someone help with this c++ problem?
sorry if this a dumb question
Technically, you can convert a single readable formula
x = (((x + 8) / 3) % 5) * 5;
into four ones:
x += 8;
x /= 3;
x %= 5;
x *= 5;
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Increment a alpha numerical string "abcd1234" upto "abcd2000"
output:
abcd1234
abcd1235
.
.
.
abcd2000
Simply:
for (int a = 1234; a <= 2000; ++a)
{
std::cout << "abcd" << a;
}
In C,
for (int i=1234; i<= 2000;i++)
printf("abcd%d\n",i);
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I have a signal x(t). I must shift it a/2 and -a/2 and then take the sum of these two shifted signals. How can I write shift of x(t) in time in C++?
For time series data a shift in time is just an offset of n samples, so to sum data which is shifted by +/-a/2 samples:
for (i = a/2; i < N - a/2; ++i)
{
y[i] = x[i - a/2] + x[i + a/2];
}