create a monitor class in C++ that terminates gracefully [duplicate] - c++

Question

This question already has answers here:
How do I terminate a thread in C++11?
(7 answers)
How to stop the thread execution in C++
(3 answers)
Proper way to terminate a thread in c++
(1 answer)
Closed 3 years ago.
My main function loads a monitoring class. This class calls external services to periodically get some data and report health status.
These are the task_1 and task_2 in the class below, that can have sub tasks. The tasks accumulate some values that are stored to a shared "Data" class.
So each task_N is coupled with a thread that executes, sleeps for a while and does this forever until the program stops.
My basic problem is that I cannot stop the threads in the Monitor class, since they might be waiting for the timer to expire (sleep)
#include <iostream>
#include <thread>
#include <utility>
#include "Settings.hpp"
#include "Data.hpp"
class Monitors {
public:
Monitors(uint32_t timeout1, uint32_t timeout2, Settings settings, std::shared_ptr<Data> data)
: timeout_1(timeout1), timeout_2(timeout2), settings_(std::move(settings)), data_(std::move(data)) {}
void start() {
thread_1 = std::thread(&Monitors::task_1, this);
thread_2 = std::thread(&Monitors::task_2, this);
started_ = true;
}
void stop() {
started_ = false;
thread_1.join();
thread_2.join();
std::cout << "stopping threads" << std::endl;
}
virtual ~Monitors() {
std::cout << "Monitor stops" << std::endl;
}
private:
void subtask_1_1() {
//std::cout << "subtask_1_1 reads " << settings_.getWeb1() << std::endl;
}
void subtask_1_2() {
//std::cout << "subtask_1_2" << std::endl;
data_->setValue1(21);
}
void task_1() {
while(started_) {
subtask_1_1();
subtask_1_2();
std::this_thread::sleep_for(std::chrono::milliseconds(timeout_1));
std::cout << "task1 done" << std::endl;
}
}
void subtask_2_1() {
//std::cout << "subtask_2_1" << std::endl;
}
void subtask_2_2() {
//std::cout << "subtask_2_2" << std::endl;
}
void task_2() {
while(started_) {
subtask_2_1();
subtask_2_2();
std::this_thread::sleep_for(std::chrono::milliseconds(timeout_2));
std::cout << "task2 done" << std::endl;
}
}
private:
bool started_ {false};
std::thread thread_1;
std::thread thread_2;
uint32_t timeout_1;
uint32_t timeout_2;
Settings settings_;
std::shared_ptr<Data> data_;
};
The main function is here:
auto data = std::make_shared<Data>(10,20);
Settings set("hello", "world");
Monitors mon(1000, 24000,set,data);
mon.start();
int count = 1;
while(true) {
std::this_thread::sleep_for(std::chrono::milliseconds(1000));
std::cout << data->getValue2() << " and count is " << count << std::endl;
count++;
if ( count == 10)
break;
}
std::cout << "now I am here" << std::endl;
mon.stop();
return 0;
Now when I call mon.stop() the main thread stops only when the timer exprires.
How can I gracefully call mon.stop() and interrupt and call the task_N?
UPDATE: Since I don't want to call std::terminate, which is the proper way to implement a monitor class in c++