XLS Create New Element If Condition Meet - xslt

Question

I'm receiving this error:
The element type "xsl:if" must be terminated by
the matching end-tag ""
when I'm trying to close and open a new fo:block if a certain condition is meet.
<xsl:if test=".[#pdf_break='true']">
</fo:block><fo:block>
</xsl:if>
How must this be written?
Full example of what I'm trying to do:
<fo:block>
<xsl:for-each select="/article/front/article-meta/contrib-group/contrib[#contrib-type='author']">
<fo:basic-link show-destination="new" external-destination="url({$link})" >
<fo:inline> <xsl:value-of select="name/given-names" /> <xsl:value-of select="name/surname" /> <fo:inline font-size="8pt" vertical-align="super" font-family="HelveticaNeueLTCom-Lt_1" padding-right="8pt" padding-left="-8pt"><xsl:for-each select="xref[#ref-type='aff']"><xsl:value-of select="sup" /><xsl:if test="position()!=last()">,</xsl:if></xsl:for-each></fo:inline></fo:inline>
</fo:basic-link>
<xsl:if test=".[#pdf_break='true']">
</fo:block><fo:block>
</xsl:if>
</xsl:for-each>
so basically it should be:
<fo:block>
Some amount of authors listed with links
</fo:block>
when pdf_break is never true, and then:
<fo:block>
Some amount of authors listed with links
</fo:block>
<fo:block>
More authors listed with links
</fo:block>
when the attribute is true.
Example XML:
<contrib-group>
<contrib equal-contrib="yes" contrib-type='author' pdf_break='false'>
<name>
<surnameExample1</surname>
<given-names>Example1</given-names>
</name>
<xref ref-type='aff' rid='ID1'><sup>1</sup></xref>
</contrib>
<contrib equal-contrib="yes" contrib-type='author' pdf_break='false'>
<name>
<surname>Example2</surname>
<given-names>Example2</given-names>
</name>
<xref ref-type='aff' rid='ID2'><sup>2</sup></xref>
<xref ref-type='aff' rid='ID3'><sup>3</sup></xref>
<xref ref-type='aff' rid='ID4'><sup>4</sup></xref>
<xref ref-type='aff' rid='ID5'><sup>5</sup></xref>
</contrib>
<contrib equal-contrib="yes" contrib-type='author' pdf_break='true'>
<name>
<surname>Example3</surname>
<given-names>Example3</given-names>
</name>
<xref ref-type='aff' rid='ID2'><sup>2</sup></xref>
</contrib>
<contrib contrib-type='author' pdf_break='false'>
<name>
<surname>Example4</surname>
<given-names>Example4</given-names>
</name>
<xref ref-type='aff' rid='ID6'><sup>6</sup></xref>
</contrib>
<contrib contrib-type='author' pdf_break='false'>
<name>
<surname>Example5</surname>
<given-names>Example15</given-names>
</name>
<xref ref-type='aff' rid='ID2'><sup>2</sup></xref>
</contrib>
</contrib-group>

Answer 1

Use:
<xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:template match="/*">
<doc xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:for-each-group select="contrib" group-ending-with="contrib[#pdf_break = 'true']">
<fo:block>
<xsl:for-each select="current-group()">
<author><xsl:sequence select="name/surname, name/given-names"/></author>
</xsl:for-each>
</fo:block>
</xsl:for-each-group>
</doc>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on the provided XML document:
<contrib-group>
<contrib equal-contrib="yes" contrib-type='author' pdf_break='false'>
<name>
<surname>Example1</surname>
<given-names>Example1</given-names>
</name>
<xref ref-type='aff' rid='ID1'><sup>1</sup></xref>
</contrib>
<contrib equal-contrib="yes" contrib-type='author' pdf_break='false'>
<name>
<surname>Example2</surname>
<given-names>Example2</given-names>
</name>
<xref ref-type='aff' rid='ID2'><sup>2</sup></xref>
<xref ref-type='aff' rid='ID3'><sup>3</sup></xref>
<xref ref-type='aff' rid='ID4'><sup>4</sup></xref>
<xref ref-type='aff' rid='ID5'><sup>5</sup></xref>
</contrib>
<contrib equal-contrib="yes" contrib-type='author' pdf_break='true'>
<name>
<surname>Example3</surname>
<given-names>Example3</given-names>
</name>
<xref ref-type='aff' rid='ID2'><sup>2</sup></xref>
</contrib>
<contrib contrib-type='author' pdf_break='false'>
<name>
<surname>Example4</surname>
<given-names>Example4</given-names>
</name>
<xref ref-type='aff' rid='ID6'><sup>6</sup></xref>
</contrib>
<contrib contrib-type='author' pdf_break='false'>
<name>
<surname>Example5</surname>
<given-names>Example15</given-names>
</name>
<xref ref-type='aff' rid='ID2'><sup>2</sup></xref>
</contrib>
</contrib-group>
The wanted -structured output is produced:
<doc xmlns:fo="http://www.w3.org/1999/XSL/Format">
<fo:block>
<author>
<surname>Example1</surname>
<given-names>Example1</given-names>
</author>
<author>
<surname>Example2</surname>
<given-names>Example2</given-names>
</author>
<author>
<surname>Example3</surname>
<given-names>Example3</given-names>
</author>
</fo:block>
<fo:block>
<author>
<surname>Example4</surname>
<given-names>Example4</given-names>
</author>
<author>
<surname>Example5</surname>
<given-names>Example15</given-names>
</author>
</fo:block>
</doc>
XSLT 1.0 solution:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns:fo="http://www.w3.org/1999/XSL/Format">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:key name="kInGroup" match="contrib"
use="generate-id(preceding-sibling::contrib[#pdf_break = 'true'][1])"/>
<xsl:template match=
"contrib[generate-id()
= generate-id(key('kInGroup',
generate-id(preceding-sibling::contrib[#pdf_break='true']
[1]
)
)[1]
)
]">
<fo:block>
<xsl:apply-templates mode="inGroup" select=
"key('kInGroup',
generate-id(preceding-sibling::contrib[#pdf_break = 'true'][1])
)"/>
</fo:block>
</xsl:template>
<xsl:template match="contrib" mode="inGroup">
<author><xsl:copy-of select="name/*"/></author>
</xsl:template>
<xsl:template match="text()"/>
</xsl:stylesheet>
When applied on the same XML document (above), again the correct-structured output is produced:
<fo:block xmlns:fo="http://www.w3.org/1999/XSL/Format">
<author>
<surname>Example1</surname>
<given-names>Example1</given-names>
</author>
<author>
<surname>Example2</surname>
<given-names>Example2</given-names>
</author>
<author>
<surname>Example3</surname>
<given-names>Example3</given-names>
</author>
</fo:block>
<fo:block xmlns:fo="http://www.w3.org/1999/XSL/Format">
<author>
<surname>Example4</surname>
<given-names>Example4</given-names>
</author>
<author>
<surname>Example5</surname>
<given-names>Example15</given-names>
</author>
</fo:block>

Answer 2

I think, if you have access to XSLT 2 or 3, you can use
<xsl:template match="contrib-group">
<xsl:for-each-group select="contrib[#contrib-type = 'author']" group-starting-with="*[#pdf_break = 'true']">
<fo:block>
<xsl:apply-templates select="current-group()"/>
</fo:block>
</xsl:for-each-group>
</xsl:template>
https://xsltfiddle.liberty-development.net/3NSSEv4/1 is a minimal sample, of course you need to add templates for remaining XML input to XSL-FO transformation.